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Olenka [21]
2 years ago
15

Keesha conducts an experiment by pouring equal amounts of boiling water into four containers. The containers are the same size a

nd shape, but they are made of different materials. The chart lists the containers according to their materials. A 2-column table with 4 rows. The first column labeled Container has entries W, X, Y, Z. The second column labeled Material has entries foam, glass, plastic, stainless steel. Using protective gloves, Keesha carefully touches each container immediately after pouring the water. Which container was likely the hottest? W X Y Z.
Physics
1 answer:
dybincka [34]2 years ago
5 0

Option Z is correct. The stainless steel container was likely the hottest. Stainless steel is an excellent heat conductor because it quickly warms the substance.

<h3 /><h3>What are the qualities of stainless steel?</h3>

Stainless steel is an excellent heat conductor because it quickly warms the substance or allows heat to travel through it. Stainless steel is also corrosion-resistant.

Foam, glass, and plastic, on the other hand, are all poor heat and electrical conductors. As a result, they do not allow heat to travel through.

As a result, we may deduce that, among the available possibilities, the stainless steel container was most likely the hottest.

Hence Option Z is correct. The stainless steel container was likely the hottest.

To learn more about stainless steel refer to the link;

brainly.com/question/94280

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Answer:

a)3000ohm

b)4.44mA

Explanation:

a) we were given a Nine tree lights connected inparallel across 120-V potential difference, since the resistor are in parallel we use the expresion below

1/R(total)= 1/R₁ + 1/R₂ + 1/R₃ + 1/R₃ +.... 1/R₉

But according to ohm'law which can be expressed below

V=IR

R=V/I

R(total)= 120/0.36

= 333.33ohm

1/R(total)= 1/R₁ + 1/R₂ + 1/R₃ + 1/R₃ +.... 1/R₉

R₁=R₂ =R₃ =R₄= R₅=R₆=R₇=R₈=R₉

1/R(total)=9/R

1/333.33= 9/R

R= 3000ohm

Therefore, the resistance is 3000ohm

b)the bulbs were connected in series here, then for series connection we use below expression

R₁=R₂ =R₃ =R₄= R₅=R₆=R₇=R₈=R₉

R(total)=9R

= 9*3000

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I=V/R

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= 4.44*10⁻³A

4.44mA

Therefore, the current is 4.4mA

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