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irinina [24]
3 years ago
5

Durante una determinación de acidez en una muestra contaminada, agregas como indicador fenolftaleina y torno a violeta. ¿Qué sus

tancia utilizarías para titular NaOH o HCI? Y ¿Por qué?
Chemistry
1 answer:
algol133 years ago
6 0

Answer:

HCl, ya que la sustancia es una base que se debe titular con un ácido.

Explanation:

¡Hola!

En este caso, teniendo en cuenta la descripción inicial de la sustancia, la cual se torna violeta cuando se le agrega la fenolftaleína, es posible inderir que esta sustancia es una base con pH básico. Ahora bien, en torno a la especificación de un proceso de titulación, es claro que dicha base debe ser titulada con un ácido, y este caso, con HCl, ácido chlorhídrico, con el fin the alcanzar el punto de equivalencia.

¡Saludos!

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trasher [3.6K]
What kind of solutions?
4 0
3 years ago
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Briefly explain the difference between hard water and soft water.​
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3 years ago
What mass of water would be produced if 1.5 g of ethanoic acid was reacted completely with sodium hydroxide (3 marks)
Zigmanuir [339]

Mass of water : 0.45 g

<h3>Further explanation</h3>

Given

1.5 g ethanoic acid

Required

Mass of water

Solution

Reaction

<em>CH₃COOH + NaOH ⇒H₂O + CH₃COONa</em>

mol CH₃COOH(MW=60 g/mol) :

= mass : MW

= 1.5 : 60

= 0.025

mol H₂O from the equation :

= 0.025(mol ratio CH₃COOH : H₂O= 1 : 1)

Mass of water :

= mol x MW water

= 0.025 x 18 g/mol

= 0.45 g

5 0
3 years ago
Be sure to answer all parts.
MrRissso [65]

Answer: The molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

Explanation:

Molarity is the number of moles of a substance present in liter of a solution.

And, moles is the mass of a substance divided by its molar mass.

(a) Moles of ethanol (molar mass = 46 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{28.5 g}{46 g/mol}\\= 0.619 mol

Now, molarity of ethanol solution is as follows.

Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.619 mol}{4.50 \times 10^{2} \times 10^{-3}L}\\= 1.38 M

(b) Moles of sucrose (molar mass = 342.3 g/mol) is as follows.

Moles = \frac{mass}{molar mass}\\= \frac{21.6 g}{342.3 g/mol}\\= 0.063 mol

Now, molarity of sucrose solution is as follows.

Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.063 mol}{0.067 L}  (1 mL = 0.001 L)\\= 0.94 M

(c) Moles of sodium chloride (molar mass = 58.44 g/mol) are as follows.

Moles = \frac{mass}{molar mass}\\= \frac{6.65 g}{58.44 g/mol}\\= 0.114 mol

Now, molarity of sodium chloride solution is as follows.

Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.114 mol}{0.0962 L}\\= 1.182 M

Thus, we can conclude that the molarity of each of the given solutions is:

(a) 1.38 M

(b) 0.94 M

(c) 1.182 M

4 0
3 years ago
The sum of two numbers is 54 one exceed the other by 14 find the number​
Aneli [31]

Answer:

x=34

y=20

Explanation:

let the first number be 'x'

let the second number be 'y'

Equation 1:-

x + y = 54

Equation 2:-

x = y + 14  (Since one exceeds the other by 14)

Substituting Equation 2 in Equation 1:-

(y + 14) + y = 54

=> y + 14 + y = 54

=> 2y + 14 = 54

=> 2y = 54 - 14

=> 2y = 40

=> y = 40/2

=> y = 20

Now in Equation 1:-

x + y = 54

Substituting y=20,

x + 20 = 54

x = 54 - 20

x = 34

7 0
3 years ago
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