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lesya692 [45]
3 years ago
10

Forces present on a flying dove

Physics
2 answers:
storchak [24]3 years ago
7 0

Answer:

There are four forces acting on a bird in flight, lift, thrust, drag and gravity (weight). These four forces act in pairs, as shown on the right. If a bird is to fly it must overcome drag and weight by generating a greater force of thrust and lift.

sasho [114]3 years ago
3 0

Refer to attachment for your answer

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sest yourse 1. A pencil lies on the dashboard of a car. a) i) What happens to the pencil when the car suddenly stops? suddenly a
julia-pushkina [17]

Answer:

1. the pencil would have the momentum and would keep going until it hits the windshield. 2. when the car suddenly accelerates, the pencil would be inert and it would move toward the back of the car until a constant speed from the car is reached.

8 0
2 years ago
The “Big Bang” is an example of what type of scientific statement? A. A law B.a hypothesis C. A theory D. An equation
Ugo [173]

Answer:

theory

Explanation:

that's why it's called the Big Bang Theory

6 0
3 years ago
Read 2 more answers
A stone is thrown towards a wall with an initial velocity of v0=19m/s and an angle = 71 with the horizontal, as illustrated in t
HACTEHA [7]

Answer:

(a) 2.85 m

(b) 16.5 m

(c) 21.7 m

(d) 22.7 m

Explanation:

Given:

v₀ₓ = 19 cos 71° m/s

v₀ᵧ = 19 sin 71° m/s

aₓ = 0 m/s²

aᵧ = -9.8 m/s²

(a) Find Δy when t = 3.5 s.

Δy = v₀ᵧ t + ½ aᵧ t²

Δy = (19 sin 71° m/s) (3.5 s) + ½ (-9.8 m/s²) (3.5 s)²

Δy = 2.85 m

(b) Find Δy when vᵧ = 0 m/s.

vᵧ² = v₀ᵧ² + 2 aᵧ Δy

(0 m/s)² = (19 sin 71° m/s)² + 2 (-9.8 m/s²) Δy

Δy = 16.5 m

(c) Find Δx when t = 3.5 s.

Δx = v₀ₓ t + ½ aₓ t²

Δx = (19 cos 71° m/s) (3.5 s) + ½ (0 m/s²) (3.5 s)²

Δx = 21.7 m

(d) Find Δx when Δy = 0 m.

First, find t when Δy = 0 m.

Δy = v₀ᵧ t + ½ aᵧ t²

(0 m) = (19 sin 71° m/s) t + ½ (-9.8 m/s²) t²

0 = t (18.0 − 4.9 t)

t = 3.67

Next, find Δx when t = 3.67 s.

Δx = v₀ₓ t + ½ aₓ t²

Δx = (19 cos 71° m/s) (3.67 s) + ½ (0 m/s²) (3.67 s)²

Δx = 22.7 m

7 0
4 years ago
A Martian rover found an interesting rock that could contain signs of what Mars was like long ago. It grabbed
kodGreya [7K]

Answer:

It would be PE=16kg * 9.8 m/s^2 * 1m = 160 J

Explanation:

The person who asked this question ended up answering his own question so I'm here to let you know all that the answer was founded by the person whos posted the question himself full credit goes to him :)

3 0
3 years ago
A simple circuit consists of a light bulb connected to the terminals of a battery. A voltmeter shows a potential difference of 1
larisa [96]
<h2>Answer:</h2>

38.14Ω

<h2>Explanation:</h2>

Let's solve this question using Ohm's law which states that the current (I) flowing through a conductor is directly proportional to the potential difference or voltage (V) across it. Mathematically;

V =  I R       -------------------(i)

<em>Where</em>;

R is the constant of proportionality called resistance of the conductor and is measured in Ohms (Ω)

<em>From the question;</em>

V = 18.5V

I = 0.485A

<em>Substitute these  values into equation (i) as follows;</em>

18.5 = 0.485 x R

<em>Solve for R;</em>

R = 18.5 / 0.485

R = 38.14Ω

Therefore the resistance of the bulb is 38.14Ω

6 0
3 years ago
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