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puteri [66]
3 years ago
15

Dilute nitric acid reacts with sodium carbonate solution. 2HNO3 (aq) + Na2CO3 (aq) → 2NaNO3 (aq) + H2O (l) + CO2 (g) 25.00 cm3 o

f sodium carbonate solution of concentration 0.153 mol/dm3 reacts completely with 25.3 cm3 of dilute nitric acid.
a) Calculate the number of moles of sodium carbonate.

b) Use your answer to (a) and the equation for the reaction to calculate the number of moles of nitric acid that reacted.

c) Use your answer to (b) to calculate the concentration of dilute nitric acid in mol/dm3.

d) Use your answer to (a), calculate the maximum volume (at r.t.p.) of carbon dioxide gas that could be produced in this reaction.
Chemistry
1 answer:
sammy [17]3 years ago
6 0
A) Mol = Conc x Vol
=0.153 x 0.025
= 0.003825 mol

b) HNO3 : Na2CO3
2 : 1
Moles of HNO3 = 0.00385 x 2
= 0.00765 mol

c) Conc = 0.00765 / 0.0253
= 0.3023715415 mol/dm^3

d) Vol of CO2 = 0.003825 x 24
= 0.0918 dm^3

Hope this helps! Im not 100% sure about the last one thoo.

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Complete and balance the equation for this reaction in acidic solution. zns+no3-
Viefleur [7K]
The equation given in question is as follow,

                                  ZnS + NO₃⁻    →    Zn²⁺ + S + NO

Oxidation state of elements in reactant side are as follow,
                                      Zn  =  +2
                                      S    =  -2
                                      N    =  +5
                                      O   =  -2
Oxidation state of elements in product side are as follow,
                                      Zn  =  +2
                                      S    =  0
                                      N    =  +2
                                      O   =  -2
So, In this reaction Nitrogen is Reduced while Sulfur is Oxidized.

Now Split the reaction into two half cell reactions,

Reduction Reaction,
                                ZnS     →     S  +  2e⁻
Oxidation Reaction,
                               NO₃⁻  +  3e⁻   →     NO

As the oxygen atoms are not balance, So, in acidic medium add H⁺ on the side having greater number of Oxygen atom and H₂O on the side having less number of Oxygen atoms,
Hence,
                                 H⁺  +   NO₃⁻  + 3e⁻    →     NO  +  H₂O
Now Balance the reaction,

                                 4H⁺  +   NO₃⁻  + 3e⁻    →     NO  +  2H₂O

So, write both half cell equations as,
 
                                             ZnS     →     S  +  2e⁻   --------- (1)
                               4H⁺  +   NO₃⁻  + 3e⁻    →     NO  +  2H₂O  -------(2)

Multiply eq. 1 with 3 and eq. 2 with 2 to equalize the electron.
So,
                                         3ZnS     →     3S  +  6e⁻   

                       8H⁺  +   2NO₃⁻  + 6e⁻    →     2NO  +  4H₂O 
                     _____________________________________(e⁻ cancelled)

                            3ZnS + 2NO₃⁻ + 8H⁺   → 3Zn + 3S + 2NO + 4H₂O
8 0
4 years ago
Balance the following equations, and indicate whether they are combination, decomposition, or combustion reactions.1. C3H6(g)+O2
antoniya [11.8K]

Answer :

(1) This reaction is a combustion reaction.

(2) This reaction is a decomposition reaction.

(3) This reaction is a combustion reaction.

(4) This reaction is a combination reaction.

(5) This reaction is a combination reaction.

Explanation :

Combination reaction : It is a type pf reaction in which the two or more molecules combine to form a larger single molecule as a product.

Decomposition reaction : It is a type of reaction in which a single larger compound decomposes to give two or more smaller molecules as a product.

Combustion reaction : It is a type of reaction in which a hydrocarbon molecule react with the oxygen molecule to give carbon dioxide and and water as a product.

1. C_3H_6(g)+O_2(g)\rightarrow CO_2(g)+H_2O(g)

This reaction is a combustion reaction.

2. NH_4NO_3(s)\rightarrow N_2O(g)+H_2O(l)

This reaction is a decomposition reaction.

3. C_5H_6O(l)+O_2(g)\rightarrow CO_2(g)+H_2O(g)

This reaction is a combustion reaction.

4. N_2(g)+H_2(g)\rightarrow NH_3(g)

This reaction is a combination reaction.

5. K_2O(s)+H_2O(l)\rightarrow KOH(aq)

This reaction is a combination reaction.

5 0
4 years ago
A Cu2+ solution is prepared by dissolving a 0.4749 g piece of copper wire in acid. The solution is then passed through a Walden
Luda [366]

Answer:

Concentration of Cr_2O_7^{2-} = 0.03101 M

Concentration of MnO_4^- = 0.03721 M

Explanation:

A)

The reduction for Cr_2O_7^{2-} is;

Cr_2O_7^{2-} + 14 H ^+ _{(aq)}  + 6 e^- -----> 2 Cr^{3+} _{(aq)}+7H_2O _{(l)}

Cu^+_{(aq)} -----> Cu^{2+} _{(aq)} + 1 e^-

6 moles of Cu ^+ = 1 mole of Cr_2O_7^{2-}

number of moles of Cu reacted = \frac{mass \ of \ Cu \ wire }{ molecular weigh tof \ Cu wire }

number of moles of Cu reacted = \frac{0.4749}{63.55}

number of moles of Cu reacted = 0.00747 mole

number of moles of Cr_2O_7^{2-}reacted = \frac{0.00747}{6}

number of moles of Cr_2O_7^{2-}reacted = 0.001245 mole

Concentration of Cr_2O_7^{2-} = \frac{number \ of moles }{Volume}

Given that the volume = 40.15 mL = 40.15 *10^{-3}; we have:

Concentration of Cr_2O_7^{2-} = \frac{0.001245}{40.15*10^{-3}}

Concentration of Cr_2O_7^{2-} = 0.03101 M

B)

The reduction for MnO_4^- is;

MnO_4^- + 8H^+ + 5 e^- -----> Mn^{2+} + 4H_2O

Cu^+_{(aq)} -----> Cu^{2+} _{(aq)} + 1 e^-

5 moles of Cu ^+ = 1 mole of Cr_2O_7^{2-}

number of moles of Cu reacted = \frac{mass \ of \ Cu \ wire }{ molecular weigh tof \ Cu wire }

number of moles of Cu reacted = \frac{0.4749}{63.55}

number of moles of Cu reacted = 0.00747 mole

number of moles of MnO_4^- reacted = \frac{0.00747}{5}

number of moles of MnO_4^- reacted = 0.001494 mole

Concentration of MnO_4^- = \frac{number \ of moles }{Volume}

Given that the volume = 40.15 mL = 40.15 *10^{-3}; we have:

Concentration of MnO_4^- = \frac{0.001494 }{40.15*10^{-3}}

Concentration of MnO_4^- = 0.03721 M

3 0
4 years ago
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gtnhenbr [62]
The   chemical  formula  of  nickel  (ii) hypochlorite  is Ni(CIO)2. Nickel (II)   has a  charge  of  +2  while (CIO-)  which  is  a  poly  atomic ion  of  chlorine and  oxygen has  a  charge  of   -1.  After  balancing  the  charge  of    nickel with  that   of  CIO- you  get  the  chemical  formula  as  Ni(CIO)2.
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Inessa [10]

Answer:

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