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chubhunter [2.5K]
3 years ago
13

What is an equation in slope-intercept form of the line that passes through (6, -7) and is perpendicular to the line shown below

?

Mathematics
1 answer:
expeople1 [14]3 years ago
7 0

Answer:

A

Step-by-step explanation:

it is y=-1/2x-4 for sure.

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What is the vertex of the graph y = x^2 + 6x - 5 ?
Dafna11 [192]
Given:  <span>y = x^2 + 6x - 5.  Then a = 1, b = 6 and c = -5.

The x-coord. of the vertex is given by x = -b / (2a), which here is x = -6 / (2*1) = -3.

Use the given formula </span><span>y = x^2 + 6x - 5 to find the value of y when x = -3:

y = (-3)^2 + 6(-3) - 5 = 9 - 18 - 5 = -14

Then the vertex is (-3, -14).</span>
6 0
3 years ago
-3[1+2(4+5)]<br> PLease answer ASAP!!!
vaieri [72.5K]

Answer:

-57

Step-by-step explanation:

<h2><u>Use BOMAS</u></h2>

B- brackets

O- of

M- multiplication

A- addition

S - subtraction

-3[1+2(4+5)]

first solve what is in the brackets

(4+5) = 9

place 9 in the brackets

-3[1+2(9)]

now multiply the 2 and 9

2*9 = 18

-3[1+18)]

1+ 18 = 19

now multiply the (-3) with 19

= <u>-57</u>

4 0
3 years ago
Read 2 more answers
Convert 12.4 pounds to ounces?
raketka [301]

Answer:

198.4 ounches is the real answer

4 0
2 years ago
Victoria searched her house for quarters. She started with 17 quarters and found 6 more quarters. She then goes to the arcade. I
Viefleur [7K]

Answer:

11 games

Step-by-step explanation:

17+6=23

23/2=11.5

Victoria can play 11 games. You'd usually round up, but in this case you can't play half a game so she'll play 11 games and have one quarter leftover.

7 0
3 years ago
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PLEASE HELP ME!!!!!!!!!
vitfil [10]
<h2>1)</h2>

(x - 4) {}^{2}  - 28 = 8 \\ (x - 4) {}^{2}  = 8 + 28 \\ (x - 4) {}^{2}  = 36

This must be true for some value of x, since we have a quantity squared yielding a positive number, and since the equation is of second degree,there must exist 2 real roots.

\sqrt{(x - 4) {}^{2} }  =  ± \sqrt{36}  \\x - 4 = ±6 \\ x _{1}- 4 = 6 \:  \:  \:  \:  \:  \:  \: \:  \:  \:  x _{2}- 4 =  - 6 \\ x_{1} = 6 + 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2} =  - 6 + 4 \\ x_{1} = 10 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:   \:  \:  \: \:  \: x_{2} =  - 2

<h2>2)</h2>

Well he started off correct to the point of completing the square.

(x - 3)  {}^{2}  = 16 \\ x - 3 = ±4 \\  \: x_{1}  - 3 = 4 \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  - 3 =  - 4 \\ x_{1}  = 7 \:  \:  \:  \:  \:  \:  \:  \:  \:  \: x_{2}  =  - 1

8 0
11 months ago
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