Explanation:
I'm not exactly a master at coding, but I'm pretty sure that:
The farmer will remove dirt as long as there is a pile, then stop when the pile is done.
La altura es de 169.4 metros.
Dado que las dos torres que sostienen un puente colgante tienen una separación de 240m y una altura de 110m a partir de la carretera, si el cable tensor más corto mide 10m, para determinar cuál es altura de un cable que se encuentra a 100m de distancia del centro se debe realizar los siguientes cálculos, aplicando la ecuación parabólica:
- (240)² = 4P x (110-10)
- 57600 = 4P x 100
- 57600 = 400P
- 57600/400 = P
- 144 = P
- 200 x 200 = 4 x 144 x (Altura - 100)
- 40000 = 576Altura - 57600
- 40000 + 57600 / 576 = Altura
-
169.4 metros = Altura
Por lo tanto, la altura es de 169.4 metros.
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Answer:
A)
- Q ( kw ) for vapor = -1258.05 kw
- Q ( kw ) for liquid = -1146.3 kw
B )
- Q ( kj ) for vapor = -1258.05 kJ
- Q ( KJ ) for liquid = - 1146.3 KJ
Explanation:
Given data :
45.00 % mole of methane
55.00 % of ethane
attached below is a detailed solution
A) calculate - Q(kw)
- Q ( kw ) for vapor = -1258.05 kw
- Q ( kw ) for liquid = -1146.3 kw
B ) calculate - Q ( KJ )
- Q ( kj ) for vapor = -1258.05 kJ
- Q ( KJ ) for liquid = - 1146.3 KJ
since combustion takes place in a constant-volume batch reactor
Answer:
30 mm is the minimum thickness that must be applied.
Explanation:
Given the data in the question;
Using Fourier's equation. the heat rate is
q = kA(ΔT/Δx)
where
A is the surface area, we must consider all surfaces through which the heat can dissipate through
i.e 2×2 for one wall gives you 4m²,
there are 5 walls, so we will have 20m² for surface area.
k is thermal conductivity of the styrofoam ( 0.030 W/m K)
q is the heat loss (500 W )
ΔT is the Temperature difference ( 35 - 10) = 25°C
Δx = ?
So we substitute
500 = (0.030)(20)(25/Δx)
500 = 0.6 (25/Δx)
500 = 15 / Δx
Δx = 15 / 500
Δx = 0.03 m = 30 mm
Therefore, 30 mm is the minimum thickness that must be applied.
Answer:
i) Heat transfer coefficient (h) = 7 w/m²k
ii) Heat transfer per meter width of wall
= h x L x 1 x (Ts - T₆₀)
= 7 x 0.3048 x (505.4 - 322) = 414.747 w/m
Explanation:
see attached image