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3 years ago

12

Will mark brainliest

1 answer:

Varvara68 [4.7K]3 years ago

3 0

Answer: I don’t think u gave enough info

Step-by-step explanation:

You might be interested in

Given that y = } 1/2(x1 + x2)c, what is y when X 1 = 3, X2 = 5, and c = 6?

vampirchik [111]

Answer:

24

Step-by-step explanation:

1/2(x1+x2)c x1=3 , x2=5 , c=6

:- 1/2(3+5)6 ( BODMAS)

:- 1/2(8)6 divide 8 by 1/2

:- (4)6 multiply both of them and the result = 24

7 0

3 years ago

⚠URGENT!!!⚠ <br><br> solve for m.

Zinaida [17]

Answer:

Step-by-step explanation:

Remark

Read the following carefully.

There is a beautiful theorem that has to do with the endpoints of two angles sharing the same endpoints.

To be a little clearer, I hope, that makes < BAC = <BDC because both angles have B and C as their endpoints inside the circle. Make sure you understand that statement before moving on.

For this problem <BDC = <CAB = 33 degrees.

That means that ADC = 37 + 33 = 70

Solution

<ADC and CBA are opposite angles.

That means that they add to 180

From the above statement in the Remark section <ADC = 37 + 33 = 70 degrees <ABD + <DBC = <ABC = m + 71

<ABC + ADC = 180

m + 71 + 70 = 180 Combine

m + 141 = 180 Subtract 141 from both sides.

m+141-141= 180 - 141 Combine

m = 39

Answer: m = 39

3 0

2 years ago

Can you answer these please many thanks

givi [52]

Given: (a) $2(x+3)=2x+6$ and (b) $4(y-3)=4y-12$ .

To find: The expanded form of the given expressions.

(c) $4(m+n)=4m+4n$ (using $a(b+c)=ab+ac$ )

(d) $3(5-q)=15-3q$ (using $a(b-c)=ab-ac$ )

(e) $5(2c+1)=10c+5$ (using $a(b+c)=ab+ac$ )

(f) $3(2x-5)=6x-15$ (using $a(b-c)=ab-ac$ )

(g) $7(4b-1)=28b-7$ (using $a(b-c)=ab-ac$ )

(h) $3(2x+y-5)=3((2x+y)-5)$

⇒ $3(2x+y-5)=3(2x+y)-15$ (using $a(b-c)=ab-ac$ )

⇒ $3(2x+y-5)=6x+3y-15$ (using $a(b+c)=ab+ac$ )

(i) $2(6a-4b+3)=2((6a-4b)+3)$

⇒ $2(6a-4b+3)=2(6a-4b)+6$ (using $a(b+c)=ab+ac$ )

⇒ $2(6a-4b+3)=12a-8b+6$ (using $a(b-c)=ab-ac$ )

(j) $6(m+n+p)=6((m+n)+p)$

⇒ $6(m+n+p)=6(m+n)+6p$ (using $a(b+c)=ab+ac$ )

⇒ $6(m+n+p)=6m+6n+6p$ (using $a(b+c)=ab+ac$ )

(k) $y(y+2)=y^2+2y$ (using $a(b+c)=ab+ac$ )

(l) $g(g-3)=g^2-3g$ (using $a(b-c)=ab-ac$ )

(m) $n(4-n)=4n-n^2$ (using $a(b-c)=ab-ac$ )

(n) $a(b+c)=ab+ac$ (using $a(b+c)=ab+ac$ )

(o) $s(3s-4)=3s^2-4s$ (using $a(b-c)=ab-ac$ )

(p) $2x(x+5)=2x^2+10x$ (using $a(b+c)=ab+ac$ )

(q) $4y(x-3)=4xy-12y$ (using $a(b-c)=ab-ac$ )

(r) $5a(2b-5)=10ab-25a$ (using $a(b-c)=ab-ac$ )

(s) $4a(3b+2c)=12ab+8ac$ (using $a(b+c)=ab+ac$ )

(t) $5p(4p-5q)=20p^2-25pq$ (using $a(b-c)=ab-ac$ )

6 0

3 years ago

6.50 is 25$ of what number?

Ivenika [448]

Answer:

3.85

Step-by-step explanation:

6.50 goes into 25 how many times

6.50×?=25

6.50 divided by 25 = 3.846153846

Simplify

3.85

8 0

3 years ago

Plz help! I will mark you brainliest!

s2008m [1.1K]

Answer:

A. 80

Step-by-step explanation:

No math necessary. You know the brace needs to be longer than the distance between posts, so cannot be 4, 15, or 42 inches. The only answer choice longer than 64 inches is the correct one:

80 inches

4 0

3 years ago