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Maru [420]
3 years ago
13

"Force is applied to an object and the object is moved over a distance in the same direction of the applied force" is the defini

tion of
balanced force.
gravitational force.
power.
work.
Physics
2 answers:
DaniilM [7]3 years ago
8 0
I believe this is gravitational force

Sonja [21]3 years ago
4 0
Hi there!!

The correct answer to your question is B. Gravitational force because the force is applied to one object as it is applied to the same direction.


Hope this helped love! Brainliest?
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A rectangular coil with 50 turns of conducting wire and a total resistance of 10.0 Ω initially lies in the yz-plane at time t =
castortr0y [4]

Answer:

a) 43.20V

b) 2.71W/s

c) 40.25s

d) 7.77Nm

Explanation:

(a) The emf of a rotating coil with N turns is given by:

emf=NBA\omega sin(\omega t)

N: turns

B: magnitude of the magnetic field

A: area

w: angular velocity

the emf max is given by:

emf_{max}=NBA\omega=(50)(1.80T)(0.200m*0.100m)(24.0rad/s)\\\\emf_{max}=43.20V

(b) the maximum rate of change of the magnetic flux is given by:

\frac{d\Phi_B}{dt}=\frac{d(A\cdot B)}{dt}=\frac{d}{dt}(ABcos\omega t)=AB\omega sin(\omega t)\\\\\frac{d\Phi_B}{dt}_{max}=(\pi(0.200*0.100))(1.80T)(24.0rad/s)=2.71\frac{W}{s}

(c) emf(t=0.050s)=(50)(1.80T)(0.200m*0.100m)(24rad/s)sin(24.0rad/s(0.050s))\\\\emf(t=0.050s)=40.26V

(d) The torque is given by:

\tau=NABIsin\theta\\\\NAB\omega=emf_{max}\\\\\tau=\frac{emf_{max}}{\omega}\frac{emf_{max}}{R}\\\\\tau=\frac{(43.20V)^2}{(24.0rad/s)(10.0\Omega)}=7.77Nm

3 0
3 years ago
A car has a mass of 1.20 x 10^3 kilograms and a momentum of 2.00 x 10^4 kilogram meters/second. What is the velocity of the car?
lorasvet [3.4K]
The answer will be v=16.7m/s
I hope this helps you, have a great day!
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3 years ago
The space between molecules is called what? Need this for a test
alexdok [17]

Answer:

voids

Explanation:

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3 years ago
Your car is stalled in the middle of a large patch of ice (assumed to be frictionless). You have a friend that has thrown a rope
Gnoma [55]

Answer:

The time depends on the distance that they have to travel

x(t) = \frac{0.3846t^{2} }{2}

Explanation:

The only horizontal force exerts over the car and you, it is the force that your friend is applied

Newton's Second Law of Motion defines the relationship between acceleration, force, and mass, thus

\sum{F} = ma

        550 = 1430a

            a = 0.3846 m/s2

             

The car and you have a motion under constant acceleration, then theirs position to a time-based is:

x(t) = x_{0} + v_{0}t +\frac{at^{2} }{2}

By the initial conditions

x(t) = \frac{at^{2} }{2}

x(t) = \frac{0.3846t^{2} }{2}

The time depends on the distance that they have to travel  

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What is the scariest thing to established U.S. utilities?
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<span>They are still structured as monopolies that bundle together disparate energy </span>
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