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xz_007 [3.2K]
3 years ago
7

PLEASE HELP ME I WOULD APPRECIATE IT SO MUCH!!!! ILL GIVE BRAINLIEST IF ITS CORRECT!

Chemistry
1 answer:
Mekhanik [1.2K]3 years ago
4 0

Answer:

Graduated cylinder

Measuring cup

Explanation:

Hope this helps!

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Answer:

<h3>Sand cannot mixed on water not float on water .</h3>

<h3>When we mix sand and water , No reaction take place . The sand simply settles down at the bottom of the water container . This is why sand is heavier than water and therefore cannot float in water .</h3>

<h2>Hope this helps you ✌️</h2>
7 0
2 years ago
URGENT!! Can someone please explain this to me?
djverab [1.8K]

Answer:

CH _{4}+ 2O  _{2} → CO _{2} + 2H _{2}O

for the balanced equation

from \: the \: equation \\ 1 \: mole \: of \: methane \: gives \: 1 \: mole \: of \: carbon \: dioxide \\ 7.4 \: moles \: of \: carbon \: dioxide \: will \: be \: given \: by \: (7.4 \times 1)moles \: of \: methane \\  = 7.4\: moles \: of \: methane \\  \\  since \: moles \: of \: oxygen \: double \: those \: of \: methane \\ moles \: of \: oxygen \:  = 7.4\times 2 \\  = 14.8 \: moles \: of \: oxygen

4 0
3 years ago
Part A
katovenus [111]

Answer:1.7

Explanation:

6 0
2 years ago
Which of the following will form a cation
sdas [7]

D) Calcium

hope this helps :)

3 0
3 years ago
Calculate the number of moles of magnesium, chlorine, and oxygen atoms in 4.90 moles of magnesium perchlorate, Mg(ClO4)2.]\
Leviafan [203]

Answer:

 4.90  moles of  Mg(ClO_4)_2   will produce  (9.8) moles of  Cl^{-} ,

                                                    (4.90) moles of Mg^{2+} and

                                                    (39.2) moles of  O^{2-}

Explanation:

From the question we are told that

  The number of moles of  is  n =  4.90  \ mols

The formation reaction of Mg(ClO_4)_2  is

             Mg^{2+} + 2 Cl^{-} + 8O^{2+} \to Mg(ClO_4)_2  

From the reaction we see that

   1 mole of  Mg(ClO_4)_2  is formed by 2 moles of Cl^{-} 1 mole of  Mg^{2+} and 4  O^{2-}

 This implies that

   4.90  moles of  Mg(ClO_4)_2   will produce  (2 * 4.90) moles of  Cl^{-} ,

                                                    (1 * 4.90) moles of Mg^{2+} and

                                                    (8 * 4.90) moles of  O^{2-}

So

  4.90  moles of  Mg(ClO_4)_2   will produce  (9.8) moles of  Cl^{-} ,

                                                    (4.90) moles of Mg^{2+} and

                                                    (39.2) moles of  O^{2-}

                           

4 0
3 years ago
Read 2 more answers
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