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2 years ago

6

A wire is 0.92 m long and 1.2 mm2 in cross-sectional area. It carries a current of 5.0 A when a 2.2 V potential difference is ap

plied between its ends. Calculate the conductivity σ of the material of which this wire is made.

1 answer:

Flura [38]2 years ago

3 0

The solution is in the attachment

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Water flows through two smooth pipes with the same diameter and length as shown below. ipe is twice that through the first-pipe.

Alisiya [41]

Answer:

The right answer is (d)

Explanation:

The pressure drop in smooth pipes with laminar flow is determined by the resistance of the fluid to flow, which is controlled by Reynolds's number. At higher Re, higher drop. But in this case, we have no information about the speed of the fluid in each pipe, and the ipe is not related to that speed. therefore we don´t have the information to say that any of the other options are the right ones

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2 years ago

When storing used oil, it need to be kept in________ container?

lisov135 [29]

Answer: In a clean plastic or metal container with a tightly sealed lid

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3 years ago

Steam undergoes an isentropic compression in an insulated piston–cylinder assembly from an initial state where T1 5 1208C, p1 5

balu736 [363]

Answer:

temperature T2 = 826.9°C

$\frac{W}{m}$ = -1142.7 kJ/kg

Explanation:

given data

initial state temperature = 120°C

final state pressure p1 = 1 bar

pressure p2 = 100 bar

solution

we use here super heated water table A6 that is

specific internal energy u1 = 2537.3 kJ/kg

specific entropy s1 = 7.4668 kJ/kg.K

and

here specific entropy stage 1 = stage 2

so for specific entropy and pressure 100 bar

specific internal energy u2 = 3680 kJ/kg

and temperature T2 = 826.9°C

so here now we get specific work of steam is

ΔU = -W ...........1

m ( u1 - u2) = W

$\frac{W}{m}$ = u1 - u2

$\frac{W}{m}$ = 2537.3 - 3680

$\frac{W}{m}$ = -1142.7 kJ/kg

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3 years ago

A horizontal 2-m-diameter conduit is half filled with a liquid (SG=1.6 ) and is capped at both ends with plane vertical surfaces

luda_lava [24]

Answer:

Resultant force = 639 kN and it acts at 0.99m from the bottom of the conduit

Explanation:

The pressure is given as 200 KPa and the specific gravity of the liquid is 1.6.

The resultant force acting on the vertical plate, Ft, is equivalent to the sum of the resultant force as a result of pressurized air and resultant force due to oil, which will be taken as F1 and F2 respectively.

Therefore,

Ft = F1 + F2

According to Pascal's law which states that a change in pressure at any point in a confined incompressible fluid is transmitted throughout the fluid such that the same change occurs everywhere, the air pressure will act on the whole cap surface.

To get F1,

F1 = p x A

= p x (πr²)

Substituting values,

F1 = 200 x π x 1²

F1 = 628.32 kN

This resultant force acts at the center of the plate.

To get F2,

F2 = Π x hc x A

F2 = Π x (4r/3π) x (πr²/2)

Π - weight density of oil,

A - area on which oil pressure is acting,

hc - the distance between the axis of the conduit and the centroid of the semicircular area

Π = Specific gravity x 9.81 x 1000

Therefore

F2 = 1.6 x 9.81 x 1000 x (4(1)/3π) x (π(1)²/2)

F2 = 10.464 kN

Ft = F1 + F2

Ft = 628.32 + 10.464

Ft = 638.784 kN

The resultant force on the surface is 639 kN

Taking moments of the forces F1 and F2 about the centre,

Mo = Ft x y

Ft x y = (F1 x r) + F2(1 - 4r/3π)

Making y the subject,

y = (628.32 + 10.464(1 - 4/3π)/ 638.784

y = 0.993m

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3 years ago

The penalty for littering 15 lb or less is _____.<br> A. $25<br> B. $50<br> C. $100<br> D. $150

Marina CMI [18]

Answer:

D the closest

Explanation:

i looked it up and 8t says 200

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3 years ago