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3 years ago

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A baseball is travelling towards a player's bat with a speed of 40.0 m/s. After being hit by the bat, the baseball is travelling

wtih a speed of 45.0 m/s in the opposite direction of the initial velocity. Calculate the impulse imparted to the baseball.

1 answer:

laila [671]3 years ago

3 0

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A large glass marble is added to the displacement can. 20 3 of water overflows into a beaker, and the displacement can now has a

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The density of the glass can be determined using the formula:

Density of the glass = (Mf - Mi)/20 cm³

<h3>What is density?</h3>

Density is defined as the ratio of mass and volume of a substance.

Density = mass/volume

The mass of the glass = Final mass of beaker - initial mass of beaker (Mf - Mi)

The initial mass of the beaker is not given.

Volume of the glass marble = 20 cm³

Density of the glass = (Mf - Mi)/20 cm³

Therefore, the density of the glass is determined from the ratio of the mass and volume of the glass.

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2 years ago

Diamond has an index of refraction of 2.419. What is the critical angle for internal reflection inside a diamond that is in air?

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Answer:

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Explanation:

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sin(∅c) = na/nd

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The action of two forces. One is a forward force of 1157 N provided by traction between the wheels and the road. The other is a

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Complete question

A 2700 kg car accelerates from rest under the action of two forces. one is a forward force of 1157 newtons provided by traction between the wheels and the road. the other is a 902 newton resistive force due to various frictional forces. how far must the car travel for its speed to reach 3.6 meters per second? answer in units of meters.

Answer:

The car must travel 68.94 meters.

Explanation:

First, we are going to find the acceleration of the car using Newton's second Law:

$\sum\overrightarrow{F}=m\overrightarrow{a}$ (1)

with m the mass , a the acceleration and $\sum\overrightarrow{F}$ the net force forces that is:

$(F-f)$ (2)

with F the force provided by traction and f the resistive force:

(2) on (1):

$(F-f)=ma$

solving for a:

$a=\frac{F-f}{m} =\frac{1157N-902N}{2700kg} =0.094\frac{m}{s^{2}}$

Now let's use the Galileo’s kinematic equation

$Vf^{2}=Vo^{2}+2a\varDelta x$ (3)

With Vo te initial velocity that's zero because it started from rest, Vf the final velocity (3.6) and $\varDelta x$ the time took to achieve that velocity, solving (3) for $\varDelta x$ :

$\varDelta x= \frac{Vf^{2}}{2a} = t= \frac{(3.6\frac{m}{s})^2}{2*0.094\frac{m}{s^{2}}}$

$t=68.94 m$

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