The equation given in question is as follow,
ZnS + NO₃⁻ → Zn²⁺ + S + NO
Oxidation state of elements in reactant side are as follow,
Zn = +2
S = -2
N = +5
O = -2
Oxidation state of elements in product side are as follow,
Zn = +2
S = 0
N = +2
O = -2
So, In this reaction Nitrogen is Reduced while Sulfur is Oxidized.
Now Split the reaction into two half cell reactions,
Reduction Reaction,
ZnS → S + 2e⁻
Oxidation Reaction,
NO₃⁻ + 3e⁻ → NO
As the oxygen atoms are not balance, So, in acidic medium add H⁺ on the side having greater number of Oxygen atom and H₂O on the side having less number of Oxygen atoms,
Hence,
H⁺ + NO₃⁻ + 3e⁻ → NO + H₂O
Now Balance the reaction,
4H⁺ + NO₃⁻ + 3e⁻ → NO + 2H₂O
So, write both half cell equations as,
ZnS → S + 2e⁻ --------- (1)
4H⁺ + NO₃⁻ + 3e⁻ → NO + 2H₂O -------(2)
Multiply eq. 1 with 3 and eq. 2 with 2 to equalize the electron.
So,
3ZnS → 3S + 6e⁻
8H⁺ + 2NO₃⁻ + 6e⁻ → 2NO + 4H₂O
_____________________________________(e⁻ cancelled)
3ZnS + 2NO₃⁻ + 8H⁺ → 3Zn + 3S + 2NO + 4H₂O
Answer :
(1) This reaction is a combustion reaction.
(2) This reaction is a decomposition reaction.
(3) This reaction is a combustion reaction.
(4) This reaction is a combination reaction.
(5) This reaction is a combination reaction.
Explanation :
Combination reaction : It is a type pf reaction in which the two or more molecules combine to form a larger single molecule as a product.
Decomposition reaction : It is a type of reaction in which a single larger compound decomposes to give two or more smaller molecules as a product.
Combustion reaction : It is a type of reaction in which a hydrocarbon molecule react with the oxygen molecule to give carbon dioxide and and water as a product.
1. 
This reaction is a combustion reaction.
2. 
This reaction is a decomposition reaction.
3. 
This reaction is a combustion reaction.
4. 
This reaction is a combination reaction.
5. 
This reaction is a combination reaction.
Answer:
Concentration of
= 0.03101 M
Concentration of
= 0.03721 M
Explanation:
A)
The reduction for
is;


6 moles of
= 1 mole of 
number of moles of Cu reacted = 
number of moles of Cu reacted = 
number of moles of Cu reacted = 0.00747 mole
number of moles of
reacted = 
number of moles of
reacted = 0.001245 mole
Concentration of
= 
Given that the volume = 40.15 mL =
; we have:
Concentration of
= 
Concentration of
= 0.03101 M
B)
The reduction for
is;


5 moles of
= 1 mole of 
number of moles of Cu reacted = 
number of moles of Cu reacted = 
number of moles of Cu reacted = 0.00747 mole
number of moles of
reacted = 
number of moles of
reacted = 0.001494 mole
Concentration of
= 
Given that the volume = 40.15 mL =
; we have:
Concentration of
= 
Concentration of
= 0.03721 M
The chemical formula of nickel (ii) hypochlorite is Ni(CIO)2. Nickel (II) has a charge of +2 while (CIO-) which is a poly atomic ion of chlorine and oxygen has a charge of -1. After balancing the charge of nickel with that of CIO- you get the chemical formula as Ni(CIO)2.
Answer:
Bones are the correct answer.