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Alja [10]
3 years ago
9

Um comentarista de futebol certa vez comentou:"A bola bateu na trave e voltou duas vezes mais forte". Sabendo que quando a bola

atinge a trave ela acerta com uma força chamada de ação e a outra trave acerta com outra força chamada de reação explique porque a frase documentalista soa errada.
Physics
1 answer:
ryzh [129]3 years ago
7 0

Answer:

Por ela ter batido na trave, não tem como voltar 2x mais forte, por que toda ação correspondente a uma reação de igual intensidade, mas que atua no sentido oposto

Explanation:

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4. List 3 detailed examples of Newton's 3rd Law.
slamgirl [31]

Answer:  If one billiard ball hits another, the second will move with the same force as the first.

A child wants to jump to climb a tree (reaction), he must push the ground to propel himself (action).

A man deflates a balloon; the force with which the air comes out causes the balloon to move from one side to the other.

Explanation:

7 0
3 years ago
Read 2 more answers
I don't understand how to find the frequency and period of wavelengths. Can anyone help me?
nordsb [41]

Frequency of a wave =

                 (speed of the wave) divided by (wavelength)
or
                 (1) divided by (period of the wave) .


Period of the wave =

                   (wavelength) divided by (speed of the wave)
or
                   (1) divided by (frequency of the wave) .
3 0
3 years ago
A
Arlecino [84]

i think the data is not complete but that's according to me

7 0
3 years ago
What is a substance?
Alika [10]

Answer:

A single component that can’t be separated

brainliest please ;)

5 0
3 years ago
Assume we’re able to travel to your planet and decide to take some fireworks with us to celebrate our journey.
julia-pushkina [17]

Answer:

The horizontal distance covered by the firework will be \frac{1876.8}{g}

Explanation:

Let acceleration due to gravity on the planet be g, initial velocity of the firework be u and angle made with the horizontal be ∅.

writing equation of motion in vertical direction:

v_{y}=u_{y}+(-g) t

u_{y}= u\sin \phi

and v_{y}=0

therefore \frac{u\sin \phi }{g} =t

writing equation of motion in horizontal direction:

s_{x}=u_{x}t

u_{x} = u\cos \phi

therefore the equation becomes s_{x}=\frac{u^{2}   \sin \phi  \cos \phi}{g}

therefore horizontal distance traveled =\frac{u^{2}\sin 2\alpha \phi }{2g}=\frac{1876.8}{g}\frac{m}{s}

5 0
3 years ago
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