Answer:
0.54454
104.00902 N
Explanation:
m = Mass of wheel = 100 kg
r = Radius = 0.52 m
t = Time taken = 6 seconds
= Final angular velocity
= Initial angular velocity
= Angular acceleration
Mass of inertia is given by
Angular acceleration is given by
Equation of rotational motion
The coefficient of friction is 0.54454
At r = 0.25 m
The force needed to stop the wheel is 104.00902 N
There are four states of matter: solid, liquid, gas and plasma. Solid has a shape and volume of its own. A liquid takes the shape of the container does not occupy entirely the volume of the container. For gas, it takes the shape of the container as well as taking the volume of the container. In this case, if the system is only composed of gas, the statement given is true.
Answer:
The speed of the clay before the impact was 106.35 m/s.
Explanation:
the only force doing work on the system is the frictional force, f, the work done by f is given by:
Wf = ΔK = Kf - Ki
The clay and the block will come to rest after sliding Δx = 7.50 m, if their intial speed is v and the combined mass is m and μ is the coefficient of friction and g is gravity,then:
f×Δx = Ki
m×g×Δx×μ = 1/2×m×v^2
v^2 = 2×g×Δx×μ
= 2×(9.8)×(7.50)×(0.650)
= 95.55
v = 9.78 m/s
This is the veloty of clay and block after the clay hit the block.
if the velocity the clay and block attains after the impact is v and the initial speed of the clay is v1 and the mass is m and the speed of the block initially is V = 0 m/s and the mass is M, then according to the conservation of linear momentum:
m×v1 +M×V = v(m + M)
m×v1 = v(m + M)
v1 = v(m + M)/m
v1 = (9.78)(8.3×10^-3 + 82×10^-3)/(8.3×10^-3)
v1 = 106.35 m/s
Therefore, the speed of the clay before the impact was 106.35 m/s.
The one with the majority of its mass furthest away from its center will reach the bottom last. The thin walled cylinder has all of its mass at the edge of itself, meaning its mass is the furthest from its center. If we take a look at the solid cylinder, it has some mass at its edge, but it also has a lot of mass very close to its center so it will roll faster than the thin walled cylinder. And the thin walled cylinder will be slower than the normal hollow cylinder because even though the hole cylinder doesn't have any mass at its center it does have some mass closer to its center than the thin walled cylinder.
So the last one to reach the bottom is the thin walled cylinder.
