Answer:
a) the flow under full capacity is q₂= 1.334 ft³/s
b) the velocity would be v= 3.793 ft/s
Explanation:
a) Since the pipe has 8 inches in diameter but 4 are covered with water flow ( half of a circle in area=A₁) , q₁=0.662 ft³/s then
q₁=A₁*v
then for the same velocity v but area A₂=2*A₁
flow under full capacity= q₂ = A₂*v= 2*A₁*v= 2*q₁=2*0.662 ft³/s= 1.334 ft³/s
b) when flowing at a depth of 4 inches
A₁= (1/2)*(π*D²/4) = π* (1/8)*(8 in)² = 8π in² * (1 ft²/ 144 in²) = π/18 ft² = 0.1745 ft²
then
v=q₁/A₁ = 0.662 ft³/s/0.1745 ft²= 3.793 ft/s
v= 3.793 ft/s
Answer: Apply battery-terminal grease to the terminals to help prevent corrosion. It's available at any auto parts store and usually comes in a little ketchup-like packet. Another great option is AMSOIL Heavy-Duty Metal Protector. It creates a protective coating on terminals that wards off corrosion.
Explanation:
Answer: b) False
Explanation:Ceramic is brittle in nature therefore it has a tendency that it is strong during the compression and it tends to be weak during the high tensile forces. While the tensile forces are applied , ceramics are not able to yield the stress and cause breakage of the material due to high tension but does not face any fault during the compression.
Answer:
improper imput validation
Explanation:
Answer:
Tire rotation is the least likely cause of tire wear. So, the option D is correct.
Explanation:
Step1
Under-inflation is the process of tire failure under low pressure. This contributes the wear on tire.
Step2
On breaking, kinetic energy changes to heat energy because of rubbing of tire. So, rubbing action increases the wear on the tire.
Step3
Acceleration on the vehicle increases the rubbing action as well as the wear and tear on the tire. So, acceleration is an also a major cause of tire wear.
Step4
Tire rotation has least amount of wear and tear due to no rubbing action. It has less amount surface contact with the surface in rotation.
Thus, tire rotation is the least likely cause of tire wear. So, the option D is correct.