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3 years ago

A gas has a volume of 240mL at 700mmHg pressure. What pressure is needed to reduce the volume to 80mL?

Chemistry

1 answer:

Dovator [93]3 years ago

5 0

Answer:

<h3>The answer is 2100 mmHg</h3>

Explanation:

The new pressure can be found by using the formula for Boyle's law which is

$P_1V_1 = P_2V_2$

Since we are finding the new pressure

$P_2 = \frac{P_1V_1}{V_2} \\$

From the question we have

$P_2 = \frac{240 \times 700}{80} = \frac{168000}{80} = \frac{16800}{8} \\$

We have the final answer as

Hope this helps you

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13.41g of Fe(NO3)2 is dissolved in 83.0mL of water. Calculate the molarity of the solution.

Phoenix [80]

Answer:

whats the question in this

Explanation:

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2 years ago

Hydrogen gas, iodine vapor, hydrogen iodine are mixed in a flask and heated to 696°C. H2(g) + I2(g) ⇋ 2 HI(g) Kc = 52 at 696°C I

Anettt [7]

Answer: The equilibrium concentration of hydrogen gas is 0.0269 M

Explanation:

The chemical reaction follows the equation:

$H_2(g)+I_2(g)\rightleftharpoons 2HI(g)$

At t = 0 0.044M 0.044M 0.177M

At $t=t_{eq}$ (0.044-x)M (0.044-x)M (0.177+x)M

The expression for $K_c$ for the given reaction follows:

$K_c=\frac{[HI]^2}{[H_2]\times [I_2]}$

We are given:

$K_c=52$

Putting values in above equation, we get:

$52=\frac{(0.177+x)^2}{(0.044-x)^2}$

$x=0.0171M$

Hence, the equilibrium concentration of hydrogen gas is (0.044-x) M =(0.044-0.0171) M= 0.0269 M

7 0

3 years ago

PLEASE HELP!!!

umka21 [38]

Answer:

the answer is A

Explanation:

physical changes does not change the property of matter.

7 0

2 years ago

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The metabolic oxidation of glucose, C6H12O6, in our bodies produces CO2, which is expelled from our lungs as a gas.

enot [183]

Answer:

$\large \boxed{\text{21.6 L}}$

Explanation:

We must do the conversions

mass of C₆H₁₂O₆ ⟶ moles of C₆H₁₂O₆ ⟶ moles of CO₂ ⟶ volume of CO₂

We will need a chemical equation with masses and molar masses, so, let's gather all the information in one place.

Mᵣ: 180.16

C₆H₁₂O₆ + 6O₂ ⟶ 6CO₂ + 6H₂O

m/g: 24.5

(a) Moles of C₆H₁₂O₆

$\text{Moles of C$_{6}$H$_{12}$O}_{6} = \text{24.5 g C$_{6}$H$_{12}$O}_{6}\times \dfrac{\text{1 mol C$_{6}$H$_{12}$O}_{6}}{\text{180.16 g C$_{6}$H$_{12}$O}_{6}}\\\\= \text{0.1360 mol C$_{6}$H$_{12}$O}_{6}$

(b) Moles of CO₂

$\text{Moles of CO}_{2} =\text{0.1360 mol C$_{6}$H$_{12}$O}_{6} \times \dfrac{\text{6 mol CO}_{2}}{\text{1 mol C$_{6}$H$_{12}$O}_{6}} = \text{0.8159 mol CO}_{2}$

(c) Volume of CO₂

We can use the Ideal Gas Law.

pV = nRT

Data:

p = 0.960 atm

n = 0.8159 mol

T = 37 °C

(i) Convert the temperature to kelvins

T = (37 + 273.15) K= 310.15 K

(ii) Calculate the volume

$\begin{array}{rcl}pV &=& nRT\\\text{0.960 atm} \times V & = & \text{0.8159 mol} \times \text{0.082 06 L}\cdot\text{atm}\cdot\text{K}^{-1}\text{mol}^{-1} \times \text{310.15 K}\\0.960V & = & \text{20.77 L}\\V & = & \textbf{21.6 L} \\\end{array}\\\text{The volume of carbon dioxide is $\large \boxed{\textbf{21.6 L}}$}$

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2 years ago

hii what the procedures of making organic fertilizer and its precautions. can u answer it i kinda need it now

frez [133]

Answer:

Go through your kitchen waste. Vegetables and fruit peelings are the number one food remnants you should keep aside. ...

Add other organic materials to the compost. ...

Collect some garden waste. ...

Create the compost. ...

Apply the fertilizer.

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2 years ago

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