Answer:
For
- 5.556 lb/s
For
- 7.4047 lb/s
Solution:
As per the question:
System Load = 96000 Btuh
Temperature, T = 
Temperature rise, T' =
Now,
The system load is taken to be at constant pressure, then:
Specific heat of air, 
Now, for a rise of
in temeprature:


Now, for
:


Answer:
q=2313.04
T=690.86°C
Explanation:
Given that
Thickness t= 20 cm
Thermal conductivity of firebrick= 1.6 W/m.K
Thermal conductivity of structural brick= 0.7 W/m.K
Inner temperature of firebrick=980°C
Outer temperature of structural brick =30°C
We know that thermal resistance

These are connect in series

Heat transfer

So heat flux
q=2313.04
Lets temperature between interface is T
Now by equating heat in both bricks

So T=690.86°C
Answer:
Please see the attached file for the complete answer.
Explanation: