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MaRussiya [10]
3 years ago
12

What are common features of both the MMPI-2 and CPI? Select all that apply.

Physics
1 answer:
Amiraneli [1.4K]3 years ago
8 0

Answer:     D

Both MMPI-2 and CPI check for serious personality disorders.

MMPI - 2

MMPI - 2 stands for Minnesota Multiphasic Personality Inventory -2. It is the most widely used psychometric test to measure adult psychopathology. MMPI-2 differentiates people with hypochondriasis from normal one. MMPI-2 is able to detect unconsciously somatizing or consciously malingering in patients.

CPI

CPI stands for california psychological inventory. It is a self report inventory created by Harrision G. This test used to test the people, which are 13 years and older. It takes 40 minutes to complete the test. CPI works on "folk-concepts" which means an ordinary people can use it to describe other people around him.    

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x = 2.33 R from the center of mass of the smallest sphere.

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Due to the symmetry of the spheres, the center of mass of any of them, is located just in the center of the sphere.

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In this case, we need to get the coordinates of the center of mass of each sphere:

If we place the spheres in such a way that the center of the first sphere has the x-coordinate equal to its radius (so it is just touching the origin), we will have:

x₁ = 2*R

For the second sphere, the center will be located at a distance equal to the diameter of  the first sphere plus its own radius, as follows:

x₂ = 4*R + R = 5*R

Finally, for the third sphere, the center will be located at a distance equal to the diameter of  the first sphere, plus the diameter of the second sphere,  plus its own radius, as follows:

x₃ = 4*R + 2*R + 3*R = 9*R

We can calculate the mass of each sphere (assuming that all are from the same material, with a constant density), as the product of the density and the volume:

m = ρ*V

For a sphere, the volume can be calculated as follows:

\frac{4}{3} *\pi *(r)^{3}

So, we can calculate the masses of the spheres, as follows:

m₁ = ρ*\frac{4}{3} *\pi *(2r)^{3}

m₂ = ρ*\frac{4}{3} *\pi *(r)^{3}

m₃ = ρ*\frac{4}{3} *\pi *(3r)^{3}

The total mass can be calculated as follows:

M= ρ*\frac{4}{3} *\pi * (8*r³ + r³ + 27*r³) =ρ*\frac{4}{3} *\pi * 36*r³

Replacing by the values, and simplifying common terms, we can calculate the x-coordinate of the center of mass of the system as follows:

Xcm = \frac{m1*x1+m2*x2+m3*x3}{m1+m2+3}

Xcm = \frac{(8*R^{3} *2*R)+(R^{3}*(5*R))+27*R^{3}*(9*R))}{36*R^{3} }=\frac{264*R^{4} x}{36*R^{3}} = 7.33 R

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d = 7.33*R - 5*R = 2.33 R

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