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Ghella [55]
3 years ago
7

Find the mass of 5.60 L O2 at 1.75 atm and 250.0 K

Chemistry
2 answers:
bixtya [17]3 years ago
8 0

Answer:

Moles O2 = pV/RT = 2.75 x 5.60 / 0.08206 x 250=0.751

mass = 32 g/mol x 0.751 mol= 24.0 g

Explanation:

Hope it help

Mark me as brainliest

Sedaia [141]3 years ago
7 0

Answer:

Explanation:

PV = nRT and you should know that moles (n) is equal to grams/molecular weight

So now the equation is PV = gRT/MW

(1.75atm)*(5.6L) = g*(0.082)*(250K)/(2*16amu)

313.6 = g*(0.082)*(250K)

g = 15.3 grams

I haven't done chemistry for a few months, so I could be rusty or used wrong values

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