Answer:
radius = 9.1 × 
m
Explanation:
given data
applied load = 5560 N
flexural strength = 105 MPa
separation between the support = 45 mm
solution
we apply here minimum radius formula that is
radius = ![\sqrt[3]{\frac{FL}{\sigma \pi}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7BFL%7D%7B%5Csigma%20%5Cpi%7D%7D)
.................1
here F is applied load and is length
put here value and we get
radius = ![\sqrt[3]{\frac{5560\times 45\times 10^{-3}}{105 \times 10^6 \pi}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B%5Cfrac%7B5560%5Ctimes%2045%5Ctimes%2010%5E%7B-3%7D%7D%7B105%20%5Ctimes%2010%5E6%20%5Cpi%7D%7D)
solve it we get
radius = 9.1 × m
Answer:
def filter_only_certain_strings(data_list):
new_list = []
for data in data_list:
# fix here. change >= to >
# because we want to return strings longer than 5 characters in length.
if type(data) == str and len(data) > 5:
new_list.append(data)
return new_list
Explanation:
def filter_only_certain_strings(data_list):
new_list = []
for data in data_list:
# fix here. change >= to >
# because we want to return strings longer than 5 characters in length.
if type(data) == str and len(data) > 5:
new_list.append(data)
return new_list
The difference between the electrical gradient is a electrical issue in power
Elements of Parallel Computing:-
Computer systems organization. Dependable and fault-tolerant systems and networks.
Computing methodologies. Parallel computing methodologies. ...
General and reference. Cross-computing tools and techniques. ...
Networks. Network performance evaluation.
Software and its engineering. ...
Theory of computation.
