Molar mass of LiBr ( lithium bromide ) = <span>86.845 g/mol
</span><span>Amount of calculation to moles of lithium bromide (LiBr)
86.845 g ------------- 1 mole
100 g ----------------- ?
n = m / M
n = 100 / 86.845
n = 1.1514 moles of LiBr
V ---------------------1.1514 moles
1 L -------------------- 4 M
1.1514 * 1 / 4
V = 1151.4 / 4
V = 0,28785 L
hope this helps!
hope this helps !</span>
<span>During an experiment, given that other elements that make up the compound are identified, an unknown element x can easily make separate if certain properties of that unknown element is exhibited in the experiment. So, the first thing to do would be to identify the compound, identify and isolate all the knowns and one can test to see the properties which the unknown element is giving and make a reasonable deduction from that.For example if we were testing for the presence of water in Copper(II) sulfate . if water is in the sample that we were testing for, we will see that the sample will turn blue because of the presence of water</span>
[H₃O⁺]=4.4 x 10⁻⁴
pH=3.357
[OH⁻] = 2.28 x 10⁻¹¹
<h3>Further explanation</h3>
Given
HNO3 concentration = 0.00044 M
Required
[H3O+],[OH-] and the pH
Solution
HNO₃ = strong acid
HNO₃ ⇒ H₃O⁺ + NO₃⁻
[H₃O⁺]=[HNO₃]=4.4 x 10⁻⁴
For strong acid pH=-log[H₃O⁺]
pH=-log 4.4 x 10⁻⁴ = 4-log 4.4 =3.357
pOH+pH=pKw
pOH+3.357=14
pOH=14-3.357=10.643
pOH=-log[OH⁻]
![\tt [OH^-]=10^{-10.643}=2.28\times 10^{-11}](https://tex.z-dn.net/?f=%5Ctt%20%5BOH%5E-%5D%3D10%5E%7B-10.643%7D%3D2.28%5Ctimes%2010%5E%7B-11%7D)
F and b because of the movement of the rock layer.
Answer:
When iron wool combusts, it reacts with oxygen from the air to form iron oxide. Iron oxide is a solid, so the oxygen atoms from the air add to the mass on the balance. The balance tips as the iron wool reacts with the oxygen to form solid iron oxide. from.
Explanation:
