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kolbaska11 [484]
3 years ago
13

Explain whether a tennis ball dropped from a high distance experiences an elastic collision or inelastic collision

Physics
1 answer:
hodyreva [135]3 years ago
4 0
I need help on that too poop head
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A person experiencing heat
balu736 [363]

Answer:

it will be heavy sweating

Explanation:

because if humans expierment a heavy heat they might be sweating heavly

7 0
3 years ago
If a fast-moving car making a loud noise approaches and moves past the person, what will happen as the distance between the two
Mrac [35]
The Car Will Cause Some Kind Of Wind Wave And Hit The Person's Body But Its Not Harmful And You Will Hear The Loud Noise Passing By

5 0
4 years ago
Is the distance we walk equal to the magnitude of our displacement?
Yuliya22 [10]

Answer:

If you take the first example of the walk around the desk, it should be apparent that sometimes the distance is the same as the magnitude of the displacement. ... Since the displacement is measured along the shortest path between two points, its magnitude is always less than or equal to the distance.

8 0
3 years ago
Air at 20ºC with a convection heat transfer coefficient of 20 W/m2·K blows over a pond. The surface temperature of the pond is 2
dimulka [17.4K]

Answer:

The heat flux between the surface of the pond and the surrounding air  is<em> 60 W/</em>m^{2}<em> </em>

Explanation:

Heat flux is the rate at which heat energy moves across a surface, it is the heat transferred per unit area of the surface. This can be calculated using the expression in equation 1;

q = Q/A ...............................1

since we are working with the convectional heat transfer coefficient equation 1 become;

q = h (T_{sf} -T_{sd}) ........................2

where q is the  heat flux;

Q is the heat energy that will be transferred;

h is the convectional heat coefficient = 20 W/m^{2}.K;

T_{sf} is the surface temperature = 23^{o}C 23°C + 273.15  = 296.15 K;

T_{sd} is the surrounding temperature = 20^{o}C = 20°C + 273.15  = 293.15 K;

The values are substituted into equation 2;

q = 20 W/m^{2}.K (  296.15 K - 293.15 K)

q = 20 W/m^{2}.K ( 3 K)

q =  60 W/m^{2}

Therefore the heat flux between the surface of the pond and the surrounding air  is 60 W/m^{2}

3 0
4 years ago
.........................................
Nastasia [14]

Answer:

that is like trying to learn your abc's at the age of 2 months old..........

Explanation:

:) just sayin

7 0
3 years ago
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