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vaieri [72.5K]
2 years ago
12

Predicting nuclear stability is important when determining whether or not a nuclear reaction can take place spontaneously.Use th

e following set of guidelines to predict the nuclear stability of the elements listed below.
1. Stable nuclei have a high neutron-to-proton ratio, greater than 1.25 beyond atomic number 40 and continuing to rise at higher atomic numbers.
2. The majority of stable nuclei have even numbers of neutrons and protons. Odd-even and even-odd combinations can be stable but stability is less likely.
3. Nuclei that have the magic numbers of 2, 8, 20, 28, 50, or 82 protons or 2, 8, 20, 28, 50, 82 or 126 neutrons are more stable than nuclei that do not contain these numbers.
4. Nuclei that have atomic numbers greater than 83 are unstable.Nuclei are considered stable if one or more criteria are met.
Chemistry
1 answer:
Nitella [24]2 years ago
8 0

Answer:

a) unstable

b) unstable

c) unstable

d) Stable

Explanation:

a)

^{212}_{84}PO

The given isotope , atomic number is greater than 83.(84>83).

Therefore, it is unstable.

b)

^{30}_{15}P

The given isotope  has even number of protons(15) and neutrons(15).

Therefore, it is unstable.

c)

^{137}_{55}Cs

The given isotope  has even number of protons(15).

Therefore, it is unstable.

d)

^{118}_{50}Sn

The given isotope have even number of neutrons ( 68) an d the proton ratio is \frac{68}{50}= 1.36.It is more than 1.25.

Therefore, it is stable.

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Answer:

The answer to your question is: kc = 6.48

Explanation:

Data

             Given                 Molecular weight

CaO =    44.6 g                    56 g

CO₂ =     26 g                       44 g

CaCO₃ = 42.3 g                  100 g

Find moles

        CaO                 56 g ----------------  1 mol

                                 44.6 g --------------   x

                               x = (44.6 x 1) / 56 = 0.8 mol

        CO₂                 44 g -----------------  1 mol

                                26 g ----------------    x

                               x = (26 x 1 ) / 44 = 0.6  moles

        CaCO₃            100 g ---------------   1 mol

                                42.3g --------------    x

                              x = (42.3 x 1) / 100 = 0.423 moles

       

Concentrations

 

        CaO     =    0.8 / 6.5  = 0.12 M

         CO₂    =     0.6 / 6.5 = 0.09 M

        CaCO₃  =   0.423 / 6.5 = 0.07 M

Equilibrium constant =   \frac{[products]}{[reactants]}

Kc = [0.07] / [[0.12][0.09]

Kc = 0.07 / 0.0108

kc = 6.48

7 0
3 years ago
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