Answer:
mass of ammonia = 10.090 kg
Explanation:
We have the following chemical reaction:
N₂ + 3 H₂ → 2 NH₃
number of moles = mass / molecular weight
number of moles of N₂ = 28 / 14 = 2 kmoles
number of moles of H₂ = 2 / 2 = 1 kmole
We see that the limiting reactant is hydrogen (H₂).
Now we devise the following reasoning:
if 3 kmoles of hydrogen produces 2 kmoles of ammonia
then 1 kmole of hydrogen produces X kmoles of ammonia
X = (1 × 2) / 3 = 0.66 kmoles of ammonia
But the yield is 90% so the real quantity of ammonia produced is:
(90/100) × 0.66 = 0.594 kmoles of ammonia
mass = number of moles × molecular weight
mass of ammonia = 0.594 × 17 = 10.090 kg
