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lara31 [8.8K]
3 years ago
6

Calcium carbide ( CaC2) reacts with water to produce acetylene (C2H2) as shown in the unbalanced reaction below: CaC2(s)+H2O(g)-

>Ca(OH)2(s)+C2H2(g). How many grams of H2O are required to completely react with 82.4g of CaC2
Chemistry
1 answer:
MaRussiya [10]3 years ago
4 0
Answer:
46.3g H2O

Explanation:
start by balancing it: CaC2(s) + 2H2O(g) -> Ca(OH)2(s) + C2H2(g)

then use factor label method to solve

82.4g CaC2 x (1 mol CaC2/64.10g CaC2) x (2 mol H2O/1 mol CaC2) x (18.016g H2O/1 mol H20) = 46.3g H2O
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An aqueous solution of ammonium sulfate is allowed to react with an aqueous solution of calcium nitrate. The net ionic equation
Veseljchak [2.6K]

The complete question is:

An aqueous solution of ammonium sulfate is allowed to react with an aqueous solution of calcium nitrate.

The net ionic equation contains which of the following species (when balanced in standard form)?

a. 2NO3-(aq)

b. Ca2+(aq)

Answer:

b. Ca2+(aq)

Ca2+ (aq) + SO4^2-(aq) --------------> CaSO4(s)

Explanation:

The overall ionic equation is:

Ca2+(aq) + 2NO3-(aq) + 2NH4+(aq) + SO4^2-(aq) ---------------> CaSO4(s) + 2NH4NO3(aq)

The NO3- and NH4+ are spectator ions as they do not participate in the formation of the precipitate CaSO4.

The net ionic equation is:

Ca2+ (aq) + SO4^2-(aq) --------------> CaSO4(s)

The spectator ions form the soluble ammonium trioxonitrate V

4 0
3 years ago
Please help I will give brainliest!
aleksklad [387]
I believe it’s the 3rd option
6 0
3 years ago
Name the phase change in each of these events: (a) A diamond film forms on a surface from gaseous carbon atoms in a vacuum.
labwork [276]

The phase shift in the events is called deposition.

In a vacuum, carbon atoms in gas form a diamond coating on a surface. The conversion of gas phase to solid phase is a part of the described process. As a result, this procedure is known as deposition.

A deposition is a process by which a solid substance is formed from a gaseous one. Bypassing the transitional liquid state, a gaseous substance is deposited in its place (often as crystals). Deposition happens, for instance, when airborne water vapor quickly freezes into ice, as when frost develops.

<h3>How does deposition occur?</h3>

Whether the eroding agent is gravity, ice, water, waves, or wind, deposition happens when it runs out of energy and can no longer support the burden of the degraded material. Gravity or, in the case of wind, the Sun, provides the energy that the erosion agents can use.

Learn more about deposition: brainly.com/question/12081679

#SPJ4

4 0
1 year ago
50cm3 of 1 mol/dm3 HCl at 30°C was mixed with 50cm3 of 1mol/dm3 NaOH at 30°C in a styrofoam calorimeter. The temperature of the
trapecia [35]

Answer:

-21 kJ·mol⁻¹  

Explanation:

Data:

                    H₃O⁺ +  OH⁻ ⟶ 2H₂O

       V/mL:    50         50  

c/mol·dm⁻³:   1.0         1.0

     

ΔT = 4.5 °C  

       C = 4.184 J·°C⁻¹g⁻¹

C_cal = 50 J·°C⁻¹

Calculations:

(a) Moles of acid

\text{Moles of acid} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}\\\\\text{Moles of base} = \text{0.050 dm}^{3} \times \dfrac{\text{1.0 mol}}{\text{1 dm}^{3}} = \text{0.050 mol}

So, we have 0.050 mol of reaction

(b) Volume of solution

V = 50 dm³ + 50 dm³ = 100 dm³

(c) Mass of solution

\text{Mass of solution} = \text{100 dm}^{3} \times \dfrac{\text{1.00 g}}{\text{1 dm}^{3}} = \text{100 g}

(d) Calorimetry

There are three energy flows in this reaction.

q₁ = heat from reaction

q₂ = heat to warm the water

q₃ = heat to warm the calorimeter

q₁ + q₂ + q₃ = 0

     nΔH   +         mCΔT       + C_calΔT = 0

0.050ΔH + 100×4.184×4.5 +   50×4.5  = 0

0.050ΔH +          1883        +      225    = 0

                                  0.050ΔH + 2108 = 0

                                              0.050ΔH = -2108

                                                        ΔH = -2108/0.0500

                                                              = -42 000 J/mol

                                                              = -42 kJ/mol

This is the heat of reaction for the formation of 2 mol of water

The heat of reaction for the formation of mol of water is -21 kJ·mol⁻¹.

5 0
3 years ago
Change for a liquid state to a solid state is known as what phase change?
NeTakaya

Answer:

B. To change from a liquid state to a solid state is called Freezing

5 0
3 years ago
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