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dolphi86 [110]
3 years ago
5

Match the action to the effect on the equilibrium position for the reaction N2(g) + 3H2(g) ⇌ 2NH3(g). Match Term Definition Remo

ving ammonia A) No effect Removing hydrogen gas B) Shift to the right Adding a catalyst C) Shift to the left
Chemistry
1 answer:
pshichka [43]3 years ago
7 0

Answer:

The answers to the questions are given below.

Explanation:

According to Le Chatelier's principle, if an external constrain such as change in concentration, temperature or pressure is imposed on a chemical system in equilibrium, the equilibrium will shift in order to neutralize the effect.

A. Effective of removing ammonia, NH3.

N2(g) + 3H2(g) ⇌ 2NH3(g)

Removing NH3 from the reaction simply means we are left with more reactants and no product. Therefore, the reactant will react to produce the product. Hence, the equilibrium position will shift to the right.

2. Effect of removing H2

N2(g) + 3H2(g) ⇌ 2NH3(g)

Remoing H2 simply means we have more products and less reactant. Therefore, the product will be convert to reactant. Hence, the equilibrium position will shift to the left.

C. Effect of adding a catalyst.

N2(g) + 3H2(g) ⇌ 2NH3(g)

Catalyst does not affect the equilibrium position. It only creates an alternative path to arrive at the product within a short time. Hence, it has no effect.

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Give the volume indicated. Be sure to include all significant figures.
miskamm [114]

Answer: -

71

Explanation: -

From the diagram, we see that volume goes from 70 to 75 in 5 markings.

Each marking is for 1.

It is the most accuracy possible as there is no smaller marking.

Significant figures expresses the required amount of accuracy.

Thus the volume indicated from the diagram is 71 .

8 0
3 years ago
Read 2 more answers
HELP NOW Do Now 3.5 Purple
Serga [27]

Answer:

The smell of a chocolate is from the presence of volatile compounds present in the chocolate bar which at room temperature readily changes phase from solid to liquid to vapor or gas

Explanation:

There are nearly 600 identified compounds present in a chocolate bar and out of these, there are volatile components which gives the chocolate bar its distinctive aroma.

These volatile chocolate contents readily change phase from solid to vapor, with very short duration liquid phase.

For example, 3 methylbutanal, vanillin, and several organic compounds which are known to be readily volatile.

4 0
2 years ago
Ethanedioic acid, a compound that is present in many vegetables, has a molar mass of 90.04 g/mol and a composition of 26.7% Carb
aleksandrvk [35]

Answer:

Empirical CHO2

Molecular C2H2O4

Explanation:

To determine the formulas, firstly, we need to divide the percentage compositions by the atomic masses.

Kindly note that the atomic mass of carbon, oxygen and hydrogen are 12, 16 and 1 respectively. We proceed with the division as follows:

C = 26.7/12 = 2.225

H = 2.2/1 = 2.2

O = 71.1/16 = 4.44375

We then proceed to divide by the smallest value which is 2.2 in this case

C = 2.25/2.2 = 1

H = 2.2/2.2 = 1

O = 4.44375/2.2 = 2

Thus, the empirical formula is CHO2

We now proceed to get the molecular formula as follows

[12+ 1 + 16(2) ]n = 90.04

45n = 90.04

n = 90.04/45 = 2

The molecular formula is :

C2H2O4

4 0
3 years ago
What is the Chemical Formula and Net Ionic Equations for all three solutions.
AlladinOne [14]

Answer:

See answer below

Explanation:

As you are asking for chemical formula and ionic equation, then, I will assume that after the station #3 below, are the solutions you are requiring.

You are also not specifing if you want for example, result of solution 1 + solution 3. If you need that, please post that on another question.

Now for the chemical formula, you need to identify the elements in all 3 solutions, and also the type of compound.

<u>1. Solution 2 Potassium Iodide: </u>

In this case we have Potassium on one side, and Iodine on the other side, the symbol for those are K and l. As Potassium have the +1 oxidation state, cause is the only one that it can have, when it's next to an halide like chlorine or bromine, it will form a binary salt. The halides, usually work with the lowest oxydation state. In the case of Iodide it will be -1, so, the formula will be:

KI

And the net ionic equation will be the chemical equation that shows how the charges and atoms are balanced. In this case it would be:  

K⁺ + I⁻ ------> KI

<u>2. Solution 1 and 3, Lead (II) nitrate and Sodium carbonate: </u>

In this case I will work with both, because both of the solution are tertiary compounds. In this cases, we have two tertiary salt, The Sodium symbol is Na, and is working with it oxydation state +1. Carbonate is an anion and have the formula CO₃ working with the oxydation state -2. Lead can work with oxidation state +2 and +4. It's symbol is Pb. Nitrate is NO₃ and works with oxydation state -1 instead.

The chemical formula and ionic equation for both will be:

Lead(II) nitrate: Pb(NO₃)₂

Sodium Carbonate: Na₂CO₃

And the net equations:

Lead nitrate: Pb²⁺ + 2NO₃⁻ ------> Pb(NO₃)₂

Copper sulfate: 2Na⁺ + CO₃²⁻ -------> Na₂CO₃

Hope this helps

6 0
3 years ago
In the molecule represented by the chemical formula H2SO4, there would be...Select one:a. 1 hydrogen atom.b. 2 hydrogen atoms.c.
REY [17]
<h2>Answer:</h2>

2 hydrogen atoms.

<h2>Explanations:</h2>

Given the chemical formula H2SO4,

The compound shows that the formula has 4 atoms of oxygen, one atom of sulfur and 2 hydrogen atoms.

Therefore, the number of hydrogen atom in the molecule H2SO4 is 2 hydrogen atoms.

3 0
1 year ago
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