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Ronch [10]
3 years ago
10

A chemistry teacher is able to grade chemistry labs at a rate of 5 labs for every 3 minutes. They need to grade 165 labs how man

y hours will it take?​
Chemistry
1 answer:
PIT_PIT [208]3 years ago
3 0

Answer:

1.65hr

Explanation:

Given parameters:

Number of labs  = 5 labs

 Time taken  = 3 minutes

Unknown:

Time taken in hours to grade 165 labs  = ?

Solution:

Let us find the rate of the teacher;

  Rate  = \frac{number of labs}{time}  

  Insert the parameters and solve;

   Rate  = \frac{5}{3}   = 1.67labs/min

Now;

   Time to grade 165 labs  = \frac{number of labs}{rate}  

   Time to grade 165 labs  = \frac{165}{1.67}   = 98.8min

  Since;

               60min = 1hr

               98.8min  = \frac{98.8}{60}   = 1.65hr

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Explanation:

the first reason why is that i got that quistion right. and when objects are unbalanced it gives negative acellaration

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3 years ago
Marijuana most abundant psychoactive chemical is delta-9- tetrahydrocannabinol or
Galina-37 [17]
<h2>Answer:</h2>

<u>Yes the statement is</u><u> True</u>

<h2>Explanation:</h2>

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3 years ago
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faltersainse [42]

Answer:

a) 1.61 mol

b) Al is limiting reactant

c) HBr is in excess

Explanation:

Given data:

Moles of Al = 3.22 mol

Moles of HBr = 4.96 mol

Moles of H₂ formed = ?

What is limiting reactant =

What is excess reactant = ?

Solution:

Chemical equation:

2Al  + 2HBr  → 2AlBr + H₂

Now we will compare the moles:

                Al              :               H₂

                  2              :               1

                 3.22         :            1/2×3.22 = 1.61 mol

                HBr            :              H₂

                 2                :               1

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The number of moles of H₂ produced by Al are less it will be limiting reactant while HBr is present in excess.

Moles of H₂ :

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6 0
3 years ago
If 4520 kj of heat is needed to boil a sample of water, what is the mass of water
Cerrena [4.2K]

Answer:

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Explanation:

If we have the value 4520kj is because the question is related to Energy and heat capacity. In this case, the law and equation that we use is the following:

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In order to determine the mass, I will have the same equation but finding m

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Answer:

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3 years ago
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