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AysviL [449]
2 years ago
9

A gas has a volume of 240mL at 700mmHg pressure. What pressure is needed to reduce the volume to 80mL?

Chemistry
1 answer:
Dovator [93]2 years ago
5 0

Answer:

<h3>The answer is 2100 mmHg</h3>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

P_1V_1 = P_2V_2

Since we are finding the new pressure

P_2 =  \frac{P_1V_1}{V_2}  \\

From the question we have

P_2 =  \frac{240 \times 700}{80}  =  \frac{168000}{80}  =  \frac{16800}{8}  \\

We have the final answer as

<h3>2100 mmHg</h3>

Hope this helps you

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Ka(HClO</span>) = 2,9·10⁻⁸.<span>
This is buffer solution, so use Henderson–Hasselbalch equation: 
pH = pKa + log(cs</span> ÷ ck).<span>
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pH = 7,54 + 0.
pH = 7,54</span>
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