Answer is: pH of methylamine is 12,2.
Chemical reaction: CH₃NH₂(aq)+ H₂O(l) ⇌ CH₃NH₃⁺(aq) + OH⁻<span>(aq).
Kb(</span>CH₃NH₂) = 4,4·10⁻⁴.
c₀(CH₃NH₂) =
0,57 M.
c(CH₃NH₃⁺) = c(OH⁻) =
x.
c(NH₂OH) = 0,57 M - x.
Kb
= c(CH₃NH₃⁺) · c(OH⁻) / c(CH₃NH₂).
0,00044 = x² / (0,57 M - x).
Solve
quadratic equation: x = c(OH⁻) =
0,0156 mol/L.
pOH
= -log(0,0156 mol/L.) = 1,80.
pH
= 14 - 1,80 = 12,2.
B: SO2
S=Sulfur
O=Oxygen
Dioxide if i am correct means 2 oxygen.
so thats one Sulfur and 2 oxygen.
The correct answer is d)all of above
examples for a are tyrosine for b lysine and for c isoleucine
Answer:
Option 5 → 7.01 g
Explanation:
Molarity . volume (L) = Moles
This can help us to determine the moles of KOH that are in the solution.
We convert the volume from mL to L → 250 mL . 1L / 1000mL = 0.250 L
0.5 mol /L . 0.250L = 0.125 moles of KOH
Now, we only have to convert the moles to mass, by the molar mass:
Moles . molar mass = mass → 0.125 mol . 56.1 g/mol = 7.01 g
