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2 years ago

The area of the triangle

Mathematics

1 answer:

Sonja [21]2 years ago

4 0

Answer:

100.763 (cm.²)

Step-by-step explanation:

1. the formula of the required area is:

$A=\frac{1}{2} *side_1*side_2*sin45;$

2. according to the formula above:

A=0.5*15*19/√2≈100.763

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The number of girls at middle school cyber summer camp was six more than twice the number of boys. There were a total of 156 mid

nordsb [41]

Ok so if you did 156-6 (considering it was 6 more you want to subtract it) and then because the girls was doubled the boys (you are now at 150) you must divide that by 3 which will give you 50. But you need to double it (for girls) which is 100 and then you have 50 left over which is for the boys. Boys=50 girls=106

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2 years ago

se an inequality symbol (<, >, =, ≠) to compare 5 + (−4) _____ 14 + (−13) A. > B. = C. ≠ D.

qwelly [4]

5+(-4)= 1
14+(-13)= 1
So the answer is B. =
I hope this helps

3 0

2 years ago

Read 2 more answers

A recent article in a university newspaper claimed that the proportion of students who commute more than miles to school is no m

Naddika [18.5K]

Answer:

The null hypothesis is $H_0: p \leq x$ , in which x is the proportion tested.

The alternative hypothesis is $H_1: p > x$

Step-by-step explanation:

A recent article in a university newspaper claimed that the proportion of students who commute more than miles to school is no more than x.

This means that at the null hypothesis, we test if the proportion is of at most x, that is:

$H_0: p \leq x$

Suppose that we suspect otherwise and carry out a hypothesis test.

The opposite of at most x is more than x, so the alternative hypothesis is:

$H_1: p > x$

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2 years ago

to attend the football game it cost $8 for parking plus $59 per ticket if bryan paid $362 how many tickets did he purchase

PilotLPTM [1.2K]

Answer:

He bought 5.4 tickets or just 5 tickets

Step-by-step explanation:

You would add the parking fee and the football game for the total of $67. Then do 362 divided by 67

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2 years ago

What is the average (arithmetic mean) of the first 90 measurements in a certain list of 92 measurements? (1) the average of the

marishachu [46]

The sum of all the measurements is just the average times the number.

$\bar x = \frac{1}{n} \sum_{i=1}^n x_i$

$\sum_{i=1}^n x_i = n \bar x$

So if the average of all 92 is 7 the sum of those is $92 \times 7$

The average of the last two is 7.2 so their sum is $2 \times 7.2$

That means the sum of the first 90 is $92 \times 7 - 2 \times 7.2$

so the average of the first 90 is

$\dfrac{92 \times 7 - 2 \times 7.2}{90} = 6.99556$ cm

7 0

2 years ago