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Inessa05 [86]
3 years ago
12

As described in "A Note About Bacterial Reproduction -- and the "Culture Bias,"" the organism Epulopisciumdoes not divide by bin

ary fission. Rather, each cell increases in sizeand divides to produce multiple daughter cells that are held within the original cell well.After lysis, those daughters are released to repeat the process. Assuming Epulopisciumcould be grown in pure culture in the laboratory in broth and on solid media (it currently cannot), which method would be best for measuring the increase in biomass during growth?Select one:a. Turbidity readings from a spectrophotometer; the increase in biomass will directly vary with the turbidity of the culture.
b. The viable plate count; each colony derives from a single cell and the number of coloniesequals the number of cells. c. Direct microscopic count; the experimenter can directly count the number of cells and extrapolate to the biomass.d. Chemostat growth; it will prevent the culture from entering the death phase
Engineering
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

A

Explanation:

The best method that will yield significantly more accurate result is to use spectrophotometer to read the turbidity of the sample and increase in turbidity is associated with increase biomass.

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hoa [83]

Answer:

Engineering is the use of scientific principles to design an build machines, structure, an other item including bridges, tunnels, road etc

3 0
3 years ago
Two sites are being considered for wind power generation. On the first site, the wind blows steadily at 7 m/s for 3000 hours per
kirill [66]

Solution :

Given :

$V_1 = 7 \ m/s$

Operation time, $T_1$ = 3000 hours per year

$V_2 = 10 \ m/s$

Operation time, $T_2$ = 2000 hours per year

The density, ρ = $1.25 \ kg/m^3$

The wind blows steadily. So, the K.E. = $(0.5 \dot{m} V^2)$

                                                             $= \dot{m} \times 0.5 V^2$

The power generation is the time rate of the kinetic energy which can be calculated as follows:

Power = $\Delta \ \dot{K.E.} = \dot{m} \frac{V^2}{2}$

Regarding that $\dot m \propto V$. Then,

Power $ \propto V^3$ → Power = constant x $V^3$

Since, $\rho_a$ is constant for both the sites and the area is the same as same winf turbine is used.

For the first site,

Power, $P_1= \text{const.} \times V_1^3$

            $P_1 = \text{const.} \times 343 \ W$

For the second site,

Power, $P_2 = \text{const.} \times V_2^3 \ W$

           $P_2 = \text{const.} \times 1000 \ W$

5 0
3 years ago
A machine raises 20kg of water through a height of 50m in 10secs. What is the power of the machine.​
Tomtit [17]

Answer:

hhahhhwghwhwhwhwjwnwjnnnnwnwwnw

Explanation:

jwkwkkwoiwiwiwiwiwowwiwowowiiiiwuuwuwgeevehehsvhsvwhbhhehehwgjjwhwhjwjqwjjuuuwi####!\\\\e

5 0
3 years ago
The statement that is NOT true about the concept of a boundary layer on an object is: a. the Reynolds number is greater than uni
Ilya [14]

Answer:

Option E

Explanation:

All the given statements are true except the velocity gradients normal to the flow direction are small since these are not normally small. It's true that viscous effects are present only inside the boundary layer and the fluid velocity equals the free stream velocity at the edge of the boundary layer. Moreover, Reynolds number is greater than unity and the fluid velocity is zero at the surface of the object.

5 0
3 years ago
Ethylene glycol, the ingredient in antifreeze, does not cause health problems because it is a clear liquid.
netineya [11]
B. false

Explanation: because it is
5 0
3 years ago
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