Answer:
D. Overrule any other laws and traffic control devices.
Explanation:
Laws and traffic control devices are undoubtedly compulsory to be followed at every point in time to control traffic and other related situations. However, there are cases when certain instructions overrule these laws and traffic control devices. For example, when a traffic police is giving instructions, and though the traffic control devices too (such as traffic lights) are displaying their own preset lights to control some traffic, the instructions from the traffic police take more priority. This is because at that point in time, the instructions from the traffic control devices might not be just applicable or sufficient.
Also, in the case of instructions given by construction flaggers, these instructions have priority over those from controlling devices. This is because during construction traffic controls are redirected from the norms. Therefore, the flaggers such be given more importance.
Answer:
Check the explanation
Explanation:
Kindly check the attached images below to see the step by step explanation to the question above.
Answer:
The answer is 4.905 dB
Explanation:
Let say that that signal is sinusoidal i.e Am sin(wt)
Hence the power of the signal
From the question we are given that Amplitude Am = 10mV
substituting this value into the power formula
Power of the signal μW
From the question we where given that the signal to noise ratio is
Note: The dB of a value means the same thing as 10 log of the value
Now to obtain noise power we make it the subject in the above equation
μW
Now to obtain the overall signal gain we multiply the individual gain for the frequency that we are considering i.e 1KHz as our signal
Overall signal gain =
Now that we have gotten this we can now compute the output signal power gain denoted by
W
Now to obtain the overall signal gain we multiply the individual gain for the frequency that we are considering i.e 10KHz as our noise
Output signal to noise ratio (S/N) =
An o ring intended for use in a hydraulic system using MIL-H-5606 (mineral base) fluid will be marked with a blue stripe or dot.
Answer:
W = 166.35 KJ
Explanation:
P₁ = 600 KPa
V₁ = 0.4 m³
V₂ = 0.2 m³
T = 300 K
W = ?
We can find the solution from the standard relation for work in an isothermal process
W = -n*R*T*Ln (Vf / Vi)
We know that
n*R*T = P*V ⇒ P₁*V₁ = P₂*V₂ = n*R*T = 600 *0.4 = 240
Now, we use the equation
W = -n*R*T*Ln (Vf / Vi) = - P₁*V₁*Ln (Vf / Vi)
⇒ W = -240*Ln (0.2 / 0.4) = 166.35 KJ