His displacement is 0 .hope this helps :)
The period of the pendulum is given by the following equation
T = 2<span>π * sqrt (L/g)
Where g is the gravity (free fall acceleration)
L is the longitude of the pendulum
T is the period.
We find g.............> (T /2</span>π)<span>^</span><span>2 = L/g
g = L/(</span>T /2π)^2...........> g = 22.657 m/s^2
The second statement is the correct choice. Don't make me type it out.
S orbital.
Group 1 elements have a general configuration
, where n represents the highest occupied Principal Energy Level. For example, Lithium has the valence configuration
whereas Cesium has
. Both of them belong to Group 1 of Periodic Table.
Group 2 elements have a general configuration of
. For example, Magnesium has
as its outer shell configuration while Strontium has the same as
.
We see that in both the cases, the outermost S orbital is being filled.
Answer:
6.75m/s
Explanation:
using the second equation of motion, the time is calculated.
and with the formula a= (v - u)/t
where a is acceleration but in this case it's deceleration (and should be negated as you solve it ) .
v is final velocity
u is initial velocity
t is time taken