Answer:
I hope this link helps you.
Explanation:
http://astronomy.swin.edu.au/cosmos/P/Phases
Answer is: this is an example of an Arrhenius acid.
An Arrhenius acid is a
substance that dissociates in water to form hydrogen ions or protons (H⁺).
For example hydrochloric acid: HCl(aq) → H⁺(aq) + Cl⁻(aq).
An Arrhenius base is a
substance that dissociates in water to form hydroxide ions (OH⁻<span>).
In this example lithium hydroxide is an Arrhenius base:</span>
LiOH(aq) → Li⁺(aq) + OH⁻(aq).
Answer:
0.022 mol O
Explanation:
Mg3(Si2O5)2(OH)2
We can see that 1 mol of this substance has 3 mol of Mg.
Oxygen altogether is 5*2 (from (Si2O5)2) + 2(from(OH)2) = 10 +2 = 12
So, 1 mol of this substance has 12 mol oxygen.
So, 1 mol of this substance contains 3 mol Mg and 12 mol O, or
ratio Mg : O = 3 : 12 = 1 : 4
1 mol Mg ----- 4 mol O
0.055 mol Mg ---x mol O
x = 0.055*4/1 = 0.220 mol O
Answer:
The Prandtl number for this example is 14,553.
Explanation:
The Prandlt number is defined as:
![Pr=\frac{C_{p}*\mu}{k}](https://tex.z-dn.net/?f=Pr%3D%5Cfrac%7BC_%7Bp%7D%2A%5Cmu%7D%7Bk%7D)
To compute the Prandlt number for this case, is best if we use the same units in every term of the formula.
![\mu=1896 \frac{lbm}{ft*h}*\frac{1000 g}{2.205 lbm}*\frac{3.281 ft}{1 m}*\frac{1h}{3600s} =7938 \frac{g}{m*s}](https://tex.z-dn.net/?f=%5Cmu%3D1896%20%5Cfrac%7Blbm%7D%7Bft%2Ah%7D%2A%5Cfrac%7B1000%20g%7D%7B2.205%20lbm%7D%2A%5Cfrac%7B3.281%20ft%7D%7B1%20m%7D%2A%5Cfrac%7B1h%7D%7B3600s%7D%20%20%3D7938%20%5Cfrac%7Bg%7D%7Bm%2As%7D)
Now that we have coherent units, we can calculate Pr
![Pr=\frac{C_{p}*\mu}{k}=0.66*7938/0.36=14553](https://tex.z-dn.net/?f=Pr%3D%5Cfrac%7BC_%7Bp%7D%2A%5Cmu%7D%7Bk%7D%3D0.66%2A7938%2F0.36%3D14553)