1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
jeka57 [31]
4 years ago
5

Consider five wireless stations A,B,C,D,E. Station

Engineering
2 answers:
Elena L [17]4 years ago
6 0

Solution to 1. When A is sending to B, then communication is established within A,C,E.

Solution to 2. When B is sending to A, A can communicate with other stations and in this case ,there is a possibility of communication with C,D,E as B is sending to A.

Solution to 3. When B is sending to C, communication is established between A,B and D.

Sladkaya [172]4 years ago
5 0

Answer and Explanation:

Communication is possible when sender and reciever both communicates in well manner and communication is only possible when there is a sender available to communicate.

1) Sending data from A to B, there is no possible communication between A and other stations because while A is communicating with B the packet's of station A will interfere with other packets by other stations. Thus while transmission from A to B there is no other communication possible between any other station.

2) In this case also there is no communication possible as B can communicate with other stations except D. If E and C try to send some data to D at the same time then this would interfere B's transmission to A. Thus while transmission from B to A there is no communication possible between any other station.

3) Station B can communicate with E, A and C but not with D. while sending data from B to C the communication will be interfered by the station B's transmission to A. But station E can safely transmit data to D while communication between station B to C. Thus there is one communication possible while sending data from B to C which is E to D.

You might be interested in
Expert Review is done by end users.
Free_Kalibri [48]

Answer:nononononono

Explanation:

6 0
3 years ago
A 3-m wide rectangular channel has a flow velocity of 1.8 m/s when the depth of flow is 1.2 m. what will be the flow velocity wh
valina [46]

Answer:

The flow velocity reduces to 0.72 m/s

Explanation:

According to the equation of continuity discharge in the channel should remain same

Thus we have

A_{1}V_{1}=A_{2}V_{2}

For a rectangular channel we have Area=Depth\times Width

Applying values in the continuity equation and since the width of the channel remains constant 3.0 m we have

3\times 1.8\times 1.2=3\times 3\times V_{2}\\\\\therefore V_{2}=\frac{6.48}{9}=0.72m/s

6 0
3 years ago
. Carly's Catering provides meals for parties and special events. In Chapter 2, you wrote an application that prompts the user f
klio [65]

Answer:

Explanation:

public class Event

  public final static int PRICE_PER_GUEST = 35;

  public final static int CUT_OFF = 50;

 

  //Attributes

  private String eventNum;

  private int noOfGuest;

  private int price;

 

  /**

  * param eventNum the eventNum to set

  */

  public void setEventNum(String eventNum)

      this.eventNum = eventNum;

 

 

  /**

  * param noOfGuest the noOfGuest to set

  */

  public void setNoOfGuest(int noOfGuest)

      this.noOfGuest = noOfGuest;

      this.price = this.noOfGuest * PRICE_PER_GUEST;

 

 

  /**

  * return the eventNum

  */

  public String getEventNum()

      return eventNum;

 

 

  /**

  * return the noOfGuest

  */

  public int getNoOfGuest()

6 0
3 years ago
You are using a Geiger counter to measure the activity of a radioactive substance over the course of several minutes. If the rea
Reika [66]

Answer: 33.35 minutes

Explanation:

A(t) = A(o) *(.5)^[t/(t1/2)]....equ1

Where

A(t) = geiger count after time t = 100

A(o) = initial geiger count = 400

(t1/2) = the half life of decay

t = time between geiger count = 66.7 minutes

Sub into equ 1

100=400(.5)^[66.7/(t1/2)

Equ becomes

.25= (.5)^[66.7/(t1/2)]

Take log of both sides

Log 0.25 = [66.7/(t1/2)] * log 0.5

66.7/(t1/2) = 2

(t1/2) = (66.7/2 ) = 33.35 minutes

4 0
3 years ago
1. What is the maximum value of the linear density in a crystalline solid (linear density defined as the fraction of the line le
insens350 [35]
Number three number three number three I’m not 100% sure though
4 0
3 years ago
Other questions:
  • Two AAA-size lithium batteries are connected in series in a flashlight. Each battery has 3.5 volt and 4- Amp-hour capacity. If t
    8·1 answer
  • Compare the tensile load capacity of a 5/16-18 UNC thread and a 5/16-24 UNF thread made of the same material.
    6·1 answer
  • What the Best describes the purpose of the occupational safety and health administración OSHA
    12·1 answer
  • The decay of a radioactive isotope can be theoretically modeled with the following equation, where C0 is the initial amount of t
    6·1 answer
  • The line voltage of a balanced three-phase transmission line is 4200 V rms. The transmission line has an impedance of 4 6 Z j l
    12·1 answer
  • Plot the following trig functions using subplots, choosing an appropriate layout for the number of functions displayed. The subp
    8·1 answer
  • List the three main methods employed in dimensional analysis
    6·1 answer
  • A string of ASCII characters has been converted to hexadecimal resulting in the following message: 4A EF 62 73 73 F4 E5 76 E5 Of
    6·1 answer
  • What’s the population in the world and why does it keep increasing in bad areas.
    8·1 answer
  • PLEASE HELP AND ANSWER MY OTHER QUESTIONS!,
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!