1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
umka21 [38]
3 years ago
8

An object moves in one dimensional motion with constant acceleration a = 4.2 m/s^2. At time t = 0 s, the object is at x0 = 3.9 m

and has an initial velocity of v0 = 2.2 m/s. How far will the object move before it achieves a velocity of v = 7.2 m/s? Your answer should be accurate to the nearest 0.1 m.
Physics
1 answer:
solong [7]3 years ago
8 0

Answer:

The object will move to Xfinal = 7.5m

Explanation:

By relating the final velocity of the object and its acceleration, I can obtain the time required to reach this velocity point:

Vf= a × t ⇒ t= (7.2 m/s) / (4.2( m/s^2)) = 1,7143 s

With the equation of the total space traveled and the previously determined time I can obtain the end point of the object on the x-axis:

Xfinal= X0 + /1/2) × a × (t^2) = 3.9m + (1/2) × 4.2( m/s^2) × ((1,7143 s) ^2) =

= 3.9m + 3.6m = 7.5m

You might be interested in
4. O/N 15/P11/Q11
anygoal [31]

Answer:

B) 4500 Pa

Explanation:

As pressure is force per unit area,

P = F/A

It stands to reason that the smallest pressure for a given force is when it is shared by the largest area.

The possible areas are

0.30(0.40) = 0.12 m²

0.30(0.50) = 0.15 m²

0.40(0.50) = 0.20 m²

The pressure when the face with the largest area (0.20 m²) is down is

P = 900 / 0.20 = 4500 N/m² or 4500 Pa

the other possible pressures would be

900/0.15 = 6000 Pa

900/0.12 = 7500 Pa

which are both larger than our solution.

5 0
3 years ago
A tissue box has regular dimensions
vova2212 [387]

Considering the volume of a rectangle, the volume of the tissue box is 3,239.1 cm³.

<h3>What is volume</h3>

Volume is a scalar-type metric quantity that is defined as the extension in three dimensions of a region of space. In other words, the volume corresponds to the space that the shape occupies.

<h3>Volume of a rectangle</h3>

To calculate the volume of a rectangle, it is necessary to multiply its 3 dimensions: length ×width×height. Volume is expressed in cubic units.

<h3>Volume of the tissue box</h3>

In this case, you know:

  • Length: 11.8 cm
  • Width: 12.2 cm
  • Height: 22.5 cm

Replacing in the definition of volume of a rectangle:

Volume of the tissue box= length ×width×height

Volume of the tissue box= 11.8 cm× 12.2 cm× 22.5 cm

Solving:

<u><em>Volume of the tissue box= 3,239.1 cm³</em></u>

Finally, the volume of the tissue box is 3,239.1 cm³.

Learn more about volume:

brainly.com/question/13535768

brainly.com/question/21172800

#SPJ1

5 0
2 years ago
Cells are visualized using light microscopes and electron microscopes. Which statement about microscopes is false. Group of answ
denpristay [2]

Answer:

Light microscopes use light and glass objectives to illuminate and magnify objects

Explanation:

Light microscopes and electron microscopes are used to study cells. The electron microscope has many times more resolving power than the ordinary light microscope. A light microscope contains an objective lens and an eyepiece through which the final image is seen.

Both light and electron microscopes magnifies the image of the object. The magnifying power of an electron microscope is many times that of the light microscope.

4 0
3 years ago
Compare these two collisions of a PE student with a wall.
Stolb23 [73]

1) The variable that is different in the two cases is \Delta t, the duration of the collision

2) The change in momentum is the same in the two cases

3) The impulse is the same in the two cases

4) Case B will experience a greater force

Explanation:

1)

The variable that is different in the two cases is \Delta t, the duration of the collision.

In fact, in the first case the wall is padded: this means that the collision will be "softer" and therefore will last longer, so the duration of the collision, \Delta t, will be larger.

In the second case instead, the wall is unpadded: this means that the collision is "harder" and so it will last less time, therefore the duration of the collision \Delta t will be smaller.

2)

The change in momentum in the two cases is the same.

In fact, the change in momentum is given by:

\Delta p = m(v-u)

where:

m is the mass of the student

u is the initial velocity

v is the final velocity

In both cases, we have:

m = 75 kg

u = 8 m/s

v = 0 (they both comes to rest)

Therefore, the change in momentum is

\Delta p = (75)(0-8)=-600 kg m/s

3)

The impulse in the two cases is the same.

In fact, impulse is defined as the product of force applied, F, and duration of the collision, \Delta t:

J=F \Delta t

However, the force can be rewritten as product of mass (m) and acceleration (a), according to Newton's second law:

F=ma

So the impulse is

J=ma\Delta t

The acceleration can be rewritten as rate of change of velocity:

a=\frac{\Delta v}{\Delta t}

So the impulse becomes

J=m\frac{\Delta v}{\Delta t}\Delta t = m\Delta v

So, the impulse is equal to the change in momentum: and since in the two cases the change in momentum is the same, the impulse is the same as well.

4)

The force in the collision is related to the impulse by

J=F\Delta t

where

J is the impulse

F is the force

\Delta t is the duration of the collision

The equation can be rewritten as

F=\frac{J}{\Delta t}

In the two situations described in the problem (A and B), we already said that the impulse is the same (because the change in momentum is the same). However, in case A (padded wall) the time \Delta t is longer, while in case B (unpadded wall) the time \Delta t is shorter: since the force F is inversely proportional to the duration of the collision, this means that in case B the student will experience a greatest force compared to case A.

Learn more about impulse:

brainly.com/question/9484203

#LearnwithBrainly

3 0
4 years ago
A 1kg box is pushed on a flat surface that is 250m long. The box is initially at rest and then pushed with a constant Net force
sasho [114]

Answer:

C) 50 m/s

Explanation:

With the given information we can calculate the acceleration using the force and mass of the box.

Newton's 2nd Law: F = ma

  • 5 N = 1 kg * a
  • a = 5 m/s²

List out known variables:

  • v₀ = 0 m/s
  • a = 5 m/s²
  • v = ?
  • Δx = 250 m

Looking at the constant acceleration kinematic equations, we see that this one contains all four variables:

  • v² = v₀² + 2aΔx

Substitute known values into the equation and solve for v.

  • v² = (0)² + 2(5)(250)
  • v² = 2500
  • v = 50 m/s

The final velocity of the box is C) 50 m/s.

7 0
3 years ago
Other questions:
  • A laser beam is incident on two slits with a separation of 0.230 mm, and a screen is placed 4.75 m from the slits. If the bright
    13·1 answer
  • Quid pro quo sexual harassment involves offering work benefits in exchange for sexual favors or threatening consequences if the
    6·1 answer
  • Of the eighteen elements in the fourth period, which a. has the largest atomic radius? b. has the smallest first ionization ener
    5·1 answer
  • Using Figure 25-2, determine how Giant stars differ from main sequence stars.
    14·2 answers
  • What should not be used to support a scaffold because they could collapse, sending the structure to the ground?
    13·1 answer
  • If electrons are taken away from an atom, the atom develops a _________ charge.
    12·2 answers
  • Amy gets up from her seat on a train to move closer to the front. Just as she begins to walk forward, the train stops at a stati
    11·2 answers
  • PLEASE HELP
    9·1 answer
  • How is it possible to move man made things​
    5·1 answer
  • Sarah decelerates from 30 to 10m/s over a distance of 5m. What is her acceleration? ​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!