All categories

3 years ago

This graph shows the change in the force of gravity as distance increases. The graph will never reach zero, which suggests that

Physics

1 answer:

kumpel [21]3 years ago

7 0

Answer:

Gravity can never be zero.

Explanation:

The graph shows that the force of gravity is always present despite the amount of distance, indicating that gravity will never be 0. Note, however, that gravity can be extremely small as the distance increases. The limit of the force of gravity as the distance approaches infinity is 0, but never actually touches this value.

You might be interested in

Which statements describe the motion of the object represented by the graph? Check all that apply.

Sav [38]

Answer:a, d, e

Explanation:

6 0

3 years ago

Read 2 more answers

A rocket is fired at 100 m/s at an angle of 37, how many seconds did it take to get to the top?

Kobotan [32]

Answer:

6.14 s

Explanation:

The time the rocket takes to reach the top is only determined from its vertical motion.

The initial vertical velocity of the rocket is:

$u_y = u sin \theta = (100)(sin 37^{\circ})=60.2 m/s$

where

u = 100 m/s is the initial speed

$\theta=37^{\circ}$ is the angle of launch

Now we can apply the suvat equation for an object in free-fall:

$v_y = u_y +gt$

where

$v_y$ is the vertical velocity at time t

$g=-9.8 m/s^2$ is the acceleration of gravity

The rocket reaches the top when

$v_y =0$

So by substituting into the equation, we find the time t at which this happens:

$t=-\frac{u_y}{g}=-\frac{60.2}{-9.8}=6.14 s$

7 0

3 years ago

Two point charges of equal magnitude q are held a distance d apart. Consider only points on the line passing through both charge

NemiM [27]

let us consider that the two charges are of opposite nature .hence they will constitute a dipole .the separation distance is given as d and magnitude of each charges is q.

the mathematical formula for potential is $V=\frac{1}{4\pi\epsilon} \frac{q}{d}$

for positive charges the potential is positive and is negative for negative charges.

the formula for electric field is given as- $E=\frac{1}{4\pi\epsilon} \frac{q}{r^2}$

for positive charges,the line filed is away from it and for negative charges the filed is towards it.

we know that on equitorial line the potential is zero.hence all the points situated on the line passing through centre of the dipole and perpendicular to the dipole length is zero.

here the net electric field due to the dipole can not be zero between the two charges,but we can find the points situated on the axial line but outside of charges where the electric field is zero.

now let the two charges of same nature.let these are positively charged.

here we can not find a point between two charges and on the line joining two charges where the potential is zero.

but at the mid point of the line joining two charges the filed is zero.

5 0

3 years ago

Which parts of Dalton’s atomic theory had to be revised

eduard

<span> The indivisibility of an atom was proved wrong an atom can be further subdivided into protons, neutrons and electrons. However an atom is the smallest particle that takes </span>part<span> in chemical reactions</span>

7 0

3 years ago

Where is the natural light display called aurora borealis located?

Xelga [282]

The natural light display called aurora borealis is located in the northern

hemisphere.

There are two types of aurora which are called aurora borealis and aurora

australis. The aurora borealis is located in the Northern hemisphere while

the aurora australis is located in the Southern hemisphere.

They receive their energy through the interaction of charged particles

on the Sun and Earth to produce the light display. An example

of the interaction involves solar wind with atoms of the upper atmosphere.

Read more on brainly.com/question/20191244

5 0

2 years ago

This graph shows the change in the force of gravity as distance increases. The graph will never reach zero, which suggests that​

This graph shows the change in the force of gravity as distance increases. The graph will never reach zero, which suggests that