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3 years ago

Please do this for me I’m having a very hard time and failing math because of this!

Mathematics

2 answers:

otez555 [7]3 years ago

5 0

Multiple the speed and time then add that to the first time and get new time

Ganezh [65]3 years ago

3 0

Answer:

Remember The distance, speed, time triangle

Step-by-step explanation:

Formula is

Speed x time=distance

Distance divided by speed=time

distance divided by time=speed

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3.3 greater than or less than 0.33

nika2105 [10]

Answer:

Greater Than

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

George and Paul use a metal alloy that is 18.1% copper to make jewelry. How many ounces of an alloy that is 14% copper must be m

ella [17]

Answer:

Use 49 ounces of the 14% allow and 41 ounces of the 23% alloy.

Step-by-step explanation:

Each ounce of the 14% copper contains 0.14 ounce of pure copper.

Each ounce of the 23% copper contains 0.23 ounce of pure copper.

Each ounce of the 18.1% copper contains 0.181 ounce of pure copper.

Use x ounces of the 14% and y ounces of the 23% to make 90 ounces of 18.1% alloy.

x+y = 90

y = 90-x

0.14x + 0.23y = 0.181·90

0.14x + 0.23(90-x) = 16.29

0.14x + 20.7 - 0.23x = 16.29

-0.09x + 20.7 = 16.29

4.41 = 0.09x

x = 49

y = 90-x = 41

Use 49 ounces of the 14% allow and 41 ounces of the 23% alloy.

7 0

3 years ago

Given a quadratic function in vertex form:

Alja [10]

Answer:

See below

Step-by-step explanation:

Part A

A vertical stretch takes place when $a\cdot f(x)$ given that $|a| > 1$

Part B

A vertical compression takes place when $a\cdot f(x)$ given that $0 < |a| < 1$

Part C

A vertical stretch is different than a horizontal compression:

In a vertical stretch, the input stays the same, but the output is multiplied by the scale factor
In a horizontal compression, the output stays the same, but the input is multiplied by the scale factor

Part D

A reflection across the x-axis means that the output, our y-variable, is the opposite sign. This means that all values of $a$ must be negative such that $a\cdot f(x)$ as mentioned in parts A and B. Also, in part C, since our scale factor is negative, the output is the only one being multiplied by the scale factor.