Answer:
V₂ = 1.41 mL
Explanation:
According to general gas equation:
P₁V₁/T₁ = P₂V₂/T₂
Given data:
Initial volume = 21 mL
Initial pressure = 1 atm
Initial temperature = 10 °C (10 +273 = 283 K)
Final temperature = 12 °C (12 +273 = 285 K)
Final volume = ?
Final pressure = 15 atm
Formula:
P₁V₁/T₁ = P₂V₂/T₂
P₁ = Initial pressure
V₁ = Initial volume
T₁ = Initial temperature
P₂ = Final pressure
V₂ = Final volume
T₂ = Final temperature
Solution:
P₁V₁/T₁ = P₂V₂/T₂
V₂ = P₁V₁T₂/T₁ P₂
V₂ = 1 atm × 21 mL × 285 K / 283 K × 15 atm
V₂ = 5985 atm .mL. K / 4245 K. atm
V₂ = 1.41 mL
Answer:
B.) 36.0 grams
Explanation:
To find the mass of water, you need to (1) convert grams H₂ to moles (using the molar mass), then (2) convert moles H₂ to moles H₂O (using mole-to-mole ratio from reaction coefficients), and then (3) convert moles H₂O to grams (using the molar mass). It is important to arrange the conversions in a way that allows for the cancellation of units.
Molar Mass (H₂): 2(1.008 g/mol)
Molar Mass (H₂): 2.016 g/mol
Molar Mass (H₂O): 2(1.008 g/mol) + 15.998 g/mol
Molar Mass (H₂O): 18.014 g/mol
2 H₂ + O₂ -----> 2 H₂O
^ ^
4.0 g H₂ 1 mole 2 moles H₂O 18.014 g
--------------- x ---------------- x ------------------------ x --------------- = 36 g H₂O
2.016 g 2 moles H₂ 1 mole
Equation :
PbF2 ------> Pb2+ + 2F-
Solubility product is given as:
Ksp = [Pb2+][F-]^2
let x = [Pb2+]
Ksp = x(2x)^2 = 4(x)^3 = 4(2.08*10^-3)^3
Ksp = 3.60*10^-8
Which two types of cells are involved in fertilization?
✅
- Gametes are an organism's reproductive cells. The female gametes are called ova or egg cells, and the male gametes are called sperm.
- During fertilisation, the gametes (an egg and sperm) fuse to form a zygote.
Answer:
C
Explanation:
electronic waves transmits energy but mechanical waves require a medium in order to transport their energy from bgg one place to another.
