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klasskru [66]
3 years ago
7

Please help with this question!

Chemistry
1 answer:
Alex17521 [72]3 years ago
6 0

Answer:

A) potential energy is stored energy. Kenetic energy is energy of motion.

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Can someone help me pls
Inessa [10]

Answer:

The heat would flow from the hot solid to the cool solid until all temperatures are near equal.

4 0
3 years ago
Spaghetti takes about 9 minutes to cook at sea level, but about 14 minutes in the mountains. Why do you think this is so?
S_A_V [24]

At high altitudes, air pressure is lower. That means that the boiling point of water is lower as well (lower air pressure means that water molecules need less energy to turn into gas), and because the water is boiling at a lower temperature it takes longer for it to cook the pasta.

hope this helps!

(:

8 0
3 years ago
Read 2 more answers
Use the graph to calculate the instantaneous rate of formation of HBr at 50 s
Lina20 [59]

<u>Answer:</u> The instantaneous rate of formation of HBr at 50 s is 1.4\times 10^{-2}M/s

<u>Explanation:</u>

From the graph,

Initial rate of the Br_2 = 1.0 M

Time when the concentration of Br_2 is 0.5 M (half the concentration ) = 60 sec

For first order reaction:

Calculating rate constant for first order reaction using half life:

t_{1/2}=\frac{0.693}{k} .....(1)

t_{1/2} = half life period = 60 s

k = rate constant = ?

Putting values in equation 1:

k=\frac{0.693}{60s}\\\\k=0.01155s^{-1}

For the given chemical reaction:

H_2(g)+Br_2(g)\rightarrow 2HBr(g)

Rate of the reaction = -\frac{\Delta [Br_2]}{\Delta t}=\frac{1}{2}\frac{\Delta [HBr]}{\Delta t}

Negative sign represents the disappearance of the reactants

From the above expression:

k[Br_2]=-\frac{\Delta [Br_2]}{\Delta t}=\frac{1}{2}\frac{\Delta [HBr]}{\Delta t}

At 50 seconds, [Br_2]=0.6 M

Plugging values in above expression, we get:

\frac{1}{2}\frac{\Delta [HBr]}{\Delta t}=0.01155\times 0.6\\\\\frac{\Delta [HBr]}{\Delta t}=2\times 0.01155\times 0.6=0.01386=1.4\times 10^{-2}M/s

Hence, the instantaneous rate of formation of HBr at 50 s is 1.4\times 10^{-2}M/s

6 0
3 years ago
Write a balanced equation for the reaction of thermal decomposition of solid mercury (II) oxide (also known as mercuric oxide) i
astra-53 [7]
The balanced equation for the thermal decomposition of liquid mercury is as follow:
2HgO + heat = 2Hg + O2.
This equation means that, two molecules of solid mercury oxide was heated to give two atoms of liquid mercury and one oxygen molecule.<span />
3 0
3 years ago
Are these equations balanced? If not how do I balance them?
wlad13 [49]

Answer:

The answer to your question is given below.

Explanation:

1. CH3COOH(aq) + NaHCO3(s) —> CO2(g) + H2O(l) + Na+(aq) + CH3COO-(aq)

The above equation is balanced since the number of atoms of the different elements present on both sides of the equation are equal.

2. CaCl2 + NaHCO3 —> CO2 + CaCO3 + NaCl + H2O

The above equation can be balance as follow:

There are 2 atoms of Cl on the left side and 1 atom on the right side. It can be balance by putting 2 in front of NaCl as shown below:

CaCl2 + NaHCO3 —> CO2 + CaCO3 + 2NaCl + H2O

Now, there are 2 atoms of Na on the right side and 1 atom on the left side. It can be balance by putting 2 in front of NaHCO3 as shown below:

CaCl2 + 2NaHCO3 —> CO2 + CaCO3 + 2NaCl + H2O

Now the equation is balanced.

3 0
3 years ago
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