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3 years ago

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A wire is 0.92 m long and 1.2 mm2 in cross-sectional area. It carries a current of 5.0 A when a 2.2 V potential difference is ap

plied between its ends. Calculate the conductivity σ of the material of which this wire is made.

1 answer:

Flura [38]3 years ago

3 0

The solution is in the attachment

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A large plate is at rest in water at 15?C. The plate is suddenly translated parallel to itself, at 1.5 m/s. The resulting fluid

ratelena [41]

Answer:

Answer: (a) = 3.8187m/s, (b) =24.0858m/s (c) = = 3220.071m/s

Explanation:

du/u² = dt = ∫du/2.3183 = ∫dt

0.4313 u = t + c

(a) t = 0, u= 15m/s, c = 0.647

u = t+c/0.4313 = t + 0.647/0.4313

(a) when t= 1 u = 1+ 0.647/0.4313 = 3.8187m/s

(b) when t= 10 u = 10 + 0.647/0.4313 = 24.0858m/s

(c)when t= 1000 u = 1000 + 0.647/0.4313 = 3220.071m/s

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3 years ago

An inventor proposes an engine that operates between the 27 deg C warm surface layer of the ocean and a 10 deg C layer a few met

SpyIntel [72]

Answer:

Engine not possible

Explanation:

source temperature T1 = 300 K

sink temperature T2= 283 K

therefore, carnot efficiency of the heat engine

η= 1- T_2/T_1

$\eta= 1-\frac{T_1}{T_2}$

$\eta= 1-\frac{283}{300}$

= 0.0566

= 5.66%

claims of work produce W = 100 kW, mass flow rate = 20 kg/s

$Q=mc_p(T_1-T_2)$

$Q=20\times4.18(300-283)$

= 1421.2 kW

now $\eta= \frac{W}Q}$

now $\eta= \frac{100}{1421.2}$

=7%

clearly, efficiency is greater than carnot efficiency hence the engine is not possible.

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4 years ago

What is the purpose of a set of curly braces in pseudocode

marysya [2.9K]

Answer:

straight teeth

Explanation:

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3 years ago

Read 2 more answers

A helical compression spring is to be made of oil-tempered wire, d, of diameter 1–mm with a spring index of C = 10. The spring i

BaLLatris [955]

Question

Determine the minimum hole diameter for the spring to operate in

Answer:

11 mm

Explanation:

Mean spring coil diameter is given from the following relationship

D=cd where C is spring index and d is the diameter of oil-tempered wire

By substitution

D=10*1 mm=10 mm

To find the outer diameter, we add the d to D hence getting the minimum hole diameter as

$D_o= D+d= 10 mm+1 mm= 11 mm$

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3 years ago

Water flows through a multisection pipe placed horizontally on the ground. The velocity is 3.0 m/s at the entrance and 2.1 m/s a

Alex_Xolod [135]

Answer:

b. 2.3 kPa.

Explanation:

This situation can be modelled by Bernoulli's Principle, as there are no energy interaction throughout the multisection pipe and current lines exists between both ends. Likewise, this system have no significant change in gravitational potential energy since it is placed horizontally on the ground and is described by the following model:

$P_{1} + \rho \cdot \frac{v_{1}^{2}}{2} = P_{2} + \rho \cdot \frac{v_{2}^{2}}{2}$

Where:

$P_{1}$ , $P_{2}$ - Pressures at the beginning and at the end of the current line, measured in kilopascals.

$\rho$ - Water density, measured in kilograms per cubic meter.

$v_{1}$ , $v_{2}$ - Fluid velocity at the beginning and at the end of the current line, measured in meters per second.

Now, the pressure difference between these two points is:

$P_{1} - P_{2} = \rho \cdot \frac{v_{2}^{2}-v_{1}^{2}}{2}$

If $\rho = 1000\,\frac{kg}{m^{3}}$ , $v_{1} = 3\,\frac{m}{s}$ and $v_{2} = 2.1\,\frac{m}{s}$ , then:

$P_{1} - P_{2} = \left(1000\,\frac{kg}{m^{3}} \right)\cdot \frac{\left(2.1\,\frac{m}{s} \right)^{2}-\left(3\,\frac{m}{s} \right)^{2}}{2}$

$P_{1} - P_{2} = -2295\,Pa$

$P_{1} - P_{2} = -2.295\,kPa$ (1 kPa is equivalent to 1000 Pa)

Hence, the right answer is B.

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3 years ago