Explanation:
Newton's second law shows that there is a direct relation ship between force and acceleration . the grater force that is applied on a object of given mass the more the accelerate. for example doubling the force in the object doubles it's acceleration.
This is a problem based on the logic and interpretation of the variables. From the measured data taken
what is collected by the two individuals is expressed as,
- NED reference system: (x, t)
- PAM reference system: (x ', t')
From the reference system we know that ν is the speed of PAM (the other reference system) as a measurement by NED.
Then ν' is the speed of NED (from the other system of the reference) as a measurement by PAM.
Answer:
Its momentum is multiplied by a factor of 1.25
Explanation:
First, we <u>calculate the initial velocity of the object</u>:
- 59.177 J = 0.5 * 3.4 kg * v₁²
With that velocity we can <u>calculate the initial momentum of the object</u>:
Then we <u>calculate the velocity of the object once its kinetic energy has increased</u>:
- (59.177 J) * 1.57 = 0.5 * 3.4 kg * v₂²
And <u>calculate the second momentum of the object</u>:
Finally we <u>calculate the factor</u>:
Answer:
a) t = 0.90 s, b) t = 0.815 s, c) t = 0.90 s, d) x = 3.6 m, e) t = 0.639 s
Explanation:
all these exercises are about kinematics
a) The body is released from rest,
y = y₀ + v₀ t - ½ g t²
in this case when reaching the ground y = 0 and its initial velocity is vo = 0
0 = y₀ + 0 - ½ g t²
t² = 2 y₀ / g
t² = 2 4 /9.81
t² = 0.815
t = √0.815
t = 0.90 s
b) It is thrown upwards at v₀ = 4 m / s
y = y₀ + v₀ t - ½ g t²
in this case the initial and final height is the same
y = y₀ = 0
0 = v₀ t -1/2 g t²
t = 2 v₀ / g
t = 2 4 /9.81
t = 0.815 s
c) the ball is at y₀ = 4 m and its initial velocity is horizontal v₀ = 4 m / s
y = y₀ + v_{oy} t - ½ g t²
0 = y₀ + 0 - ½ g t²
t² = 2 i / g
t² = 2 4 / 9.81
t² = 0.815
t = 0.90 s
d) the horizontal distance traveled is
x = v₀ₓ t
x = 4 0.90
x = 3.6 m
e) We can calculate the time to fall from I = 2 m
y = y₀ + v_{oy} t - ½ g t²
0 = y₀ + 0 - ½ g t²
t² = 2 y₀i / g
t² = 2 2 /9.81
t² = 0.4077
t = 0.639 s
Therefore, when making measurements, you should find readings around this value.
Answer:
d)no unit
Explanation:
refractive index is a unit less quantity.
