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jeka57 [31]
3 years ago
5

Consider five wireless stations A,B,C,D,E. Station

Engineering
2 answers:
Elena L [17]3 years ago
6 0

Solution to 1. When A is sending to B, then communication is established within A,C,E.

Solution to 2. When B is sending to A, A can communicate with other stations and in this case ,there is a possibility of communication with C,D,E as B is sending to A.

Solution to 3. When B is sending to C, communication is established between A,B and D.

Sladkaya [172]3 years ago
5 0

Answer and Explanation:

Communication is possible when sender and reciever both communicates in well manner and communication is only possible when there is a sender available to communicate.

1) Sending data from A to B, there is no possible communication between A and other stations because while A is communicating with B the packet's of station A will interfere with other packets by other stations. Thus while transmission from A to B there is no other communication possible between any other station.

2) In this case also there is no communication possible as B can communicate with other stations except D. If E and C try to send some data to D at the same time then this would interfere B's transmission to A. Thus while transmission from B to A there is no communication possible between any other station.

3) Station B can communicate with E, A and C but not with D. while sending data from B to C the communication will be interfered by the station B's transmission to A. But station E can safely transmit data to D while communication between station B to C. Thus there is one communication possible while sending data from B to C which is E to D.

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3 years ago
A cooling system load is 96,000 BTUh sensible. How much chilled air is required to satisfy the load if the system is designed fo
Natalija [7]

Answer:

For 20^{\circ} - 5.556 lb/s

For 15^{\circ} - 7.4047 lb/s

Solution:

As per the question:

System Load = 96000 Btuh

Temperature, T = 20^{\circ}

Temperature rise, T' = 15^{\circ}

Now,

The system load is taken to be at constant pressure, then:

Specific heat of air, C_{p} = 0.24 btu/lb ^{\circ}F

Now, for a rise of 20^{\circ} in temeprature:

\dot{m}C_{p}\Delta T = 96000

\dot{m} = \frac{96000}{C_{p}\Delta T} = \frac{96000}{0.24\times 20} = 20000 lb/h = \frac{20000}{3600} = 5.556 lb/s

Now, for 15^{\circ}:

\dot{m}C_{p}\Delta T = 96000

\dot{m} = \frac{96000}{C_{p}\Delta T} = \frac{96000}{0.24\times 15} = 26666.667 lb/h = \frac{26666.667}{3600} = 7.4074 lb/s

4 0
3 years ago
A furnace wall is to be built of 20-cm firebrick and building (structural) brick of same thickness. The thermal conductivities o
Norma-Jean [14]

Answer:

q=2313.04W/m^2

T=690.86°C

Explanation:

Given that

Thickness t= 20 cm

Thermal conductivity of firebrick= 1.6 W/m.K

Thermal conductivity of structural brick= 0.7 W/m.K

Inner temperature of firebrick=980°C

Outer temperature of structural brick =30°C

We know that thermal resistance

R=\dfrac{t}{KA}

These are connect in series

R=\left(\dfrac{t}{KA}\right)_{fire}+\left(\dfrac{t}{KA}\right)_{struc}

R=\dfrac{0.2}{1.6A}+\dfrac{0.2}{0.7A}\ K/W

R=\dfrac{23}{56A}\ K/W

Heat transfer

Q=\dfrac{\Delta T}{R}

Q=56A\times \dfrac{980-30}{23}\ W

So heat flux

q=2313.04W/m^2

Lets temperature between interface is T

Now by equating heat in both bricks

\dfrac{980-T}{\dfrac{0.2}{1.6A}}=\dfrac{T-30}{\dfrac{0.2}{0.7A}}

So T=690.86°C

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3 years ago
In some synchronizer applications, the clock frequency f is substituted for the parameter a in metastability MTBF calculations,
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Answer:

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