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meriva
3 years ago
9

3. Using the solubility of ionic compounds table and/or the solubility rules,

Chemistry
1 answer:
Klio2033 [76]3 years ago
6 0
Answer:

Sugar, sodium chloride, and hydrophilic proteins
You might be interested in
Use the periodic table to determine the electron configuration for Ca and Pm in noble-gas notation Ca: [Ar]4s2 [Ar]4s1 [Ar]3s2 [
sveta [45]
Answer:

1) Ca: [Ar]4s²
2) Pm: [Xe]6s²4f⁵

Explanation:

1) Ca:

Its atomic number is 20. So it has 20 protons and 20 electrons.

Since it is in the row (period) 4 the noble gas before it is Ar, and the electron configuration is that of Argon whose atomic number is 18.

So, you have two more electrons (20 - 18 = 2) to distribute.

Those two electrons go the the orbital 4s.

Finally, the electron configuration is [Ar] 4s².

2) Pm

The atomic number of Pm is 61, so it has 61 protons and 61 electrons.

Pm is in the row (period) 6. So, the noble gas before Pm is Xe.

The atomic number of Xe is 54.

Therefore, you have to distribute 61 - 54 = 7 electrons on the orbitals 6s and 4f.

The resultant distribution for Pm is: [Xe]6s² 4f⁵.
5 0
3 years ago
Read 2 more answers
Ozone has a molecular formula of O3. If 7.92*1024 atoms of oxygen react to form ozone, how many
prisoha [69]

337.92 moles of Ozone will be produced

1 Oxygen atom is 8 g

1 mole of ozone, O3 = 8 * 3 = 24 g

7.92 * 1024 = 8110.08 g

1 mole = 24 g

? moles = 8110.08 g

? = 337.92 moles


Read more on moles here:

brainly.com/question/15356425

Hope it helps

7 0
2 years ago
Are elements always transparent
Dmitry_Shevchenko [17]

No, the elements are not always transparent.

<u>Explanation:</u>

The elements become transparent when the light passes through those elements. Transparency is caused because of the transmission and the passing of the light waves through these elements.

But the metals do not become transparent even when the light waves pass through these metals. Metals do not become transparent because the refractive index in them is very big.

8 0
3 years ago
phillip morris cigaretteshave 5mg tar and 0.4 mg nicotine per cigarette and 20 cigarettes per pack how many packs of cigarettes
Shalnov [3]

Answer: A solution is made by dissolving 27.8 g of nicotine (Molar Mass = 160 g/mol) in 145 g of cyclohexane (C6H12) to form 142 mL of solution. Calculate the mole fraction of the solute and the molarity, respectively, of this solution.

Explanation:

8 0
3 years ago
Given the following balanced equation, determine the rate of reaction with respect to [Cl2]. If the rate of Cl2 loss is 4.44 × 1
PolarNik [594]

Answer:

8.88 x 10⁻² M/s

Explanation:

The rate  of reaction for:

                    NO(g) + Cl₂ (g) ⇒  2NOCl(g)

is rate = -ΔNO/Δt = -ΔCl2/Δt = 1/2 ΔNOCl/Δt

so  ΔNOCl/Δt = 2 ΔCl2/Δt  = 2  x 4.44 × 10⁻²  M/s = 8.88 x 10⁻² M/s

In general given a reaction

                            aA + bB ⇒ cC + dD

rate = -1/a ΔA/Δt = -1/b ΔB/Δt = 1/c ΔC/Δt = 1/d ΔD/Δt

8 0
3 years ago
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