Answer:
<em>The temperature will be greater than 25°C</em>
Explanation:
In an adiabatic process, heat is not transferred to or from the boundary of the system. The gain or loss of internal heat energy is solely from the work done on the system, or work done by the system. The work done on the system by the environment adds heat to the system, and work done by the system on its environment takes away heat from the system.
mathematically
Change in the internal energy of a system ΔU = ΔQ + ΔW
in an adiabatic process, ΔQ = 0
therefore
ΔU = ΔW
where ΔQ is the change in heat into the system
ΔW is the work done by or done on the system
when work is done on the system, it is conventionally negative, and vice versa.
also W = pΔv
where p is the pressure, and
Δv = change in volume of the system.
In this case,<em> work is done on the gas by compressing it from an initial volume to the new volume of the cylinder. The result is that the temperature of the gas will rise above the initial temperature of 25°C </em>
A robot is a machine. It is often, or almost always, automatic, which means that it is able to perform activities on its own without the aid of external variables, like humans. It moves in the way that it was originally programmed, or designed to act. These actions are described as 'intents' of its own.
Vibrations felt through the floor are due to unbalanced wheels. It would most likely be rear because if it’s the front the steering whee would also vibrate
The work done during the process is 359 btu
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<u>Explanation:</u>
Given-
P1 = 15psia
P2 = 140 psia
V1 = 7ft³
a = 5 psia/ft³
b = C
P = aV +b
Work done, W = ?
P1 = aV1 + b
15 = 5 (7) + b
b = -20 psia
P2 = aV2 + b
140 = 5 ( V2) - 20
V2 = 32 ft³
The work done by the process is the area under the curve which is trapezoidal.
Therefore,
Work done, W = area of trapezoid
= (P2 + P1 / 2) (V2 - V1)
= ( 140 + 15 / 2 ) ( 32 - 7)
= 1937.5 psia ft³
= 1937.5/ 5.4039 = 359 btu
Therefore, the work done during the process is 359 btu
Answer:
concentration of Mg ion = 0.0122 g/L
Explanation:
Given data;
initial concentration of Magnesium in water is 40 mg/l
concentration of 
we have dissociation reaction Magnesium dioxide
from above reaction we can conclude
concentration of 
Mass of magnesium ion is calculated as = Mg mole * molar mass of magnesium
concentration of Mg ion = 0.0005*24.305 g/mol = 0.0122 g/L
