Answer:
hello your question incomplete attached below is the complete question and detailed solution
Answer : Csf = 0.0131
Explanation:
Attached below is the detailed solution
Given data :
ΔTe = 17.1⁰c calculated as ;Ts - Tsat = ( 117.1 - 100 )
Pe = 957.9 kg/m^3
Cp1e = 4217 j/kgk
<em>U</em>e = 279 * 10^-6 n. s / m^2
Pre = 1.76
hfg = 2.257 * 10^6 J/kg
Pv = 0.5955 kg/m^3
б = 0.0589 N/m
q" = 664 * 10^3 w/m^2 ( calculated )
Input these values into equation 1 as contained in the detailed solution
Csf = 0.0131
Here is the flow sheet. Hope this helps have a great day!!
Answer:
1 The weight of the foundation block should be enough to withstand vibrations
2 The foundation must be so dimensional that the resulting pressure due to weight of the device as well as the weight of foundation moves through the center of gravity of a base impact area in order to avoid the risk of specific settlement.
3.The base should be sufficiently rigid to have the requisite rigidity
4 a distance should be created all across machine foundation to separate it from the adjacent parts of the building
Explanation:
1. The weight of the foundation block should be enough to withstand vibrations and to avoid friction between device and the surrounding soil as well. This can be done by increasing the base block weight in supporting with engine power
2.The foundation must be so dimensional that the resulting pressure due to weight of the device as well as the weight of foundation moves through the center of gravity of a base impact area in order to avoid the risk of specific settlement.
3.The base should be sufficiently rigid to have the requisite rigidity as the slightest misdirection of foundation may cause significant bearing disorders.
4.To avoid propagation of vibration from a device to the adjacent parts of the building, a distance should be created all across machine foundation to separate it from the adjacent parts of the building.
