All categories

3 years ago

How can you increase the amount of energy in a wave?

Chemistry

2 answers:

solmaris [256]3 years ago

6 0

Answer:

The higher the amplitude, the higher the energy. To summarise, waves carry energy. The amount of energy they carry is related to their frequency and their amplitude.

patriot [66]3 years ago

5 0

Explanation:

One is amplitude, which is the distance from the rest position of a wave to the top or bottom. Large amplitude waves contain more energy. The other is frequency, which is the number of waves that pass by each second. If more waves pass by, more energy is transferred each second.

You might be interested in

How would I find the answer?

ELEN [110]

Answer:

Explanation:

The noble gas that is isoelectronic with Br⁻ is krypton.

This is because krypton is the closest noble gas to Br on the periodic table.

Electronic configuration of Bromine is;

2, 8, 18, 7

Br⁻ becomes; 2, 8, 18, 8

Krypton is; 2, 8, 18, 8

4 0

3 years ago

A phase diagram assumes ______ is kept constant

bogdanovich [222]

The answer is b i think

8 0

3 years ago

Read 2 more answers

Two significance of melting point

eimsori [14]

The significance of melting points are

it gives us a idea about inter molecular force which binds the particles together.

at melting point the solid and liquid states exist in equilibrium.

<h3>What is melting point?</h3>

The melting point is the temperature at which a given substance change its physical state from solid to liquid. At this point solids and liquids exist at equilibrium. Melting point of a substance depends on pressure. The melting point of ice increases when pressure decreases. Melting point of a substance decreases by the presence of impurities in it. so you increase or decrease the melting point on any substance by adding more impurities. Ionic bonds, shape and size of molecules are some other factors that affect the melting point.

To learn more about melting point refer:

brainly.com/question/25689052

#SPJ2

5 0

2 years ago

Calculate the [H+] and pH of a 0.0040 M hydrazoic acid solution. Keep in mind that the Ka of hydrazoic acid is 2.20×10−5. Use th

Vera_Pavlovna [14]

Answer:

$[H^+]=0.000285$

$pH=3.55$

Explanation:

In this, we can with the ionization equation for the hydrazoic acid ( $HN_3$ ). So:

$HN_3~~H^+~+~N_3^-$

Now, due to the Ka constant value, we have to use the whole equilibrium because this is not a strong acid. So, we have to write the Ka expression:

$Ka=\frac{[H^+][N_3^-]}{[HN_3]}$

For each mol of $H^+$ produced we will have 1 mol of $N_3^-$ . So, we can use "X" for the unknown values and replace in the Ka equation:

$Ka=\frac{X*X}{[HN_3]}$

Additionally, we have to keep in mind that $HN_3$ is a reagent, this means that we will be consumed. We dont know how much acid would be consumed but we can express a subtraction from the initial value, so:

$Ka=\frac{X*X}{0.004-X}$