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vaieri [72.5K]
3 years ago
12

Predicting nuclear stability is important when determining whether or not a nuclear reaction can take place spontaneously.Use th

e following set of guidelines to predict the nuclear stability of the elements listed below.
1. Stable nuclei have a high neutron-to-proton ratio, greater than 1.25 beyond atomic number 40 and continuing to rise at higher atomic numbers.
2. The majority of stable nuclei have even numbers of neutrons and protons. Odd-even and even-odd combinations can be stable but stability is less likely.
3. Nuclei that have the magic numbers of 2, 8, 20, 28, 50, or 82 protons or 2, 8, 20, 28, 50, 82 or 126 neutrons are more stable than nuclei that do not contain these numbers.
4. Nuclei that have atomic numbers greater than 83 are unstable.Nuclei are considered stable if one or more criteria are met.
Chemistry
1 answer:
Nitella [24]3 years ago
8 0

Answer:

a) unstable

b) unstable

c) unstable

d) Stable

Explanation:

a)

^{212}_{84}PO

The given isotope , atomic number is greater than 83.(84>83).

Therefore, it is unstable.

b)

^{30}_{15}P

The given isotope  has even number of protons(15) and neutrons(15).

Therefore, it is unstable.

c)

^{137}_{55}Cs

The given isotope  has even number of protons(15).

Therefore, it is unstable.

d)

^{118}_{50}Sn

The given isotope have even number of neutrons ( 68) an d the proton ratio is \frac{68}{50}= 1.36.It is more than 1.25.

Therefore, it is stable.

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A gas has a volume of 62.65 L at STP. At what temperature (in oC) would the volume of the gas be 78.31 L at a pressure of 612.0
masha68 [24]

Answer:

1.788 C DEGREES

Explanation:

STP is 1 atm at  273.15 K

P1V1/T1  = P2V2/T2

(1)(62.65) / (273.15) = (612/760)(78.31)/T2

T2 = 274.93 K     = 1.788 C

5 0
2 years ago
A bar of gold is 5.0mm thick, 10.0cm long and 2.0cm wide. It has a mass of exactly 193.0g. What is the desity of gold?
Tanzania [10]
<h3>Answer:</h3>

19.3 g/cm³

<h3>Explanation:</h3>

Density of a substance refers to the mass of the substance per unit volume.

Therefore, Density = Mass ÷ Volume

In this case, we are given;

Mass of the gold bar = 193.0 g

Dimensions of the Gold bar = 5.00 mm by 10.0 cm by 2.0 cm

We are required to get the density of the gold bar

Step 1: Volume of the gold bar

Volume is given by, Length × width × height

Volume =  0.50 cm × 10.0 cm × 2.0 cm

             = 10 cm³

Step 2: Density of the gold bar

Density = Mass ÷ volume

Density of the gold bar = 193.0 g ÷ 10 cm³

                                      = 19.3 g/cm³

Thus, the density of the gold bar is 19.3 g/cm³

3 0
3 years ago
A tank at is filled with of dinitrogen monoxide gas and of boron trifluoride gas. You can assume both gases behave as ideal gase
blsea [12.9K]

Answer:

(1). Mole fraction = 0.152 for sulfur tetrafluoride gas.

Mole fraction = 0.848 For dinitrogen monoxide gas.

(2). Partial Pressure for dinitrogen monoxide gas = 187 kPa

Partial Pressure for sulfur tetrafluoride gas = 33.4 kpa.

(3). Total Partial Pressure = 220.4 kpa.

Explanation:

So, we are given the following data or parameters or information in the question above;

• Volume of the tank = 5.00L per tank;

• Temperature of the tank = 7.03°C;

• The mass of the content in the tank =

17.7g of dinitrogen monoxide gas and

7.77g of sulfur tetrafluoride gas.

So, we will be making use of the formulae below to calculate the MOLE FRACTION:

Moles, n= mass/molar mass and mole fraction = n(1)/ n(1) + n(2) per each constituents.

Moles, n1 = 17.7g of dinitrogen monoxide gas/ 44 grams per mole. =0.4023 moles.

Moles, n2 = 7.77g of sulfur tetrafluoride gas/ 108.1 grams per mole. = 0.07188 moles.

Total numbers of moles = n1 + n2 = 0.47415 moles

Mole fraction =0.4023 / 0.47415 = 0.848 of dinitrogen monoxide gas.

Mole fraction = 0.07188/0.47415 = 0.152 of sulfur tetrafluoride gas.

PART TWO: CALCULATE THE PARTIAL PRESSURE AND TOTAL PRESSURE BY USING THE FORMULA BELOW;

pressure × volume = number of moles × gas constant, R × temperature.

Pressure = n × R × T/ V.

For dinitrogen monoxide gas. ;

Partial Pressure = 0.4023 × 8.314 × 280.03 / 5 × 10^-3 = 187 kPa.

For sulfur tetrafluoride gas

Partial Pressure = 0.07188 × 8.314 ( × 280.03 / 5 × 10^-3. = 33.4 kpa.

(3). Total pressure = (187 + 33.4)kpa = 220.4 kpa

6 0
3 years ago
Sodium (NA) and potassium (K) are in the same group in the periodic table. Sodium is in the 11th position. How many valence elec
garri49 [273]
C= 1 Valence electron
3 0
3 years ago
Read 2 more answers
Consider the following reaction at 298 K.
Jlenok [28]

Answer and Explanation:

The reaction is in the gas phase, so the equilibrium constant is expressed in terms of the partial pressures (P) of the products and reactants, as follows:

Kp = \frac{P^{2}_{SO_{3}  } }{P_{SO_{2}} ^{2}P_{O_{2}}  }

We have the following data:

P(SO₃) = 2.6 atm

P(O₂) = 0.43 atm

We need Kp for this reaction. We can assume that in Appendix 4 we found that Kp = 7 x 10²⁴.

Then, we introduce the data in the equilibrium constant expression to calculate the partial pressure f SO₂ (PSO₂), as follows:

P_{SO_{2} } = \sqrt{\frac{P_{SO_{3} } ^{2} }{Kp P_{O_{2} } } } = \sqrt{\frac{(2.6 atm)^{2} }{(7 x 10^{24)}(0.43 atm) } } = 1.5 x 10^{-12} atm

Therefore, the partial pressure of SO₂ is 1.5 x 10⁻¹² atm (for the given Kp).

4 0
3 years ago
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