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jeka57 [31]
3 years ago
5

Consider five wireless stations A,B,C,D,E. Station

Engineering
2 answers:
Elena L [17]3 years ago
6 0

Solution to 1. When A is sending to B, then communication is established within A,C,E.

Solution to 2. When B is sending to A, A can communicate with other stations and in this case ,there is a possibility of communication with C,D,E as B is sending to A.

Solution to 3. When B is sending to C, communication is established between A,B and D.

Sladkaya [172]3 years ago
5 0

Answer and Explanation:

Communication is possible when sender and reciever both communicates in well manner and communication is only possible when there is a sender available to communicate.

1) Sending data from A to B, there is no possible communication between A and other stations because while A is communicating with B the packet's of station A will interfere with other packets by other stations. Thus while transmission from A to B there is no other communication possible between any other station.

2) In this case also there is no communication possible as B can communicate with other stations except D. If E and C try to send some data to D at the same time then this would interfere B's transmission to A. Thus while transmission from B to A there is no communication possible between any other station.

3) Station B can communicate with E, A and C but not with D. while sending data from B to C the communication will be interfered by the station B's transmission to A. But station E can safely transmit data to D while communication between station B to C. Thus there is one communication possible while sending data from B to C which is E to D.

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Thermal energy generated by the electrical resistance of a 5-mm-diameter and 4-m-long bare cable is dissipated to the surroundin
ella [17]

Answer:

surface temperature = 128.74⁰c

Explanation:

Given data

diameter of cable = 5 mm = 0.005 m

length of cable = 4 m

T∞ ( surrounding temperature ) = 20⁰c

voltage drop across cable ( dv )= 60 V

current across cable = 1.5 A

attached to this answer is the comprehensive analysis and solution to the problem.

The assumption made is not a good one since the calculated Ts ( surface temperature ) is very much different from the assumed Ts

6 0
3 years ago
Which of the following is not one of the systems required to ensure the safe and correct operation of an engine?
velikii [3]
Brake system

Explanation: the engine doesn’t need to be running to make the brake system work the brake system it’s independent
6 0
3 years ago
Hỗ trợ mình với được không các bạn
Leya [2.2K]

Answer:

Explanation:

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6 0
3 years ago
For the pipe-fl ow-reducing section of Fig. P3.54, D 1 5 8 cm, D 2 5 5 cm, and p 2 5 1 atm. All fl uids are at 20 8 C. If V 1 5
bonufazy [111]

Answer:

The total force resisted by the flange bolts is  163.98 N

Explanation:

Solution

The first step is to find  the pipe cross section at the inlet section

Now,

A₁ = π /4 D₁²

D₁ =  diameter of the pipe at the inlet section

Now we insert 8 cm for D₁ which gives us A₁ = π /4 D (8)²

=50.265 cm² * ( 1 m²/100² cm²)

= 5.0265 * 10^⁻³ m²

Secondly, we find cross section area of  the pipe at the inlet section

A₂ = π /4 D₂²

D₂ =  diameter of the pipe at the inlet section

Now we insert 5 cm for D₁ which gives us A₁ = π /4 D (5)²

= 19.63 cm² * ( 1 m²/100² cm²)

= 1.963 * 10^⁻³ m²

Now,

we write down the conversation mass relation which is stated as follows:

Q₁ = Q₂

Where Q₁ and Q₂ are both the flow rate at the exist and inlet.

We now insert A₁V₁ for Q₁ and A₂V₂ for Q₂

So,

V₁ and V₂ are defined as the velocities at the inlet and exit

We now insert 5.0265 * 10^⁻³ m² for A₁ 5 m/s for V₁ and 1.963 * 10^⁻³ m² for A₂

= 5.0265  * 5 = 1.963 * V₂

V₂ = 12.8 m/s

Note: Kindly find an attached copy of the part of the solution to the given question below

8 0
3 years ago
Write a program that prompts for a line of text and then transforms the text based on chosen actions. Actions include reversing
nlexa [21]

Answer:

public class TextConverterDemo

{

//Method definition of action1337

public static String action1337(String current)

{

//Replace each L or l with a 1 (numeral one)

 current = current.replace('L', '1');

 current = current.replace('l', '1');

 

 //Replace each E or e with a 3 (numeral three)

 current = current.replace('E', '3');

 current = current.replace('e', '3');

 //Replace each T or t with a 7 (numeral seven)

 current = current.replace('T', '7');

 current = current.replace('t', '7');

 //Replace each O or o with a 0 (numeral zero)

 current = current.replace('O', '0');

 current = current.replace('o', '0');

 

//Replace each S or s with a $ (dollar sign)

 current = current.replace('S', '$');

 current = current.replace('s', '$');

 return current;

}

//Method definition of actionReverse

//This method is used to reverses the order of

//characters in the current string

public static String actionReverse(String current)

{

 //Create a StringBuilder's object

 StringBuilder originalStr = new StringBuilder();

 //Append the original string to the StribgBuilder's object

 originalStr.append(current);

 //Use reverse method to reverse the original string

 originalStr = originalStr.reverse();

 

 //return the string in reversed order

 return originalStr.toString();

}

//Method definition of main

public static void main(String[] args)

{

    //Declare variables

 String input, action;

 

 //Prompt the input message

 System.out.println("Welcome to the Text Converter.");

 System.out.println("Available Actions:");

 System.out.println("\t1337) convert to 1337-speak");

 System.out.println("\trev) reverse the string");

 System.out.print("Please enter a string: ");

   

 //Create a Scanner class's object

 Scanner scn = new Scanner(System.in);

 

 //Read input from the user

 input = scn.nextLine();

 do

 {

  /*Based on the action the user chooses, call the appropriate

   * action method. If an unrecognized action is entered then

   * the message "Unrecognized action." should be shown on a

   * line by itself and then the user is prompted again just

   * as they were when an action was performed.

   * */

  System.out.print("Action (1337, rev, quit): ");

  action = scn.nextLine();

  if (action.equals("1337"))

  {

   input = action1337(input);

   System.out.println(input);

  } else if (action.equals("rev"))

  {

   input = actionReverse(input);

   System.out.println(input);

  } else if (!action.equals("quit"))

  {

   System.out.println("Unrecognized action.");

  }

 } while (!action.equals("quit"));

 System.out.println("See you next time!");

 scn.close();

}

}

7 0
3 years ago
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