Answer:
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Mass of water : 0.45 g
<h3>Further explanation</h3>
Given
1.5 g ethanoic acid
Required
Mass of water
Solution
Reaction
<em>CH₃COOH + NaOH ⇒H₂O + CH₃COONa</em>
mol CH₃COOH(MW=60 g/mol) :
= mass : MW
= 1.5 : 60
= 0.025
mol H₂O from the equation :
= 0.025(mol ratio CH₃COOH : H₂O= 1 : 1)
Mass of water :
= mol x MW water
= 0.025 x 18 g/mol
= 0.45 g
Answer: The molarity of each of the given solutions is:
(a) 1.38 M
(b) 0.94 M
(c) 1.182 M
Explanation:
Molarity is the number of moles of a substance present in liter of a solution.
And, moles is the mass of a substance divided by its molar mass.
(a) Moles of ethanol (molar mass = 46 g/mol) is as follows.

Now, molarity of ethanol solution is as follows.

(b) Moles of sucrose (molar mass = 342.3 g/mol) is as follows.

Now, molarity of sucrose solution is as follows.

(c) Moles of sodium chloride (molar mass = 58.44 g/mol) are as follows.

Now, molarity of sodium chloride solution is as follows.

Thus, we can conclude that the molarity of each of the given solutions is:
(a) 1.38 M
(b) 0.94 M
(c) 1.182 M
Answer:
x=34
y=20
Explanation:
let the first number be 'x'
let the second number be 'y'
Equation 1:-
x + y = 54
Equation 2:-
x = y + 14 (Since one exceeds the other by 14)
Substituting Equation 2 in Equation 1:-
(y + 14) + y = 54
=> y + 14 + y = 54
=> 2y + 14 = 54
=> 2y = 54 - 14
=> 2y = 40
=> y = 40/2
=> y = 20
Now in Equation 1:-
x + y = 54
Substituting y=20,
x + 20 = 54
x = 54 - 20
x = 34