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3 years ago

11. Which of these is NOT true when dealing with refrigerants?

Engineering

1 answer:

Alexus [3.1K]3 years ago

4 0

Answer is an increase in pressure will cause an decrease in the pressure

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Does anybody know how to take a screenshot on a HP pavilion computer?

Setler79 [48]

Answer:

I do i do it everyday

Explanation:

Press windows and prt sc at the same time

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2 years ago

4. Which type of duct undergoes more rigorous testing before it's labeled?

Alenkasestr [34]

Answer:

Flexible duct

Explanation:

it is flexible duct due to current flow

7 0

3 years ago

How many trips would one rubber-tired Herrywampus have to make to backfill a space with a geometrical volume of 5400 cubic yard?

nikklg [1K]

Answer:

If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288

Explanation:

a) By volume.

The shrinkage factor is:

$\frac{5400cu-yd}{1-0.25} =7200cu-yd$

The volume at loose is:

$V_{loose} =V_{bank} (1+swell-factor)=7200(1+0.2)=8640cu-yd$

If the Herrywampus has a capacity of 30 cubic yard:

$\frac{8640cu-yd}{30cu-yd/trip} =288trip$

b) By weight

The swell factor in terms of percent swell is equal to:

$pounds-per-cubic-yard-loose=\frac{pounds-per-cubic-yard-bank}{\frac{percent-swell}{100}+1 }$

$pounds-per-cubic-yard-loose=\frac{3000}{\frac{20}{100} +1} =2500lb/cu-yd$

The weight of backfill is:

$8640cu-yd*2500\frac{lb}{cu-yd} *\frac{1ton}{2000lb} =10800ton$

The Herrywampus has a capacity of 40 ton:

$\frac{10800}{40ton/trip} =270trip$

If analyzed by volume capacity, more trips are needed to fill the space, thus the required trips are 288

8 0

3 years ago

A Venturi meter (see below) uses the principles of the Bernoulli equation to measure the velocity of a flow in a reactor system.

LenaWriter [7]

Answer:

Q=0.000604 m³/s

Explanation:

Given that

d₁=5 cm

d₂=1 cm

P= 30 KPa

Density of water ,ρ=1000 kg/m³

As we know that volume flow rate Q given as

$Q=A_1A_2\sqrt{\dfrac{\dfrac{2\Delta P}{\rho}}{A_1^2-A_2^2}}$

$A_1=\dfrac{\pi}{4}\times 0.05^2\ m^2$

A₁=0.0019 m²

$A_2\dfrac{\pi}{4}\times 0.01^2\ m^2$

A₂=0.000078 m²

$Q=0.0019 \times 0.000078 \sqrt{\dfrac{\dfrac{2\times 30\times 1000}{1000}}{0.0019^2-0.000078^2}}\ m^3/s$

Q=0.000604 m³/s

7 0

3 years ago

Which of the following are not related to a materials structure? (Mark all that apply) a)- Atomic bonding b)- Crystal structure

belka [17]

The answer is c) atomic number

3 0

3 years ago