11. Which of these is NOT true when dealing with refrigerants?

Which of the following is NOT a breach of Netiquette?

alexandr402 [8]

Answer:

I need some more point and i do not understand your question

Explanation:

7 0

3 years ago

1 gallon of benzene having a density of 0.88 g/mL is spilled in 200 feet by 150 foot lake having an average depth of 6 feet. Wha

Irina18 [472]

Answer:

The concentration of benzene in this contaminated lake would be 653549ng/L.

Explanation:

The concentration C of a contaminant over a body of water of volume V can be obtained as:

C=Mass contaminant / V

In this case, the volume of the body of water:

$V=200ft\cdot150ft\cdot6ft=5097.033m^3$

The mass of the contaminant (Benzene):

$m=\delta V_{ben}=0.88\frac{g}{ml} 1gal(us)=3.3311kg$

Therefore:

$C=\frac{m_{ben}}{V_{lake}}=6.53549\cdot10^{-4}kg/m^3=653549ng/l$

4 0

4 years ago

A 100 MHz generator with Vg= 10/00 v and internal resistance 50 ohms air line that is 3.6m and terminated in a 25+j25 ohm load

Lilit [14]

The value of Vz at point z from the generator = 17.748 ∠ -107.62° V

Given data :

Internal resistance = 50 ohms

Vg = 10 ∠ 0° v

length of air line = 3.6 m

Terminating resistance = 25 + j25 Ω

First step : Determine the Total impedance 

Total Impedance ( z ) = Rin + Rline + Rl + jXl

= 50 + 50 + 25 + j25

= 125 + j25 ≈ 127.47 ∠ 11.3°

Next step : Determine the current in the circuit

current ( I ) = Vg / z

= ( 10∠0° v ) / ( 127.47 ∠ 11.3° )

= 0.0784 ∠ -11.3 amp

Final step : Determine the value of Vz at point z from the generator

Vz = ( Vg + I * Ri ) - ( RI * I + Rline * I )

= ( 10∠0° + 0.0784 ∠ -11.3 * 50 ) - ( 25 + j25 + 50 * 0.0784 ∠ -11.3 )

= -5.37 - j16.91 ≈ 17.748 ∠ -107.62° V

Hence we can conclude that the value of Vz at point z form the generator 17.748 ∠ -107.62° V

Learn more about voltage : brainly.com/question/11288970

Hello your question is incomplete below is the complete question

A 100 MHz generator with Vg =10< 0 degree (v) and internal resistance 50-ohm is connected to a lossless 50-ohm air line that is 3.6m long and terminated in a 25+j25 (ohm) load.

Find (a) V(z) at a location z from the generate.

4 0

3 years ago

Select the correct answer. Which physical quantity measures the rate at which an objectâ€™s velocity changes?

ZanzabumX [31]

Answer:

I think answer is Force.

6 0

3 years ago

The pump of a water distribution system is powered by a 6-kW electric motor whose efficiency is 95 percent. The water flow rate

Sonja [21]

Answer:

a) Mechanical efficiency ( $\varepsilon$ )=63.15% b) Temperature rise= 0.028ºC

Explanation:

For the item a) you have to define the mechanical power introduced (Wmec) to the system and the power transferred to the water (Pw).

The power input (electric motor) is equal to the motor power multiplied by the efficiency. Thus, $Wmec=0.95*6kW=5.7 kW$ .

Then, the power transferred (Pw) to the fluid is equal to the flow rate (Q) multiplied by the pressure jump $\Delta P$ . So $P_W = Q*\Delta P=0.018m^3/s * 200x10^3 Pa=3600W$ .

The efficiency is defined as the ratio between the output energy and the input energy. Then, the mechanical efficiency is $\varepsilon=3.6kW/5.7kW=0.6315=63.15\%$

For the b) item you have to consider that the inefficiency goes to the fluid as heat. So it is necessary to use the equation of the heat capacity but in a "flux" way. Calling H to the heat transfered to the fluid, the specif heat of the water and $\rho$ the density of the water:

$[tex]H=(5.7-3.6) kW=\rho*Q*c*\Delta T=1000kg/m^3*0.018m^3/s*4186J/(kg \ºC)*\Delta T$ [/tex]

Finally, the temperature rise is:

$\Delta T=2100/75348 \ºC=0.028 \ºC$

7 0

3 years ago