Answer:
Explanation:
By definition, <em>half neutralization</em> is the point at which half of the acid has been neutralized.
The neutralization reaction that you are studying is the acid-base reaction:
- HCl (aq) + NaOH (aq) → NaCl(aq) + H₂O (aq)
Then, since the starting molarity of the acid (HCl) is 0.2 M, you just need to find half of that concentration:
- Half molarity = M / 2 = 0.2 M / 2 = 0.1 M
So, the answer is the first choice: a. 0.1 M.
Answer:
Here's how I would explain it.
Explanation:
Think of it this way.
When you mix solutions of silver nitrate and sodium chloride, you get an immediate precipitate of silver chloride. The equation is
Ag⁺(aq) + Cl⁻(aq) ⟶ AgCl(s)
Now, take some AgCl and stir it vigorously with water.
You won't see much happening, because the AgCl is has such a low solubility. Not much of it will go into solution. And yet, a small amount of it does dissolve until the solution is saturated.
The concentration of AgCl in the saturated solution is
about 0.000 01 mol·L⁻¹.
I hope you will agree that this is a dilute solution even though it is saturated with AgCl.
Answer:
That it is cooking the food or whatever you have in the pot.
Explanation:
We are learning this in science.
<h3>
Answer:</h3>
0.0113 mol Ba(ClO₃)₂
<h3>
General Formulas and Concepts:</h3>
<u>Math</u>
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Chemistry</u>
<u>Atomic Structures</u>
- Reading a Periodic Table
- Using Dimensional Analysis
<h3>
Explanation:</h3>
<u>Step 1: Define</u>
3.45 g Ba(ClO₃)₂
<u>Step 2: Identify Conversions</u>
Molar Mass of Ba - 137.33 g/mol
Molar Mass of Cl - 35.45 g/mol
Molar Mass of O - 16.00 g/mol
Molar Mass of Ba(ClO₃)₂ - 137.33 + 2(35.45) + 6(16.00) = 304.33 g/mol
<u>Step 3: Convert</u>
- Set up:
- Multiply/Divide:
<u>Step 4: Check</u>
<em>Follow sig fig rules and round. We are given 3 sig figs.</em>
0.011336 mol Ba(ClO₃)₂ ≈ 0.0113 mol Ba(ClO₃)₂
