Answer:
-
419kJ/mol
- 5,0,0,+12
- That catches fire spontaneously
Explanation:
1. Topic: Chemistry
ElementFirst Ionization Energy (kJ/mol) Lithium520Sodium496Rubidium403Cesium376According to the above table, which is most likely to be the first ionization energy for potassium?
2. Topic: Chemistry, Atom
The correct set of four quantum numbers for the valence electrons of the rubidium atom (Z=37) is:
3. Rubidium and cesium are pyrophoric. Here the term pyrophoric means:
- That does not catch fire at all
- That catches fire spontaneously
Answer : The correct option is, (2) Cr (Chromium)
Explanation :
The reactivity series of metal are arranged of the reactivity from the highest to the lowest. Reactivity series is used to determine the products of the single displacement reactions. In the single displacement reaction, the most reactive metal displaces the least reactive metal.
From the given reactivity series we conclude that there are two metal (Mg and Cr) are more reactive metal than the Ni and there are two metal (Pb and Cr) are less reactive metal than the Zn. So, the Cr (Chromium) is the metal which is more active than Ni and less active than Zn.
Hence, the correct option is, (2) Cr
Answer:
H⁺(aq)
Explanation:
Let's consider the following redox reaction.
Sn(s) + 2 H⁺(aq) → Sn²⁺(aq) + H₂(g)
We can identify both half-reactions.
Oxidation: Sn(s) → Sn²⁺(aq) + 2 e⁻
Reduction: 2 H⁺(aq) + 2 e⁻ → H₂(g)
Sn(s) undergoes oxidation so it is the reducing agent, while H⁺(aq) undergoes reduction so it is the oxidizing agent.
This question would be easier to answer if you attached a picture of the graph the question is referring to.
Here's link to the answer:
bit.
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