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nexus9112 [7]
3 years ago
8

A long chain of hydrocarbon bonded to cooh is a ________ acid.

Chemistry
2 answers:
vodomira [7]3 years ago
6 0
A long chain of hydrocarbon bonded to COOH is a FATTY acid.
prisoha [69]3 years ago
6 0

Answer: Option (d) is the correct answer.

Explanation:

A fatty acid is defined as a long chain of hydrocarbons that consists of a carboxylic group, that is, COOH group at the end of the chain.

General formula of a fatty acid is R-(CH_{2})_{n}-COOH where n is mostly an even number in many cases.

Fatty acids are also known as aliphatic monocarboxylic acid.

For example, C_{17}H_{35}COOH is the formula of stearic acid which is a fatty acid.

Thus, we can conclude that a long chain of hydrocarbon bonded to cooh is a fatty acid.

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ipn [44]

Answer:

It will take 28.5 minutes

Explanation:

<u>Step 1: </u>Data given

Mass of Cu = 4.50 grams

8.00 A of current are used

Molar mass of Cu = 63.5 g/mol

Step 2: Calculate time needed

Cu2+ →Electricity → Cu

we notice a flow of 2 electrons ⇒ This means the Faraday constant = 2F

Since Molar mass of Cu is 63.5 g/mol

63.5 grams of Cu is deposited by 2*96500 C

4.50 grams of Cu ((2*96500)/63.5)  * 4.50 = 13677.17 C

Q = It

13677.17 = 8t*60 seconds

t = 28.5 minutes

3 0
3 years ago
What is the number of moles in 546 g strontium nitrite?
Eduardwww [97]
The answer is 2.58 mol
4 0
2 years ago
Which type of bond is not backed by any specific collateral, such as land or equipment?
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Answer:

A

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I would rather say secured bond fit into not being backed by any specific collateral

7 0
1 year ago
A solution of LiCl in water has XLiCl = 0.0800. What is the molality? A solution of LiCl in water has XLiCl = 0.0800. What is th
Kay [80]

Answer:

mol LiCl = 4.83 m

Explanation:

GIven:

Solution of LiCl in water XLiCl = 0.0800

Mol of water in kg = 55.55 mole

Find:

Molality

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mole fraction = mol LiCl / (mol water + mol LiCl)

0.0800 = mol LiCl / (55.55 mol + mol LiCl)

0.0800 mol LiCl + 4.444 mol = mol LiCl

mol LiCl - 0.0800 mol LiCl = 4.444 mol

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7 0
3 years ago
The car wit fastest acceleration is the tempest. it has an acceleration of 6.1 m/s. suppose the car accelerates from rest to a f
ziro4ka [17]

<u>Given:</u>

Initial velocity (v1) = 0 m/s

Final velocity (v2) = 30 m/s

Acceleration (a) = 6.1 m/s2

<u>To determine:</u>

The time (t) taken to reach the final speed

<u>Explanation:</u>

Use the relation:

Acceleration (a) = [final velocity(v2) - initial velocity (v1)]/time (t)

t = (v2-v1)/a = 30-0/6.1 = 4.92 s

Ans: Time taken is around 4.9 s

3 0
3 years ago
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