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Y_Kistochka [10]
3 years ago
13

Please I just need 1,2 I’ll give brainlest ://

Mathematics
1 answer:
Andre45 [30]3 years ago
7 0
1 Mean : 99.5
Median : 100
Range: 31
2 Mean: 29.7
Median: 29.5
Range: 7
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A small airplane is flying at a speed of 15,840 feet per minute. What is the airplane's speed in miles per hour?
Marat540 [252]

Answer:

im pretty sure you have to divide 15, 840 by 60 and you should get 0.264

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
4(b+24)=(12b+8) pls help
vfiekz [6]

Answer:

b=11

Step-by-step explanation:

4(b+24)=(12b+8)

4b+96=12b+8

-4. -4

96=8b+8

-8. -8

88=8b

88÷8=11

8 0
3 years ago
0.25 divided by 0.14
Fittoniya [83]

1.785714285714286 should be your answer

8 0
3 years ago
ASAP help me , I will give brainliest​
max2010maxim [7]

Answer:

Step-by-step explanation:

Perimeter = 2(l + w)

l = 8.5cm, perimeter = 24cm

24 = 2(8.5 + w)

Dividing through by 2

24/2 = 8.5 + w

12 = 8.5 + w

W = 12 - 8.5

W = 3.5cm

7 0
3 years ago
Read 2 more answers
The function H(t) = −16t2 + 60t + 95 shows the height H(t), in feet, of a projectile after t seconds. A second object moves in t
EleoNora [17]
H(t) = -16t² + 60t + 95
g(t) = 20 + 38.7t

h(1) = -16(1²) + 60(1) + 95 = -16 + 60 + 95 = -16 + 155 = 139
h(2) = -16(2²) + 60(2) + 95 = -16(4) + 120 + 95 = -64 + 215 = 151
h(3) = -16(3²) + 60(3) + 95 = -16(9) + 180 + 95 = -144 + 275 = 131
h(4) = -16(4²) + 60(4) + 95 = -16(16) + 240 + 95 = -256 + 335 = 79

g(1) = 20 + 38.7(1) = 20 + 38.7 = 58.7
g(2) = 20 + 38.7(2) = 20 + 77.4 = 97.4
g(3) = 20 + 38.7(3) = 20 + 116.1 = 136.1
g(4) = 20 + 38.7(4) = 20 + 154.8 = 174.8

Between 2 and 3 seconds. 
The range of the 1st object is 151 to 131.
The range of the 2nd object is 97.4 to 136.1

h(t) = g(t) ⇒ 131 = 131

<span>It means that the point where the 2 objects are equal is the point where the 1st object is falling down while the 2nd object is still going up. </span>
5 0
4 years ago
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