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Semmy [17]
3 years ago
13

If we double the resistance in a circuit but keep the current in it constant, the power dissipated by that circuit will

Physics
1 answer:
7nadin3 [17]3 years ago
5 0
By definition, the power is equal to the product of the current high squared by the value of the resistance.
 In other words:
 P = I ^ 2 * R
 where,
 I: Current
 R: resistance
 If we double the resistance in a circuit but keep the current in it constant, then:
 P = (I ^ 2) * (2 * R)
 P = 2 * (I ^ 2 * R)
 The power increases twice.
 answer:
 The power dissipated by that circuit will increase twice
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3 years ago
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<span>Vout = n2/n1*Vin (n2/n1 is essentially your 'transfer function' that dictates what a specified input would produce) </span>

<span>Solving the equation: </span>

<span>Vin = Vout*n1/n2 = (320V)*(600/300) = 640 V </span>

<span>This is checked by seeing if Vin is greater than Vout, which it is for a step down transformer.</span>
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3 years ago
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