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Nonamiya [84]
3 years ago
8

True or False: Both molecules and compounds are pure substances.

Chemistry
2 answers:
Solnce55 [7]3 years ago
4 0

Answer:

False

Explanation:

Hope this helps!

WARRIOR [948]3 years ago
3 0

Answer:

True

Explanation:

It's because both compounds and elements are considered pure substances and a molecules is considered an element.

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When aqueous solutions of Na2SO4 and Pb(NO3)2 are mixed, PbSO4 precipitates. Calculate the mass of PbSO4 formed when 1.25 L of 0
neonofarm [45]

Answer:

The mass of PbSO4 formed 15.163 gram

Explanation:

mole of Pb(NO₃)₂ = 1.25 x 0.05 = 0.0625

mole of Na₂SO₄ = 2 x 0.025 = 0.05

                                      Pb(NO₃)₂ + Na₂SO₄ → PbSO₄ + 2 NaNO₃

( Mole/Stoichiometry )    \frac{0.0625}{1}           \frac{0.05}{1}

                                     = 0.0625     = 0.05

From  (Mole/ Stoichiometry ) we can conclude that Na₂SO₄ is limiting reagent.

Mass of PbSO₄ precipitate = 0.05 x Molecular mass of PbSO₄

                                            = 0.05 x 303.26 g

                                            = 15.163 g

7 0
3 years ago
Pa help po thanks! I need the answer ASAP
Korolek [52]

The object and description that matches is Object 2 and T.

Object 1 has no matching description.

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A Fish aquarium filter is a filter whose function is to clean the water of debris, removes the toxic buildup of ammonia and nitrates, and aerates the water so that fish can in a conducive environment and breathe properly

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6 0
2 years ago
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When acids react with water, ions are released which then combine with water molecules to form .
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When acids react with water, H ions are released which then combine with water molecules to form H₃O⁺
7 0
3 years ago
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Silver metal can be prepared by reducing its nitrate, AgNO3 with copper according to the following equation:
Lerok [7]

%yield = 88.5%

<h3>Further explanation</h3>

Given

Reaction

Cu(s) + 2 AgNO₃(aq) → Cu(NO₃)₂(aq) + 2Ag(s)

Required

The percent yield

Solution

mol AgNO₃(MW=169,87 g/mol) :

= mass : MW

= 127 : 169.87

= 0.748

mol Ag from equation :

= 2/2 x mol AgNO₃

= 2/2 x 0.748

= 0.748

Mass Ag (theoretical) :

= mol x Ar Ag

= 0.748 x 108

= 80.784

% yield = (actual/theoretical) x 100%

%yield = 71.5/80.784 x 100%

<em>%yield = 88.5%</em>

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