The complete question is:
An aqueous solution of ammonium sulfate is allowed to react with an aqueous solution of calcium nitrate.
The net ionic equation contains which of the following species (when balanced in standard form)?
a. 2NO3-(aq)
b. Ca2+(aq)
Answer:
b. Ca2+(aq)
Ca2+ (aq) + SO4^2-(aq) --------------> CaSO4(s)
Explanation:
The overall ionic equation is:
Ca2+(aq) + 2NO3-(aq) + 2NH4+(aq) + SO4^2-(aq) ---------------> CaSO4(s) + 2NH4NO3(aq)
The NO3- and NH4+ are spectator ions as they do not participate in the formation of the precipitate CaSO4.
The net ionic equation is:
Ca2+ (aq) + SO4^2-(aq) --------------> CaSO4(s)
The spectator ions form the soluble ammonium trioxonitrate V
I believe it’s the 3rd option
The phase shift in the events is called deposition.
In a vacuum, carbon atoms in gas form a diamond coating on a surface. The conversion of gas phase to solid phase is a part of the described process. As a result, this procedure is known as deposition.
A deposition is a process by which a solid substance is formed from a gaseous one. Bypassing the transitional liquid state, a gaseous substance is deposited in its place (often as crystals). Deposition happens, for instance, when airborne water vapor quickly freezes into ice, as when frost develops.
<h3>
How does deposition occur?</h3>
Whether the eroding agent is gravity, ice, water, waves, or wind, deposition happens when it runs out of energy and can no longer support the burden of the degraded material. Gravity or, in the case of wind, the Sun, provides the energy that the erosion agents can use.
Learn more about deposition: brainly.com/question/12081679
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Answer:
-21 kJ·mol⁻¹
Explanation:
Data:
H₃O⁺ + OH⁻ ⟶ 2H₂O
V/mL: 50 50
c/mol·dm⁻³: 1.0 1.0
ΔT = 4.5 °C
C = 4.184 J·°C⁻¹g⁻¹
C_cal = 50 J·°C⁻¹
Calculations:
(a) Moles of acid
So, we have 0.050 mol of reaction
(b) Volume of solution
V = 50 dm³ + 50 dm³ = 100 dm³
(c) Mass of solution
(d) Calorimetry
There are three energy flows in this reaction.
q₁ = heat from reaction
q₂ = heat to warm the water
q₃ = heat to warm the calorimeter
q₁ + q₂ + q₃ = 0
nΔH + mCΔT + C_calΔT = 0
0.050ΔH + 100×4.184×4.5 + 50×4.5 = 0
0.050ΔH + 1883 + 225 = 0
0.050ΔH + 2108 = 0
0.050ΔH = -2108
ΔH = -2108/0.0500
= -42 000 J/mol
= -42 kJ/mol
This is the heat of reaction for the formation of 2 mol of water
The heat of reaction for the formation of mol of water is -21 kJ·mol⁻¹.
Answer:
B. To change from a liquid state to a solid state is called Freezing
