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lesya692 [45]
2 years ago
10

Forces present on a flying dove

Physics
2 answers:
storchak [24]2 years ago
7 0

Answer:

There are four forces acting on a bird in flight, lift, thrust, drag and gravity (weight). These four forces act in pairs, as shown on the right. If a bird is to fly it must overcome drag and weight by generating a greater force of thrust and lift.

sasho [114]2 years ago
3 0

Refer to attachment for your answer

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What is the escape speed of an electron launched from the surface of a 1.1-cm-diameter glass sphere that has been charged to 8.0
zimovet [89]
At surface,
v = kq/r

And potential energy of an electron is given by,
PE = -ev = -ekq/r

At escape velocity,
PE + KE = 0.
Therefore,
1/2mv^2 - ekq/r =0
1/2mv^2 = ekq/r
v = Sqrt [2ekq/mr], where v = escape velocity, e = 1.6*10^-19 C, k = 8.99*10^9 Nm^2/C^2, m = 9.11*10^-31 kg, r = 1.1*10^-2 m, q = 8*10^-9 C

Substituting;
v = Sqrt [(2*1.6*19^-19*8.99*10^9*8*10^-9)/(9.11*10^-31*1.1*10^-2)] = 47949357.23 m/s ≈ 4.795 *10^7 m/s
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24 How long does it take for the Earth to orbit the Sun?
Zarrin [17]

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365 days

So The Final Answer is a Year

D is the answer

Explanation:

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2 years ago
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Every force has a specific and identifiable cause called a(n)...............
goblinko [34]
1 Bc I just did it and got it right
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2 years ago
In designing buildings to be erected in an area prone to earthquakes, what are the things that you need to consider?
il63 [147K]

Answer:

In an earthquake prone area, the things that are needed to be considered for the buildings to stand constant and no cause of damages are as follows-

  • The foundation of the building must be made strong, using large amount of concretes so that it can hold the entire load of the building.
  • The pillars of the buildings are also should be firmed, rigid, strong and thick.
  • The buildings are needed to be construct in such a way that during any seismic event, the forces can be redistributed easily through the body of the building without causing any damage.
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6 0
3 years ago
An inclined plane of effective length 4.5m is used to raise a load of 500N through a height of 1.5m .If the list is raise by for
IrinaK [193]

Answer:

1850 N

Explanation:

The formula for friction force between the load and plane is given as ;

F= μ*N

N = mg cos θ

To find θ, which is the angle the inclined plane makes with the ground at the height of 1.5 m

Sin θ = 1.5/4.5

Sin θ = 0.3333

Sin⁻{0.3333} = 19.50°

θ = 19.50°

Finding N , where m= 500 N , and g= 9.81

N = mg cos θ

N= 500 * 9.81 * cos 19.50°

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Coefficient of kinetic friction is calculated as;

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μ = 200/500 = 0.4

The magnitude of kinetic friction is given as;

Fk= μ * N

Fk = 0.4 * 4624

Fk= 1850 N

8 0
2 years ago
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