<u>Answer:</u> The edge length of the unit cell is 0.461 nm
<u>Explanation:</u>
We are given:
Atomic radius of iridium = 0.163 nm
To calculate the edge length, we use the relation between the radius and edge length for FCC lattice:

Putting values in above equation, we get:

Hence, the edge length of the unit cell is 0.461 nm
Answer:

Explanation:
Mole ratio


Moles of CO₂

Use formula to find mass

Relative molecular mass of CO₂ = 12 + 16 × 2 = 44


Answer:
25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2
Explanation:
The balanced equation is
Mg3N2 + 6H2O -> 3Mg(OH)2 + 2NH3
Molecular weight of magnesium nitride = 100.9494 g/mol
Molecular weight of magnesium hydroxide = 58.3197 g/mol
one mole of Mg3N2 produces three moles of 3Mg(OH)2
100.9494 g/mol of Mg3N2 produces 3* 58.3197 g/mol of Mg(OH)2
1 gram of Mg3N2 produces
grams of Mg(OH)2
Or 1.733 grams of Mg(OH)2 will be produced by 1 gram of Mg3N2
25 grams of Mg(OH)2 will be produced by 14.424 gram of Mg3N2
Solution here,
Volume(V)=67.4 L
Pressure(P)=1 atm
Temperature(T)=(0+273)K=273K
Universal gas constant(R)=0.0821 L.atm.mol^-1K^-1
No. of moles(n)=?
Now,
PV=nRT
or, 1×67.4=n×0.0821×273
or, 67.4=22.4n
or, n=67.4/22.4
or, n=3
therefore, required no. of mole is 3.