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2 years ago

Forces present on a flying dove

Physics

2 answers:

storchak [24]2 years ago

7 0

Answer:

There are four forces acting on a bird in flight, lift, thrust, drag and gravity (weight). These four forces act in pairs, as shown on the right. If a bird is to fly it must overcome drag and weight by generating a greater force of thrust and lift.

sasho [114]2 years ago

3 0

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Several large firecrackers are inserted into the holes of a bowling ball, and the 6.3 kg ball is then launched into the air with

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Answer

given,

mass of the ball = 6.3 kg

speed of the ball = 10.4 m/s

angle made with horizontal = 43°

m_a = 1.8 kg v_a = 2.2 m/s

m_b = 1.6 kg v_b = 1.8 m/s

mass of third particle = 6.3 - 1.8 - 1.6

= 2.9 kg

u cos θ = 10.4 x cos 43° = 7.61 m/s

by using conservation momentum along x-axis

6.3 x 7.61 = 1.8 × (-2.2) + 0 + 1.6 × V₃ₓ

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by using conservation momentum along y-axis

0 = 0 + 1.6 x 1.8 + 1.6 × V₃y

V₃y = -1.8 m/s (indicate downward)

velocity of the third particle

$v = \sqrt{32.44^2 + (-1.8)^2}$

v = 32.49 m/s

$tan \theta = \dfrac{-1.8}{32.44}$

$\theta = tan^{-1}(\dfrac{-1.8}{32.44})$

θ = 3.176° (downward with horizontal)

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2 years ago

The part of the cerebrum that controls voluntary movements is located in the _______ lobe. A. frontal B. parietal C. temporal D.

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3 years ago

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Answer:

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Answer:

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Explanation:

Given,

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=0.75 kg m/s

Momentum of 2nd ball=mass of the ball*velocity

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Since the first ball undergoes head on collision with the second ball,

momentum of first ball=momentum of second ball

0.75 kg m/s=0.6 kg*velocity of 2nd ball

Velocity of 2nd ball=0.75 kg m/s ÷ 0.6 kg

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2 years ago

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Sliva [168]

Answer:

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