Answer B is the correct pair.
Answer:
coal tar is one of the product of coal
c.magnetic induction hope this helps
What is the kinetic energy of the system after the collision?
![K_f=\frac{3}{2} \frac{m^{2}v_i^{2} }{(M+3m)}](https://tex.z-dn.net/?f=K_f%3D%5Cfrac%7B3%7D%7B2%7D%20%5Cfrac%7Bm%5E%7B2%7Dv_i%5E%7B2%7D%20%20%7D%7B%28M%2B3m%29%7D)
How this is calculated?
Given:
Initial speed=![v_i](https://tex.z-dn.net/?f=v_i)
mass of rod=M
Let, Initial kinetic energy =![K_i](https://tex.z-dn.net/?f=K_i)
Final kinetic energy=![K_f](https://tex.z-dn.net/?f=K_f)
Moment of inertia =I
What is the moment of inertia?
![I=(I_p)_0+(I_{rod})_0\\I=m(\frac{d}{2})^{2} +\frac{Md^{2} }{12} \\I=\frac{(M+3m)d^{2} }{12}](https://tex.z-dn.net/?f=I%3D%28I_p%29_0%2B%28I_%7Brod%7D%29_0%5C%5CI%3Dm%28%5Cfrac%7Bd%7D%7B2%7D%29%5E%7B2%7D%20%20%2B%5Cfrac%7BMd%5E%7B2%7D%20%7D%7B12%7D%20%5C%5CI%3D%5Cfrac%7B%28M%2B3m%29d%5E%7B2%7D%20%7D%7B12%7D)
What is the angular momentum?
By conservation of angular momentum,
![L_i=L_f](https://tex.z-dn.net/?f=L_i%3DL_f)
![mv_i\frac{d}{2}=\frac{(M+3m)d^{2}\omega }{12} \\\omega=\frac{6mv_i^{2} }{d(M+3m)}](https://tex.z-dn.net/?f=mv_i%5Cfrac%7Bd%7D%7B2%7D%3D%5Cfrac%7B%28M%2B3m%29d%5E%7B2%7D%5Comega%20%7D%7B12%7D%20%20%5C%5C%5Comega%3D%5Cfrac%7B6mv_i%5E%7B2%7D%20%7D%7Bd%28M%2B3m%29%7D)
We know that, the final kinetic energy is given by,
![K_f=I\omega^{2}\\K_f=\frac{1}{2} *\frac{(M+3m)d^{2} }{12} *\frac{36m^{2}v_i^{2}}{d^{2}(M+3m)^{2}}\\ K_f=\frac{3}{2} \frac{m^{2}v_i^{2} }{(M+3m)}](https://tex.z-dn.net/?f=K_f%3DI%5Comega%5E%7B2%7D%5C%5CK_f%3D%5Cfrac%7B1%7D%7B2%7D%20%2A%5Cfrac%7B%28M%2B3m%29d%5E%7B2%7D%20%7D%7B12%7D%20%2A%5Cfrac%7B36m%5E%7B2%7Dv_i%5E%7B2%7D%7D%7Bd%5E%7B2%7D%28M%2B3m%29%5E%7B2%7D%7D%5C%5C%20K_f%3D%5Cfrac%7B3%7D%7B2%7D%20%5Cfrac%7Bm%5E%7B2%7Dv_i%5E%7B2%7D%20%20%7D%7B%28M%2B3m%29%7D)
What is the kinetic energy?
- In physics, the kinetic energy of an object is the energy that it possesses due to its motion.
- It is defined as the work needed to accelerate a body of a given mass from rest to its stated velocity.
- Having gained this energy during its acceleration, the body maintains this kinetic energy unless its speed changes.
To know more about kinetic energy, refer:
brainly.com/question/114210
#SPJ4
Answer:
The value is ![a_t = 2.42 \ m/s^2](https://tex.z-dn.net/?f=a_t%20%3D%20%202.42%20%5C%20%20m%2Fs%5E2)
Explanation:
From the question we are told that
The radius of the tires is ![r = 0.22 \ m](https://tex.z-dn.net/?f=r%20%3D%20%200.22%20%5C%20%20m)
The angular acceleration is ![\alpha = 11.0 \ rad/s^2](https://tex.z-dn.net/?f=%5Calpha%20%20%3D%20%2011.0%20%5C%20rad%2Fs%5E2)
Generally the linear acceleration is mathematically represented as
![a_t = r * \alpha](https://tex.z-dn.net/?f=a_t%20%3D%20%20r%20%2A%20%20%5Calpha)
=> ![a_t = 0.22 * 11](https://tex.z-dn.net/?f=a_t%20%3D%20%200.22%20%20%2A%20%2011)
=> ![a_t = 2.42 \ m/s^2](https://tex.z-dn.net/?f=a_t%20%3D%20%202.42%20%5C%20%20m%2Fs%5E2)