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lesya692 [45]
3 years ago
10

Forces present on a flying dove

Physics
2 answers:
storchak [24]3 years ago
7 0

Answer:

There are four forces acting on a bird in flight, lift, thrust, drag and gravity (weight). These four forces act in pairs, as shown on the right. If a bird is to fly it must overcome drag and weight by generating a greater force of thrust and lift.

sasho [114]3 years ago
3 0

Refer to attachment for your answer

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mezya [45]

Answer:

uh what are you saying

6 0
3 years ago
X<br> x<br> 2.5 N<br> 1.7 N<br> 2.5 N
Olin [163]

Answer:

2.5*1.7/2.5

Explanation:

6 0
3 years ago
Select the correct answer.
Effectus [21]
A. logic, would be your answer i believe!
4 0
2 years ago
A box slides down a frictionless incline, gaining speed. The work done by the normal force n is _______.
jeka57 [31]

The work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.

<h3>What is normal force?</h3>

The force of contact is called the normal force. When the two surfaces are in contact with each other, then the normal force acts.

This force is applied by the solid bodies on each other in order to prevent the passing through each other.

A box slides down a frictionless incline, gaining speed. For this box, the value of work done by normal force has to be found out. Let's analyze the given condition.

  • The body is gaining the speed, which means there is a change in kinetic energy.
  • The change in kinetic energy is equal to the work done.
  • The friction force is the product of coefficient of the friction and normal force.
  • The friction force for the given case is zero. Thus, the normal force must be equal to the zero.

Thus, the work done by the normal force n when the box slides down a frictionless incline and gaining speed is zero.

Learn more about the normal force here;

brainly.com/question/10941832

7 0
2 years ago
Read 2 more answers
Friends Burt and Ernie stand at opposite ends of a uniform log that is floating in a lake. The log is 3.0 m long and has mass 20
Taya2010 [7]

Answer:

The distance the log has moved by the time Ernie reaches Bur is 1.33 m.

Explanation:

give information:

The log is 3.0 m long and has mass 20.0 kg.

Burt has mass 30.0 kg; Ernie has mass 40.0 kg

Ernie has mass 40.0 kg.

to find the distance, first, we have to calculate the center of mass

X = ∑ m x /∑m

   = (20 x (3/2)) + (30 x 0) + (40 x 3)/ (20+30+40)

   = 150/90

   = 5/3

when Ernie walk, the center of the mass is

X = (70 x 0) + (20 x (3/2))/(70 + 20)

  = 30/90

  = 1/3

the distance of log moved = 5/3 - 4/3 = 1.33 m

5 0
3 years ago
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