What is the force needed to accelerate a 10 kg object at 2 m/s??

An object is 10 cm from the mirror, its height is 1 cm and the focal length is 5 cm. What is the distance from the image to the

7nadin3 [17]

The answer to the question is 10

5 0

4 years ago

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What are the (time varying) amplitudes of the E and H fields if summer sunlight has an intensity of 1150 W/m2 in any Town?

Greeley [361]

Answer:

The relative strength of the gravitational and solar electromagnetic pressure forces is $7.33\times10^{13}\ N$

Explanation:

Given that,

Intensity = 1150 W/m²

(a). We need to calculate the magnetic field

Using formula of intensity

$I=\dfrac{E^2}{2\mu_{0}c}$

$E=\sqrt{2\times I\times\mu_{0}c}$

Put the value into the formula

$E=\sqrt{2\times1150\times4\pi\times10^{-7}\times3\times10^{8}}$

$E=931.17\ N/C$

Using relation of magnetic field and electric field

$B=\dfrac{E}{c}$

Put the value into the formula

$B=\dfrac{931.17}{3\times10^{8}}$

$B=0.0000031039\ T$

$B=3.10\times10^{-6}\ T$

(2). The relative strength of the gravitational and solar electromagnetic pressure forces of the sun on the earth

We need to calculate the gravitational force

Using formula of gravitational

$F_{g}=\dfrac{GmM}{r^2}$

Where, m = mass of sun

m = mass of earth

r = distance

Put the value into the formula

$F_{g}=\dfrac{6.67\times10^{-11}\times1.98\times10^{30}\times5.97\times10^{24}}{(1.496\times10^{11})^2}$

$F_{g}=3.52\times10^{22}\ N$

We need to calculate the radiation force

Using formula of radiation force

$F_{R}=\dfrac{I}{c}\times\pi\timesR_{e}^2$

$F_{R}=\dfrac{1150}{3\times10^{8}}\times\pi\times(6.371\times10^{6})^2$

$F_{R}=4.8\times10^{8}\ N$

We need to calculate the pressure

$\dfrac{F_{g}}{F_{R}}=\dfrac{3.52\times10^{22}}{4.8\times10^{8}}$

$\dfrac{F_{g}}{F_{R}}=7.33\times10^{13}\ N$

Hence, The relative strength of the gravitational and solar electromagnetic pressure forces is $7.33\times10^{13}\ N$

8 0

3 years ago

An Alaskan rescue plane traveling 45 m/sdrops a package of emergency rations froma height of 145 m to a stranded party of reese

Artist 52 [7]

Answer:

package will strike at a distance of 244.7 m

Explanation:

Given data;

Velocity of plane 45 m/s

Acceleration due to gravity 9.8 m/s^2

horizontal component of plane velocity is ux = 45 m/s

vertical component is zero

in the same way

ay = - 9.8 m/s^2

ax = .0 m/s^2

motion in y direction = -145 m

from equation of motion time of flight is

$s = ut + \frac{1}{2} at^2$

$-145 = 0 + \frac{1}{2} (-9.8) t^2$

solving for t we get

t = 5.439 sec

Motion in x direction

$s = ut + \frac{1}{2} at^2$

$= (45 \times 5.43) + \frac{1}{2} (0) 5.43^2$

s = 244.79 m

Therefore package will strike at a distance of 244.7 m

4 0

4 years ago

A ferromagnet and electromagnet can be used together to

natita [175]

Answer:

The correct option is : (a) Create a strong magnetic field.

Explanation:

An electromagnet is a substance which produces magnetic field when electric current is passed through it. The magnetic field produced by them disappears when the electric current is turned off.

A Ferromagnetic substance is a substance that gets magnetized when kept in an external magnetic field. Such substances remain magnetized even after the external magnetic field is removed.

When an electromagnet and a ferromagnet is combined, it results in the production of a strong magnetic field.

8 0

3 years ago

A bicyclist accelerates at 0.89 m/s2 during a 5.0 s interval. What is the change in speed if the bicyclist and the bicycle?

Allisa [31]

Answer:

attached below

Explanation:

3 0

3 years ago

What is the force needed to accelerate a 10 kg object at 2 m/s??​

What is the force needed to accelerate a 10 kg object at 2 m/s??