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Maru [420]
3 years ago
13

"Force is applied to an object and the object is moved over a distance in the same direction of the applied force" is the defini

tion of
balanced force.
gravitational force.
power.
work.
Physics
2 answers:
DaniilM [7]3 years ago
8 0
I believe this is gravitational force

Sonja [21]3 years ago
4 0
Hi there!!

The correct answer to your question is B. Gravitational force because the force is applied to one object as it is applied to the same direction.


Hope this helped love! Brainliest?
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A table tennis ball has a mass of about 2.45 g. Suppose the ball is hit across the table with a speed of 4.0 m/s. What is it’s k
cluponka [151]

Answer:

0.0196 j

Explanation:

i) The formula for kinetic energy is as follows: 0.5*m*v^2

ii) Since we have all the values all that's left is to plug them into the equation

iii) First, WE MUST, Convert grams into kgs as this is the SI unit of mass so 2.45/1000

iv) All that's left now is to plug it into the equation so:

0.5* (s.45/1000)*(4^2)

v) Lastly we add the unit joules at the end as we're talking about energy

Hope this was useful! :)

3 0
2 years ago
Compare the earths climate today with its climate during an ice age.
tresset_1 [31]
It’s a lot warmer now
Than it is during an ice age
5 0
3 years ago
In unit-vector notation, what is the torque about the origin on a particle located at coordinates (0 m, −3.0 m, 2.0 m) due to fo
irinina [24]

Answer:

The torque about the origin is 2.0Nm\hat{i}-8.0Nm\hat{j}-12.0Nm\hat{k}

Explanation:

Torque \overrightarrow{\tau} is the cross  product between force \overrightarrow{F} and vector position \overrightarrow{r} respect a fixed point (in our case the origin):

\overrightarrow{\tau}=\overrightarrow{r}\times\overrightarrow{F}

There are multiple ways to calculate a cross product but we're going to use most common method, finding the determinant of the matrix:

\overrightarrow{r}\times\overrightarrow{F} =-\left[\begin{array}{ccc} \hat{i} & \hat{j} & \hat{k}\\ F1_{x} & F1_{y} & F1_{z}\\ r_{x} & r_{y} & r_{z}\end{array}\right]

\overrightarrow{r}\times\overrightarrow{F} =-((F1_{y}r_{z}-F1_{z}r_{y})\hat{i}-(F1_{x}r_{z}-F1_{z}r_{x})\hat{j}+(F1_{x}r_{y}-F1_{y}r_{x})\hat{k})

\overrightarrow{r}\times\overrightarrow{F} =-((0(2.0m)-0(-3.0m))\hat{i}-((4.0N)(2.0m)-(0)(0))\hat{j}+((4.0N)(-3.0m)-0(0))\hat{k})

\overrightarrow{r}\times\overrightarrow{F}=-2.0Nm\hat{i}+8.0Nm\hat{j}+12.0Nm\hat{k}=\overrightarrow{\tau}

4 0
3 years ago
Under which set of circumstances will the pressure of a gas DEFINITELY increase?
malfutka [58]
Temperature increase, smaller container, or influx of more gas
5 0
3 years ago
(d) Suppose you use a spring to launch a payload horizontally from the asteroid so that the payload ends up far from the asteroi
nydimaria [60]

Answer:

ks= 133.2 N/m

Explanation:

  • Assuming that we can neglect the gravitational potential energy of the mass, and that no other forces acting on the payload, total mechanical energy must be conserved.
  • This energy, at any time, is part elastic potential energy (stored in the spring) and part kinetic energy.
  • When the spring is initially compressed, the payload is at rest, so all energy is elastic potential.
  • Once the spring has returned to its natural state, all this elastic potential energy must have been turned into kinetic energy.
  • If the payload is launched horizontally, and no gravity is present,this means that its final speed will be horizontal only also, according to Newton's First Law.
  • So, we can write the following equation:

       \Delta U + \Delta K = 0 (1)

  • where ΔU = -1/2*k*(Δx)²  (2)
  • and ΔK = 1/2*m*v² (3)
  • Replacing in (2) and (3) by the givens, and simplifying, we can find the stiffness ks as follows:

       k_{s} =\frac{m*v^{2}}{\Delta x^{2}} = \frac{29 kg*(3m/s)^{2}}{(1.4m)^{2}} = 133.2 N/M (4)

5 0
2 years ago
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