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Stells [14]
3 years ago
13

Why is lithium used in the body?

Chemistry
1 answer:
Veronika [31]3 years ago
8 0

Answer:

Lithium is used to treat mania that is part of bipolar disorder (manic-depressive illness). It is also used on a daily basis to reduce the frequency and severity of manic episodes.

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Boyle's Law represents the relationship of volume as pressure changes. The constants of Boyle's Law are:
Aleksandr [31]

Answer:

d. Temperature and number of molecules of gas  

Step-by-step explanation:

Boyle's Law states, "The volume of a fixed mass of a gas is inversely proportional to the pressure if the temperature remains constant."

Let's examine the words.

"… volume…is inversely proportional to the pressure …" This means that volume and pressure are the <em>variables</em>.

"… fixed mass of a gas …" means that the number of molecules is constant.

"… temperature remains constant" speaks for itself.

a, c, and e are <em>wrong</em>, because pressure is a variable.

b is <em>wrong</em>, because volume is a variable.

5 0
3 years ago
If a substance has a temperature of 273 kelvins, what is its temperature in degrees celsius?
kipiarov [429]
It is at 0 degrees Celsius
5 0
3 years ago
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kirill [66]
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8 0
2 years ago
Calculate the hydronium ion concentration in an aqueous solution with a ph of 9.85 at 25°c.
UkoKoshka [18]

Answer:

1.41 × 10⁻¹⁰ M

Explanation:

We have a solution with a pH of 9.85 at 25 °C. We can calculate the concentration of H⁺ using the following expression.

pH = -log [H⁺]

[H⁺] = antilog -pH

[H⁺] = antilog -9.85

[H⁺] = 1.41 × 10⁻¹⁰ M

H⁺ is usually associated with water molecules forming hydronium ions.

H⁺ + H₂O → H₃O⁺

Then, the concentration of H₃O⁺ ions is 1.41 × 10⁻¹⁰ M.

8 0
3 years ago
Read 2 more answers
A solid powder is known to be a mixture of NaCl and Na2CO3, but the relative amounts of each compound in the sample are unknown.
AveGali [126]

Answer:

Concentration of sodium carbonate in the solution before the addition of HCl is 0.004881 mol/L.

Explanation:

Na_2CO_3(aq) +2 HCl(aq)\rightarrow 2NaCl(aq) + H_2O(l)+CO_2(g)

Molarity of HCl solution = 0.1174 M

Volume of HCl solution = 83.15 mL = 0.08315 L

Moles of HCl = n

molarity=\frac{moles}{Volume (L)}

0.1174 M=\frac{n}{0.08315 L}

n=0.1174 M\times 0.08315 L=0.009762 mol

According to reaction , 2 moles of HCl reacts with 1 mole of sodium carbonate.

Then 0.009762 mol of HCl will recat with:

\frac{1}{2}\times 0.009762 mol=0.004881 mol

Moles of Sodium carbonate = 0.004881 mol

Volume of the sodium carbonate containing solution taken = 1L

Concentration of sodium carbonate in the solution before the addition of HCl:

[Na_2CO_3]=\frac{0.004881 mol}{1 L}=0.004881 mol/L

4 0
3 years ago
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