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cricket20 [7]
3 years ago
8

The rate constant k for a certain reaction is measured at two different temperatures:

Chemistry
1 answer:
bogdanovich [222]3 years ago
8 0

Answer:

Ea=5.5 Kcal/mole

Explanation:

Let rate constant are K_1  and K_2  at temperature T_1  and T_2

By using Arrhenius equation at two different two different temperature,

Log K_1/K_2 =E_a/2.303R*(1/T_2 -1/T_2 );T_1=273+376=649K  ;K_1=4.8*10^8;T_2=273+280=553K  ;K_2=2.3*10^8;R=2 cal/(mole.K);Log (4.8*10^8)/(2.3*10^8 )=E_a/2.303R*(1/553K-1/649); Log 4.8/2.3=E_a/2.303R*96/358897 ;0.32=E_a/2.303R*96/358897;E_a=(0.32*2.303R*358897)/96;  

By putting value of R=2 cal/mole.K

E_a=5510.265cal/mole;

By rounding off upto 2 significant figure;

E_a=5.5Kcal/mole;

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Answer:

So the volume will be 2.33 L

Explanation:

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Now we apply the Ideal Gases Law to find out the volume formed.

P . V = n . R . T

p = 1atm

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T = 273 + 23 = 296K

V = ?

1atm × V = 0.096 mol × 0.082 L.atm/mol.K × 296K

V = 0.096 mol × 0.082 L.atm/mol.K × 296K / 1atm

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3 years ago
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Can somebody plz help answer this science questions (only 1-2 sentences is good thx !
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<u>Explanation:</u>

To calculate the volume of solution, we use the equation used to calculate the molarity of solution:

\text{Molarity of the solution}=\frac{\text{Mass of solute}\times 1000}{\text{Molar mass of solute}\times \text{Volume of solution (in mL)}}

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Putting values in above equation, we get:

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Answer:

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