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kotegsom [21]
3 years ago
6

A student did an experiment to determine the specific heat capacity of a metal alloy. The student put a sample of the alloy in b

oiling water for several minutes, then quickly transferred the alloy into a calorimeter containing water originally at 25°C. The temperature of the water was monitored over time. The data are given in the graph above.
(a) What is the value of ΔT that the student should use to calculate the value of q, the heat gained by the water?

(b) In terms of what occurs at the particulate level, explain how the temperature of the water increases after the alloy sample is added.

(c) The student claims that thermal equilibrium is reached at time t. Justify the student’s claim. In your justification, include a description of what occurs at the particulate level when the alloy and the water have reached thermal equilibrium.

Chemistry
1 answer:
guapka [62]3 years ago
7 0

Answer:

a) ∆T=T1-T2

b) At the particle level the temperature changes are the result of the added energy causing the particles of water to move more vigorously. Either the particles of solid vibrate more vigorously about their fixed positions or the particles of liquid and gas move about their container more rapidly.

c) The state in which two substances in physical contact do not share any heat energy. The temperature of two substances in thermal equilibrium is said to be the same. Also see thermodynamics.

Explanation:

hope that helped good luck!

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WILL GIVE BRAINLIEST
dedylja [7]

Answer:

In order to be able to solve this problem, you will need to know the value of water's specific heat, which is listed as

c=4.18Jg∘C

Now, let's assume that you don't know the equation that allows you to plug in your values and find how much heat would be needed to heat that much water by that many degrees Celsius.

Take a look at the specific heat of water. As you know, a substance's specific heat tells you how much heat is needed in order to increase the temperature of 1 g of that substance by 1∘C.

In water's case, you need to provide 4.18 J of heat per gram of water to increase its temperature by 1∘C.

What if you wanted to increase the temperature of 1 g of water by 2∘C ?

This will account for increasing the temperature of the first gram of the sample by n∘C, of the the second gramby n∘C, of the third gram by n∘C, and so on until you reach m grams of water.

And there you have it. The equation that describes all this will thus be

q=m⋅c⋅ΔT , where

q - heat absorbed

m - the mass of the sample

c - the specific heat of the substance

ΔT - the change in temperature, defined as final temperature minus initial temperature

In your case, you will have

q=100.0g⋅4.18Jg∘C⋅(50.0−25.0)∘C

q=10,450 J

4 0
3 years ago
When water reaches its boiling point and turns into water vapor what happens to its molecular structure
Alex787 [66]
When water reaches its boiling point and turns into water vapor, the molecular structure of water remains the same. It is only the state of the substance that is changed in this process. I hope this helps you 
8 0
4 years ago
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Answer:

1.26 mole

Explanation:

Using ideal gas law

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n= 1.26 mole

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Answer: C

Explanation:

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Answer:

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Explanation:

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