NaOH is a strong base and complete dissociation into Na⁺ and OH⁻ ions.
Therefore [NaOH] = [OH⁻]
To calculate the [OH⁻], we can first find the pOH as NaOH is a basic solution.
pH + pOH = 14
Since pH = 11.50
pOH = 14 - 11.50
pOH = 2.50
We can calculate [OH⁻] by knowing pOH
pOH = -log[OH⁻]
[OH⁻] = antilog(-pOH)
[OH⁻] = 3.2 x 10⁻³ M
therefore [NaOH] = 3.2 x 10⁻³ M
Explanation: Outer shell electronic configuration for Group 18 is :
( have 8 electrons in the outer shell)
The electronic configurations for other groups are:
( have 1 electron in the outer shell}
( have 2 electrons in the outer shell)
( have 5 electrons in the outer shell)
( have 6 electrons in the outer shell)
( have 7 electrons in the outer shell)
Comparing the electron configurations of group 18 to other groups.
Group 18 has fully filled outer shell, that is 8 electrons in the outer shell, while others are partially filled.
I'm pretty sure is'd diffusion! Ya know..diffusion and osmosis, hydro-tonic solution, hypertonic solution!
Unstable Isotopes, Source of Thermal Energy, Poses Health Problems.