1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Inessa05 [86]
3 years ago
12

As described in "A Note About Bacterial Reproduction -- and the "Culture Bias,"" the organism Epulopisciumdoes not divide by bin

ary fission. Rather, each cell increases in sizeand divides to produce multiple daughter cells that are held within the original cell well.After lysis, those daughters are released to repeat the process. Assuming Epulopisciumcould be grown in pure culture in the laboratory in broth and on solid media (it currently cannot), which method would be best for measuring the increase in biomass during growth?Select one:a. Turbidity readings from a spectrophotometer; the increase in biomass will directly vary with the turbidity of the culture.
b. The viable plate count; each colony derives from a single cell and the number of coloniesequals the number of cells. c. Direct microscopic count; the experimenter can directly count the number of cells and extrapolate to the biomass.d. Chemostat growth; it will prevent the culture from entering the death phase
Engineering
1 answer:
zloy xaker [14]3 years ago
5 0

Answer:

A

Explanation:

The best method that will yield significantly more accurate result is to use spectrophotometer to read the turbidity of the sample and increase in turbidity is associated with increase biomass.

You might be interested in
WHAT PARTS OF THE BRAKE LAMP SYSTEM CAN FAIL? DESCRIBE HOW?<br> Help me ASAP please
adell [148]

Answer:

Explanation:

Brake systems are most likely to fail at the ends.  One of the most common problems is a trailer lighting splitter is left on. With time and usage, the fuse can blow interrupting the signal path from the switch to the bulb.

Answered by the <u><em>ONE </em></u>& <u><em>ONLY</em></u> <u><em>#QUEEN aka #DRIPPQUEENMO</em></u>

<u><em>HOPE THIS HELPED!!!</em></u>

5 0
3 years ago
Air enters a compressor at 100 kPa and 25 ⁰C. It is compressed to 2 MPa and exits the compressor at 540 K. The compressor is at
AysviL [449]

Answer:

(a) The reversible work is 207 kJ/kg

(b) The irreversibility rate is -38.39 kJ/kg

Explanation:

State1 : p1 = 100kpa, T1= 25+273 =298k

From air table, h1 =298.18 kJ/kg, s10= 1.69528 kJ/kgK

State 2a:p2=2mpa,t2=540k (actual condition 2a)

h2a= 544.35 kJ/kg,s2a0=2.29906

actual work input to the compressor =wout=h1-h2+Qin

=298.18-544.35+(-150)kJ/kg(- sign indicate heat loss)

=(-246.17)kJ/kg(-ve sign indicates the work is given into the system

a) Reversible work= Win actual - any irreversiblities present

                             =246.17 + irreversibilty

b) irreversibility = T0(Entopy generation Sgen) for air, Sgen

                         =s20-s10-Rln(p2/p1), T0=250C

                         =(25+273)(s2a0-s10-Rlnp2/p1+Qout/Tsurr)

    = 298x[(2.29906-1.69528-0.287kJ/kgK xln(2000kpa/100) + 150 /298]

  = -38.39 kJ/kg

a)Reversible work = Win actual -any irreversiblities present                  

                           =246.17 + irreversibilty

                           =246.17+-38.39

                          =207 kJ/kg

8 0
3 years ago
-Draw the FBD
schepotkina [342]

Answer: whats the question

Explanation:

7 0
3 years ago
If a pendulum is 10m long, (a) what is the natural frequency and the period of vibration on the earth, where the free-fall accel
suter [353]

Answer:

(a) Natural frequency = 0.99 rad/sec (b) 0.4086 rad/sec

Explanation:

We have given length of pendulum = 10 m

(a) Acceleration due to gravity =9.81m/sec^2

Time period of pendulum is given by T=2\pi\sqrt{\frac{L}{g}}, L is length of pendulum and g is acceleration due to gravity

So T=2\pi\sqrt{\frac{L}{g}}=2\times 3.14\times \sqrt{\frac{10}{9.81}}=6.34sec

Natural frequency is given by \omega =\frac{2\pi }{T}=\frac{2\times 3.14}{6.34}=0.99rad/sec

(b) In this case acceleration due to gravity g=1.67m/sec^2

So time period T=2\pi\sqrt{\frac{L}{g}}=2\times 3.14\times \sqrt{\frac{10}{1.67}}=15.3674sec\

Natural frequency \omega =\frac{2\pi }{T}=\frac{2\times 3.14}{15.36}=0.4086rad/sec

5 0
3 years ago
Help asap 9) A poorly tied down blimp falls over in a field. If the blimp exerts a downward force of 4000 N over an area
kari74 [83]

Answer:

Pressure = 16\ pa

Explanation:

Given

Force = 4000N

Area = 250m^2

Required

Determine the pressure

Pressure is calculated using:

Pressure = \frac{Force}{Area}

Substitute values for Force and Area

Pressure = \frac{4000N}{250m^2}

Pressure = 16N/m^2

Change units

Pressure = 16\ pa

6 0
3 years ago
Other questions:
  • WILL GIVE BRAINLIEST
    11·1 answer
  • Smoke rises from a chimney on a day with variable winds and produces a visible pattern. Does this pattern represent a pathline o
    14·1 answer
  • What is the weight density of a 2.24 in diameter titanium sphere that weights 0.82 lb?
    12·1 answer
  • The fine for passing a stopped school bus illegally on the right is
    14·1 answer
  • True or False? Early engineers used a trial-and­error approach, rather than mathematical and scientific principles when solving
    14·1 answer
  • Which is a reason that teen might choose to focus on a friendship and not a romantic relationship
    13·2 answers
  • Is it possible that two types of dislocation coexist. a)-True b)- False
    14·1 answer
  • A 20 mm diameter rod made of ductile material with a yield strength of 350 MN/m2 is subjected to a torque of 100 N.m, and a bend
    8·1 answer
  • 40 = 6(X^2) / 4 (tan(180/6)) solve for X
    12·1 answer
  • A bridge foundation has a nominal load capacity of 1700kN. If the resistance factor for this foundation is 0.65, what is the ult
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!